Problem 23
Question
For the following exercises, factor the polynomial. $$ 16 x^{2}-100 $$
Step-by-Step Solution
Verified Answer
The factored form is \( (4x - 10)(4x + 10) \).
1Step 1: Identify as a Difference of Squares
The polynomial is in the form \( a^2 - b^2 \), which is a difference of squares. Here, \( a = 4x \) and \( b = 10 \), since \( (4x)^2 = 16x^2 \) and \( 10^2 = 100 \).
2Step 2: Apply the Difference of Squares Formula
The formula for the difference of squares is \( a^2 - b^2 = (a - b)(a + b) \). Apply this formula using \( a = 4x \) and \( b = 10 \) to factor the polynomial.
3Step 3: Substitute and Simplify
Substitute \( a = 4x \) and \( b = 10 \) into the formula: \( (4x - 10)(4x + 10) \). Thus, the polynomial \( 16x^2 - 100 \) is factored as \( (4x - 10)(4x + 10) \).
Key Concepts
Difference of SquaresFactoring PolynomialsAlgebraic Expressions
Difference of Squares
The concept of "difference of squares" is a special algebraic pattern used in factoring certain polynomials. It is recognized by its specific form: \( a^2 - b^2 \). This expression represents a difference (subtraction) between two perfect squares. Identifying this pattern is crucial in simplifying and solving algebraic expressions.
When you spot a difference of squares, it can be easily factored using the identity:
When you spot a difference of squares, it can be easily factored using the identity:
- \( a^2 - b^2 = (a - b)(a + b) \)
Factoring Polynomials
Factoring polynomials involves rewriting a polynomial as a product of its simpler polynomial factors. This process is fundamental to solving polynomial equations, simplifying expressions, and is widely used in calculus and higher algebra.
The basic idea of factoring is to decompose a complex polynomial into parts that, when multiplied together, give the original polynomial. In the given exercise \( 16x^2 - 100 \), we identify it as a difference of squares, allowing us to apply the formula directly.
To factor polynomials effectively:
The basic idea of factoring is to decompose a complex polynomial into parts that, when multiplied together, give the original polynomial. In the given exercise \( 16x^2 - 100 \), we identify it as a difference of squares, allowing us to apply the formula directly.
To factor polynomials effectively:
- Identify common patterns like difference of squares, perfect square trinomials, or cube formulas.
- Look for common factors in all terms, using them to simplify first if possible.
- Apply appropriate factoring techniques or identities.
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and mathematical operations like addition, subtraction, multiplication, and division. They serve as the language of algebra, representing real-world problems and abstract mathematical ideas.
Understanding and manipulating algebraic expressions is key to solving equations and understanding algebra concepts. In the expression \( 16x^2 - 100 \), both terms are specific types of algebraic components:
Understanding and manipulating algebraic expressions is key to solving equations and understanding algebra concepts. In the expression \( 16x^2 - 100 \), both terms are specific types of algebraic components:
- \( 16x^2 \) is a term composed of a coefficient (16) and a variable raised to an exponent (\( x^2 \)).
- 100 is a constant term.
Other exercises in this chapter
Problem 22
For the following exercises, simplify the given expression. $$ (12 \div 3 \cdot 3)^{2} $$
View solution Problem 22
Simplify the given expression. $$ (12 \div 3 \cdot 3)^{2} $$
View solution Problem 23
For the following exercises, multiply the rational expressions and express the product in simplest form. $$ \frac{36 x^{2}-25}{6 x^{2}+65 x+50} \cdot \frac{3 x^
View solution Problem 23
For the following exercises, simplify each expression. $$ (\sqrt{42})(\sqrt{30}) $$
View solution