Problem 23
Question
In \(3-26,\) prove that each equation is an identity. $$ \sin \theta+\frac{\cos ^{2} \theta}{1+\sin \theta}=1 $$
Step-by-Step Solution
Verified Answer
The identity is proven as \(\sin \theta + \frac{\cos^2 \theta}{1 + \sin \theta} = 1\).
1Step 1: Analyze the Objective
We need to prove that the given equation is an identity, meaning it holds true for all values of \(\theta\) where it is defined.
2Step 2: Simplify the Equation
Start by simplifying the left-hand side (LHS) of the equation: \(\sin \theta + \frac{\cos^2 \theta}{1 + \sin \theta}\). Our goal is to show it equals 1, which is the right-hand side (RHS).
3Step 3: Substitute Trigonometric Identity
Recall the Pythagorean identity: \(\cos^2 \theta = 1 - \sin^2 \theta\). Substitute \(\cos^2 \theta\) in the LHS with \(1 - \sin^2 \theta\) to get: \[\sin \theta + \frac{1 - \sin^2 \theta}{1 + \sin \theta}\].
4Step 4: Simplify the Fraction
Simplify the fraction: \[\frac{1 - \sin^2 \theta}{1 + \sin \theta} = \frac{(1 - \sin \theta)(1 + \sin \theta)}{1 + \sin \theta} = 1 - \sin \theta\]. The last step assumes \(1 + \sin \theta eq 0\).
5Step 5: Combine the Terms
Combine terms in the LHS: \[\sin \theta + (1 - \sin \theta) = 1\]. This shows LHS equals the RHS, thus verifying the identity.
Key Concepts
Pythagorean IdentityFraction SimplificationTrigonometric Equations
Pythagorean Identity
The Pythagorean identity is a fundamental concept in trigonometry, connecting the squares of sine and cosine functions. It is written as:
In the given problem, we utilize the Pythagorean identity to replace \(\cos^2 \theta\) with \(1 - \sin^2 \theta\). This substitution is crucial because it allows us to work with expressions in terms of sine only, making the algebraic manipulation more straightforward.
The beauty of the Pythagorean identity lies in its ability to work for any angle \(\theta\). It is applicable everywhere the trigonometric functions are defined, aiding in various trigonometric proofs and simplifications.
- \(\sin^2 \theta + \cos^2 \theta = 1\)
In the given problem, we utilize the Pythagorean identity to replace \(\cos^2 \theta\) with \(1 - \sin^2 \theta\). This substitution is crucial because it allows us to work with expressions in terms of sine only, making the algebraic manipulation more straightforward.
The beauty of the Pythagorean identity lies in its ability to work for any angle \(\theta\). It is applicable everywhere the trigonometric functions are defined, aiding in various trigonometric proofs and simplifications.
Fraction Simplification
Fraction simplification is a technique used to make equations easier to handle and solve. When faced with a complex fraction, the goal is to reduce it to a simpler form by canceling common factors in the numerator and the denominator.
This results in the fraction simplifying to \(1 - \sin \theta\), significantly reducing the complexity of the original expression.
- In our exercise, we need to simplify \(\frac{1 - \sin^2 \theta}{1 + \sin \theta}\).
This results in the fraction simplifying to \(1 - \sin \theta\), significantly reducing the complexity of the original expression.
Trigonometric Equations
Trigonometric equations, like the one in this exercise, often require proving that two expressions are equivalent under certain conditions. Solving these equations often involves the application of trigonometric identities and simplifications.
To establish the equation as an identity, we start by simplifying the left-hand side (LHS)
Trigonometric equations often require comfort with algebraic manipulation and an understanding of where identities apply. Recognizing patterns and strategically applying identities are keys to mastering these types of problems.
To establish the equation as an identity, we start by simplifying the left-hand side (LHS)
- First, we incorporate the Pythagorean identity.
- Next, we simplify fractions to reduce the expression.
Trigonometric equations often require comfort with algebraic manipulation and an understanding of where identities apply. Recognizing patterns and strategically applying identities are keys to mastering these types of problems.
Other exercises in this chapter
Problem 23
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