Problem 23
Question
Find the period and graph the function. $$y=\cot \left(x+\frac{\pi}{4}\right)$$
Step-by-Step Solution
Verified Answer
The period is \( \pi \), with a phase shift of \( -\frac{\pi}{4} \) to the left.
1Step 1: Identify the Base Function
The given function is based on the cotangent function, which is \( y = \cot(x) \). The cotangent function has a period of \( \pi \).
2Step 2: Determine the Period
The period of \( y = \cot(x) \) is \( \pi \). The function \( y = \cot \left( x + \frac{\pi}{4} \right) \) includes a horizontal shift but does not affect the period. Therefore, the period remains \( \pi \).
3Step 3: Identify Transformation Effects
The argument \( x+\frac{\pi}{4} \) indicates a phase shift (horizontal shift) by \( -\frac{\pi}{4} \). This means the graph of the function is shifted \( \frac{\pi}{4} \) units to the left.
4Step 4: Sketch the Graph
To graph \( y = \cot(x+\frac{\pi}{4}) \), start with the graph of \( y = \cot x \), which has vertical asymptotes at \( x = n\pi \), where \( n \) is an integer. Shift each point and asymptote to the left by \( \frac{\pi}{4} \) to account for the horizontal shift. The asymptotes will occur at \( x = n\pi - \frac{\pi}{4} \). The period remains \( \pi \).
Key Concepts
Cotangent FunctionGraphing TransformationsPeriod of Functions
Cotangent Function
The cotangent function, denoted by \( \cot(x) \), is one of the six fundamental trigonometric functions. It is defined as the reciprocal of the tangent function, meaning \( \cot(x) = \frac{1}{\tan(x)} \). In terms of sine and cosine, it can also be expressed as:\[ \cot(x) = \frac{\cos(x)}{\sin(x)} \]This function is known for its characteristic wave form and periodic nature. Some key features of the cotangent function include:
- Vertical asymptotes at integer multiples of \( \pi \), i.e., at \( x = n\pi \), where \( n \) is an integer.
- It crosses the x-axis at points \( x = (2n+1)\frac{\pi}{2} \).
- It decreases moving from left to right.
Graphing Transformations
Graphing transformations, like shifts and stretches, help us modify the basic trigonometric function to fit specific cases. For the given function \( y = \cot(x + \frac{\pi}{4}) \), we apply a transformation to the standard \( y = \cot(x) \) graph.A common transformation for trigonometric graphs is the horizontal shift, also known as the phase shift. In our function, the term \( x + \frac{\pi}{4} \) indicates a phase shift to the left by \( \frac{\pi}{4} \) units. This means every point on the graph moves left:
- The vertical asymptotes, originally at \( x = n\pi \), will now be located at \( x = n\pi - \frac{\pi}{4} \).
- The zeros of the function will also shift left by \( \frac{\pi}{4} \).
Period of Functions
The period of a function is the distance over the x-axis it takes before the function begins to repeat. For trigonometric functions, this is a crucial attribute. The cotangent function, \( \cot(x) \), has a standard period of \( \pi \), meaning it repeats every \( \pi \) units.In the transformed function \( y = \cot(x + \frac{\pi}{4}) \), while there is a horizontal shift, it does not affect the function's period. The period remains \( \pi \). This means that every interval of \( \pi \) along the x-axis contains one complete wave of the cotangent function.Key points to remember about periods:
- Horizontal or phase shifts do not impact the period.
- The period of \( \cot(bx) \) is \( \frac{\pi}{|b|} \). In our scenario, \( b = 1 \), so the period is still \( \pi \).
Other exercises in this chapter
Problem 22
Find the amplitude and period of the function, and sketch its graph. $$y=5 \cos \frac{1}{4} x$$
View solution Problem 23
Find the exact value of the expression, if it is defined. $$\sin \left(\sin ^{-1} \frac{1}{4}\right)$$
View solution Problem 23
Find the exact value of the trigonometric function at the given real number. (a) \(\sin 13 \pi\) (b) \(\cos 14 \pi\) (c) \(\tan 15 \pi\)
View solution Problem 23
Find the terminal point \(P(x, y)\) on the unit circle determined by the given value of \(t .\) $$t=\frac{\pi}{2}$$
View solution