Problem 23
Question
In \(15-26,\) write each logarithmic equation in exponential form. $$ -2=\log _{5} 0.04 $$
Step-by-Step Solution
Verified Answer
The exponential form is \(5^{-2} = 0.04\).
1Step 1: Understand the Logarithmic Form
The logarithmic equation given is \(-2 = \log_{5} 0.04\). This means that \(5\) raised to the power of \(-2\) gives \(0.04\). In general, \(\log_b a = c\) can be rewritten as \(b^c = a\).
2Step 2: Convert to Exponential Form
To convert \(-2 = \log_{5} 0.04\) to its exponential form, use the relationship that \(b^c = a\). Here, \(b = 5\), \(c = -2\), and \(a = 0.04\). So the exponential form is \(5^{-2} = 0.04\).
Key Concepts
Logarithmic EquationLogarithmic to Exponential ConversionExponentiation
Logarithmic Equation
A logarithmic equation involves an expression with a logarithm, and it typically relates three components: a base, a result, and an exponent. The general form is represented as \(\log_b a = c\). In this format, \(b\) represents the base of the logarithm, \(a\) is the value you're taking the logarithm of, and \(c\) is the result or exponent. For example, in the equation \(-2 = \log_{5} 0.04\), \(5\) is the base, \(0.04\) is the result of the base raised to some power, and \(-2\) is the power itself.
- \(b\) is always a positive real number and not equal to 1.
- \(a\) is a positive number because you can’t take the logarithm of zero or a negative number in real numbers.
- \(c\) can be any real number, positive or negative.
Logarithmic to Exponential Conversion
Converting a logarithmic equation to exponential form is a crucial skill in mastering logarithms. This conversion is straightforward once you understand the relationship between the two. You start with a logarithmic equation: \(\log_b a = c\). To convert this into an exponential form, you rewrite it as \(b^c = a\).
For example, the given logarithmic equation is \(-2 = \log_{5} 0.04\). To convert, you recognize:
This conversion process is helpful because it often simplifies solving exponential growth or decay problems.
For example, the given logarithmic equation is \(-2 = \log_{5} 0.04\). To convert, you recognize:
- \(b = 5\)
- \(c = -2\)
- \(a = 0.04\)
This conversion process is helpful because it often simplifies solving exponential growth or decay problems.
Exponentiation
Exponentiation is a fundamental mathematical operation involving numbers. It refers to multiplying a number by itself a certain number of times, as indicated by an exponent. When we write \(b^c\), \(b\) is called the base and \(c\) is the exponent. When the exponent is negative, as in \(5^{-2}\), this indicates reciprocal or division.
Using this concept, you calculate \(5^{-2}\) as follows:
Using this concept, you calculate \(5^{-2}\) as follows:
- The negative exponent indicates that we take the reciprocal of the base raised to the positive exponent.
- \(5^2 = 25\), hence \(5^{-2} = \frac{1}{25}\).
- Therefore, \(5^{-2} = 0.04\) holds true, as the division yields \(0.04\).
Other exercises in this chapter
Problem 23
In \(21-32,\) for each given logarithm, find \(x,\) the antilogarithm. Write the answer to four decimal places. $$ \ln x=1.3826 $$
View solution Problem 23
In \(15-23,\) evaluate each logarithm to the nearest hundredth. $$ \log \frac{1}{2} \cdot \log 100 \cdot \log 300 $$
View solution Problem 23
a. Expand each expression as a difference, sum, and/or multiple of logarithms. b. Find the value of each expression. \(\log _{4} \sqrt{16^{2}}\)
View solution Problem 24
In \(21-32,\) for each given logarithm, find \(x,\) the antilogarithm. Write the answer to four decimal places. $$ \ln x=1.7790 $$
View solution