Problem 23
Question
Find the horizontal asymptote of the graph of each rational function. $$ y=\frac{5 x^{3}+2 x}{2 x^{5}-4 x^{3}} $$
Step-by-Step Solution
Verified Answer
The horizontal asymptote of the function \(y = \frac{5x^{3} + 2x}{2x^{5}-4x^{3}}\) is \(y=0\).
1Step 1: Identify the Degree of the Polynomials
An important aspect in determining the horizontal asymptote is recognizing the degree of the polynomials in the numerator and the denominator. The degree is the exponent of the highest degree term, that is the term with the largest exponent. In this case, the function is \( y = \frac{5x^{3} + 2x}{2x^{5}-4x^{3}} \). The degree of the numerator is 3 (from \(5x^{3}\)) and the degree of the denominator is 5 (from \(2x^{5}\)). Thus, the degree of the denominator is greater than the degree of the numerator.
2Step 2: Determine the Horizontal Asymptote
In rational functions, if the degree of the denominator is greater than the degree of the numerator, then the horizontal asymptote is at y=0. This is because as \(x\) tends to positive or negative infinity, the function tends to zero since the higher degree term in the denominator dominates the numerator.
Key Concepts
Horizontal Asymptote in Rational FunctionsUnderstanding Polynomial DegreeGraph Behavior of Rational Functions
Horizontal Asymptote in Rational Functions
A horizontal asymptote in a rational function gives us insight into how the graph behaves as the x-values move towards positive or negative infinity. It essentially represents a horizontal line that the function approaches but never quite reaches.
To determine the horizontal asymptote, focus on comparing the degrees of the polynomials in the numerator and denominator of the rational function. Depending on their degrees, the horizontal asymptote will be different:
To determine the horizontal asymptote, focus on comparing the degrees of the polynomials in the numerator and denominator of the rational function. Depending on their degrees, the horizontal asymptote will be different:
- If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is at the line \(y = 0\).
- If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is at \(y = \frac{a}{b}\), where \(a\) and \(b\) are the leading coefficients.
- If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote, but rather an oblique or slant asymptote.
Understanding Polynomial Degree
The degree of a polynomial is a key concept that influences the behavior of rational functions, especially when determining horizontal asymptotes. The degree of a polynomial is identified by the highest exponent of its variables. This is crucial for understanding the comparative growth rates of the polynomials in the function.
In the rational function \(y = \frac{5x^{3} + 2x}{2x^{5} - 4x^{3}}\), let's break it down:
In the rational function \(y = \frac{5x^{3} + 2x}{2x^{5} - 4x^{3}}\), let's break it down:
- The numerator, \(5x^{3} + 2x\), has a degree of 3 because the highest exponent is 3, from \(5x^{3}\).
- The denominator, \(2x^{5} - 4x^{3}\), has a degree of 5 because the highest exponent is 5, from \(2x^{5}\).
Graph Behavior of Rational Functions
Rational functions exhibit a variety of behaviors on their graphs, largely determined by the degrees of the polynomials in the numerator and denominator. Understanding the degree enables one to predict how the graph approaches its horizontal asymptote.
As \(x\) approaches very large positive or negative numbers, the terms with the highest degrees dominate the behavior of the function:
As \(x\) approaches very large positive or negative numbers, the terms with the highest degrees dominate the behavior of the function:
- For our rational function \(y = \frac{5x^{3} + 2x}{2x^{5} - 4x^{3}}\), since the denominator’s degree (5) is greater than the numerator’s degree (3), the graph approaches the horizontal asymptote \(y = 0\).
- The function's graph thus flattens and runs parallel to the x-axis, without crossing it, as it stretches towards infinity in either direction.
Other exercises in this chapter
Problem 23
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Describe the combined variation that is modeled by each formula. $$ \ell=\frac{V}{w h} $$
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Write an equation for the translation of \(y=\frac{2}{x}\) that has the given asymptotes. \(x=-2\) and \(y=3\)
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