Problem 23
Question
If \(\mathrm{T}\) is the intensity of absorbed light and ' \(\mathrm{C}\) is the concentration of \(\mathrm{AB}\) for the photochemical process \(\mathrm{AB}+\mathrm{hv} \longrightarrow \mathrm{AB} \bullet\), the rate of formation of \(\mathrm{AB}^{\prime}\) is directly proportional to (a) \(\vec{C}\) (b) I (c) \(\mathrm{I}^{2}\) (d) C.I
Step-by-Step Solution
Verified Answer
The rate is directly proportional to \(\mathrm{C} \cdot \mathrm{I}\).
1Step 1: Define Proportionality
The problem states that the rate of formation of \(\mathrm{AB}'\) is directly proportional to certain factors. This implies that as these factors increase, the rate of formation of \(\mathrm{AB}'\) will also increase. To solve the problem, we need to establish what \(\mathrm{AB}'\) is dependent on based on the given photochemical process \(\mathrm{AB} + \mathrm{hv} \longrightarrow \mathrm{AB} \bullet\).
2Step 2: Understand Reaction Mechanics
In photochemical reactions like \(\mathrm{AB} + \mathrm{hv} \longrightarrow \mathrm{AB} \bullet\), the light intensity \(\mathrm{I}\) plays a significant role as it's the source of energy driving the reaction forward. Typically, reactions directly proportional to light intensity will have their rate depend linearly on \(\mathrm{I}\).
3Step 3: Examine Concentration Effects
The concentration \(\mathrm{C}\) of the reactant \(\mathrm{AB}\) can affect the rate of the photochemical reaction. If more \(\mathrm{AB}\) molecules are present, more reactants can absorb light \(\mathrm{hv}\) and transition into \(\mathrm{AB} \bullet\). Thus, reaction rates are often directly proportional to concentration \(\mathrm{C}\).
4Step 4: Combine Factors
Both the light intensity \(\mathrm{I}\) and the concentration \(\mathrm{C}\) influence the chemical reaction. The rate of formation of \(\mathrm{AB}'\) is therefore likely to be directly proportional to the product of these two factors: \(\mathrm{C} * \mathrm{I}\), taking into account the necessity for reactants and sufficient energy input.
Key Concepts
Rate of ReactionLight IntensityConcentration
Rate of Reaction
The rate of reaction is a critical concept in understanding photochemical processes. It refers to how quickly a reaction progresses from reactants to products. In the equation presented, \[ \mathrm{AB} + \mathrm{hv} \longrightarrow \mathrm{AB} \bullet, \]the rate of formation of the product \( \mathrm{AB}' \) is central to this reaction.
- In photochemical reactions, the rate is significantly influenced by external factors like light intensity and concentration.
- The rate can be measured by the change in concentration of reactants or products over time.
- In this specific process, the higher the rate, the more products form in a shorter period.
Light Intensity
Light intensity refers to the amount of light energy hitting a certain area. In photochemical reactions, such as the one given \(\mathrm{AB} + \mathrm{hv} \rightarrow \mathrm{AB} \bullet, \)this parameter is key because it provides the energy required to initiate and sustain the reaction.
- The reaction rate is often proportional to light intensity because more energy results in more reactants transitioning to products.
- As intensity increases, more photons are available to interact with molecules, driving the chemical change.
- In some reactions, too much light can lead to side effects, like degradation of products, so balance is crucial.
Concentration
Concentration, in the context of chemistry, refers to how much of a substance is present in a mixture or solution. In the discussed photochemical reaction \(\mathrm{AB} + \mathrm{hv} \longrightarrow \mathrm{AB} \bullet, \)the concentration \( \mathrm{C} \) of reactant \( \mathrm{AB} \) affects reaction rate significantly.
- A higher concentration of \( \mathrm{AB} \) means more molecules are available to absorb light and form \( \mathrm{AB} \bullet \).
- This increase in reactant molecules can lead to a faster reaction.
- Since the rate of the reaction depends on this initial concentration, it is directly proportional to the product formation.
Other exercises in this chapter
Problem 19
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