Problem 23
Question
For the following exercises, find the determinant. \(\left|\begin{array}{rrr}2 & -1.6 & 3.1 \\ 1.1 & 3 & -8 \\ -9.3 & 0 & 2\end{array}\right|\)
Step-by-Step Solution
Verified Answer
The determinant is -17.03.
1Step 1: Identify matrix elements
The given matrix is a 3x3 matrix:\[ A = \begin{bmatrix} 2 & -1.6 & 3.1 \ 1.1 & 3 & -8 \ -9.3 & 0 & 2 \end{bmatrix} \] Identify elements: \[ a_{11} = 2, \, a_{12} = -1.6, \, a_{13} = 3.1, \ a_{21} = 1.1, \, a_{22} = 3, \, a_{23} = -8, \ a_{31} = -9.3, \, a_{32} = 0, \, a_{33} = 2 \]
2Step 2: Apply the 3x3 determinant formula
The determinant of a 3x3 matrix \( A \) is given by:\[ \text{det}(A) = a_{11}(a_{22}a_{33} - a_{23}a_{32}) - a_{12}(a_{21}a_{33} - a_{23}a_{31}) + a_{13}(a_{21}a_{32} - a_{22}a_{31}) \] Substituting the elements from the matrix into the formula gives:
3Step 3: Calculate each cofactor
Compute the cofactors individually:- \( a_{11}(a_{22}a_{33} - a_{23}a_{32}) = 2(3 \times 2 - (-8) \times 0) = 2(6) = 12 \)- \( a_{12}(a_{21}a_{33} - a_{23}a_{31}) = -1.6(1.1 \times 2 - (-8) \times (-9.3)) = -1.6(2.2 - 74.4) = -1.6(-72.2) = 115.52 \)- \( a_{13}(a_{21}a_{32} - a_{22}a_{31}) = 3.1(1.1 \times 0 - 3 \times (-9.3)) = 3.1(0 + 27.9) = 86.49 \)
4Step 4: Sum the results to find the determinant
Combine the calculated cofactors:\[ \text{det}(A) = 12 - 115.52 + 86.49 = -17.03 \] The determinant of the matrix is \(-17.03\).
Key Concepts
3x3 matrixCofactor expansionMatrix operations
3x3 matrix
A 3x3 matrix is a special type of square matrix that contains three rows and three columns. This means it has exactly 9 elements in total. Each element in the matrix is usually represented by a specific notation such as \(a_{ij}\), where \(i\) indicates the row number and \(j\) indicates the column number.
For example, the matrix in our exercise is:
For example, the matrix in our exercise is:
- Row 1: \(a_{11}=2, \, a_{12}=-1.6, \, a_{13}=3.1\)
- Row 2: \(a_{21}=1.1, \, a_{22}=3, \, a_{23}=-8\)
- Row 3: \(a_{31}=-9.3, \, a_{32}=0, \, a_{33}=2\)
Cofactor expansion
Cofactor expansion, also known as Laplace expansion, is a method used to calculate the determinant of a matrix. For a 3x3 matrix, this involves selecting a particular row or column and calculating the determinant based on the elements and their cofactors.
In our exercise, we expand along the first row. The determinant of the matrix \( A \) is calculated as follows:
In our exercise, we expand along the first row. The determinant of the matrix \( A \) is calculated as follows:
- Select row or column: The first row is chosen: \(a_{11}, \, a_{12}, \, a_{13}\).
- Compute cofactors:
- \(C_{11} = a_{11}(a_{22}a_{33} - a_{23}a_{32})\).
- \(C_{12} = -a_{12}(a_{21}a_{33} - a_{23}a_{31})\).
- \(C_{13} = a_{13}(a_{21}a_{32} - a_{22}a_{31})\).
Matrix operations
Matrix operations are operations that can be performed on matrices, such as addition, subtraction, multiplication, and computing determinants. In this exercise, we are primarily focused on the determinant operation. The determinant is a scalar value that can be computed from the elements of a square matrix.
Computing a determinant for a 3x3 matrix involves the following:
Computing a determinant for a 3x3 matrix involves the following:
- Identify all elements: Record down each value in the matrix.
- Apply the determinant formula: Use the specific formula for 3x3 matrices to break down the determinant using cofactors.
- Perform arithmetic operations: Carry out step-by-step computations to reach the final value.
Other exercises in this chapter
Problem 22
For the following exercises, use any method to solve the system of nonlinear equations. $$x^{4}-x^{2}=y$$ $$x^{2}+y=0$$
View solution Problem 22
For the following exercises, solve each system by Gaussian elimination. $$ \begin{aligned} 10 x+2 y-14 z &=8 \\\\-x-2 y-4 z &=-1 \\\\-12 x-6 y+6 z &=-12 \end{al
View solution Problem 23
For the following exercises, solve the system by Gaussian elimination. $$ \begin{aligned} 2 x+3 y &=12 \\ 4 x+y &=14 \end{aligned} $$
View solution Problem 23
Solve the system by Gaussian elimination. \(2 x+3 y=12\) \(4 x+y=14\)
View solution