Problem 23
Question
Five associate professors are being considered for promotion to the rank of full professor, but only three will be promoted. How many different combinations of three could be promoted? 10
Step-by-Step Solution
Verified Answer
There are 10 ways to select 3 professors for promotion out of 5.
1Step 1: Understanding the Problem
We have 5 associate professors and we need to select 3 for promotion. Since this is a combination problem, we use the combination formula.
2Step 2: Recall the Combination Formula
The formula for combinations is given by \( C(n, r) = \frac{n!}{r!(n-r)!} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
3Step 3: Substitute Values into the Formula
Let's substitute \( n = 5 \) and \( r = 3 \) into the formula: \[ C(5, 3) = \frac{5!}{3!(5-3)!} \]
4Step 4: Calculate Factorials
First, calculate the factorials: \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \) \( 3! = 3 \times 2 \times 1 = 6 \) \( 2! = 2 \times 1 = 2 \)
5Step 5: Apply Factorials to the Formula
Now, apply the calculated factorials into the combination formula: \[ C(5, 3) = \frac{120}{6 \times 2} \]
6Step 6: Divide to Find the Result
Simplify and calculate: \[ \frac{120}{12} = 10 \] Thus, there are 10 different combinations of promotions possible.
Key Concepts
Combination FormulaFactorialsMathematical Problem Solving
Combination Formula
In mathematics, the combination formula is a key concept used in solving problems where the order of selection does not matter. When you have a set of items and need to select a specific number from that set, the combination formula comes into play. It is critical when tackling problems involving selections or groupings.
The combination formula is expressed as:
This is especially useful in cases like our exercise where we have 5 professors and need to choose 3 for promotion. By applying the combination formula, you quickly find the total number of possible groupings.
The combination formula is expressed as:
- \( C(n, r) = \frac{n!}{r!(n-r)!} \)
This is especially useful in cases like our exercise where we have 5 professors and need to choose 3 for promotion. By applying the combination formula, you quickly find the total number of possible groupings.
Factorials
Factorials are a mathematical concept crucial to understanding and applying the combination formula effectively. The factorial of a number \( n \), written as \( n! \), refers to the product of all positive integers up to \( n \).
For example, the factorial of 5, or \( 5! \), is calculated as:
To compute the number of combinations using the formula from our exercise, we need the factorials of 5, 3, and 2. Understanding how to calculate factorials allows you to break down complex selection problems into manageable steps, making the problem-solving process more systematic and accessible.
For example, the factorial of 5, or \( 5! \), is calculated as:
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
To compute the number of combinations using the formula from our exercise, we need the factorials of 5, 3, and 2. Understanding how to calculate factorials allows you to break down complex selection problems into manageable steps, making the problem-solving process more systematic and accessible.
Mathematical Problem Solving
Solving mathematical problems involves a clear understanding and application of concepts and formulas. In combinatorics, recognizing whether a problem involves permutations or combinations is key. With combination problems like the one in our exercise, where order doesn’t matter, simplifying using the combination formula is essential.
To solve these problems efficiently:
To solve these problems efficiently:
- Read and understand the problem context carefully.
- Identify what you are asked to find—in this case, the number of combinations of professors.
- Recall the appropriate formula.
- Substitute known values and calculate.
- Double-check your calculations to ensure accuracy.
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