Problem 23
Question
Find the limit. $$ \lim _{x \rightarrow-\infty} \frac{1-2 x^{2}}{x^{3}+1} $$
Step-by-Step Solution
Verified Answer
The limit as x approaches negative infinity of the given function \(\frac{1-2 x^{2}}{x^{3}+1}\) is 0.
1Step 1: Identify the degrees of the polynomials in the numerator and denominator.
The given function is:
\[
\frac{1-2 x^{2}}{x^{3}+1}
\]
The degrees of the polynomials are:
- Degree of the numerator = 2
- Degree of the denominator = 3
2Step 2: Determine the behavior of the function as x approaches negative infinity based on the degrees.
As x approaches negative infinity, the term with the highest power in the numerator and denominator will dominate the behavior of the function. Since the degree of the denominator is higher than the degree of the numerator (3 > 2), the rational function will approach zero.
3Step 3: Calculate the limit.
As we concluded in step 2, the limit of the given function as x approaches negative infinity is 0:
\[
\lim _{x \rightarrow-\infty} \frac{1-2 x^{2}}{x^{3}+1} = 0
\]
Hence, the limit as x approaches negative infinity is 0.
Key Concepts
Rational FunctionsDegrees of PolynomialsBehavior of Functions at Infinity
Rational Functions
Rational functions are expressions that result from dividing two polynomials. They can come in handy for solving limits, as they offer insight into the behavior of functions. Understanding rational functions involves analyzing the numerator and the denominator separately. The function given here, \( \frac{1-2x^2}{x^3+1} \), is a clear example of a rational function since both the numerator and the denominator are polynomials.
- The numerator: \( 1-2x^2 \)
- The denominator: \( x^3+1 \)
Degrees of Polynomials
The degree of a polynomial is simply the highest power of its variable, which dictates how fast it grows as the variable increases. In the exercise, we examine:
- Numerator \( 1-2x^2 \): Degree is 2 (due to \( x^2 \))
- Denominator \( x^3+1 \): Degree is 3 (due to \( x^3 \))
Behavior of Functions at Infinity
Determining the limit of a function as \( x \) approaches infinity (or negative infinity) involves recognizing how the leading terms of polynomials influence the entire expression. In the given rational function \( \frac{1-2x^2}{x^3+1} \), the higher degree in the denominator (3) compared to the numerator (2) indicates that the denominator grows faster than the numerator as \( x \) moves towards negative infinity.
Here's what happens:
Here's what happens:
- As \( x \rightarrow -\infty \), \( x^3 \) becomes very large negatively compared to \( 2x^2 \).
- This fast-growing denominator leads the whole fraction towards zero because the larger denominator "overpowers" the numerator.
Other exercises in this chapter
Problem 23
Let \(f(x)=x^{3}-3 x-1\). Use the Intermediate Value Theorem to prove that \(f\) has a zero between \(x=1\) and \(x=2\), and then use Newton's method to find it
View solution Problem 23
evaluate the limit using l'Hôpital's Rule if appropriate. $$ \lim _{x \rightarrow 0^{+}} \frac{e^{x^{2}}+x-1}{1-\sqrt{1-x^{2}}} $$
View solution Problem 23
(a) find the intervals on which \(f\) is increasing or decreasing, and (b) find the relative maxima and relative minima of \(\vec{f}\). $$ f(x)=\frac{x^{2}}{x-1
View solution Problem 23
Determine where the graph of the function is concave upward and where it is concave downward. Also, find all inflection points of the function. $$ f(u)=\frac{u}
View solution