Problem 23
Question
Find the derivative of the function using the definition of derivative. State the domain of the function and the domain of its derivative. \(f(x)=x^{3}-3 x+5\)
Step-by-Step Solution
Verified Answer
The derivative is \(f'(x) = 3x^2 - 3\), and the domain of both the function and its derivative is all real numbers, \(x \in \mathbb{R}\).
1Step 1: Understand the Function
We start with the given function \(f(x) = x^3 - 3x + 5\). This is a polynomial function of degree 3.
2Step 2: Apply the Definition of the Derivative
According to the definition of the derivative, \(f'(x)\) can be found using the limit: \[f'(x) = \lim_{{h \to 0}} \frac{{f(x+h) - f(x)}}{h}\]
3Step 3: Substitute the Function into the Derivative Formula
First, calculate \(f(x+h)\):\[f(x+h) = (x+h)^3 - 3(x+h) + 5\]Expanding \((x+h)^3\) gives:\[x^3 + 3x^2h + 3xh^2 + h^3\]Thus,\[f(x+h) = x^3 + 3x^2h + 3xh^2 + h^3 - 3x - 3h + 5\]
4Step 4: Calculate f(x+h) - f(x)
Subtract \(f(x)\) from \(f(x+h)\):\[f(x+h) - f(x) = (x^3 + 3x^2h + 3xh^2 + h^3 - 3x - 3h + 5) - (x^3 - 3x + 5)\]This simplifies to:\[3x^2h + 3xh^2 + h^3 - 3h\]
5Step 5: Divide by h and Simplify
Divide the expression by \(h\):\[\frac{{3x^2h + 3xh^2 + h^3 - 3h}}{h} = 3x^2 + 3xh + h^2 - 3\]Cancel \(h\) to simplify the expression.
6Step 6: Evaluate the Limit
Apply the limit as \(h\) approaches 0:\[f'(x) = \lim_{{h \to 0}}(3x^2 + 3xh + h^2 - 3) = 3x^2 - 3\]
7Step 7: Determine the Domain of f(x)
The domain of \(f(x) = x^3 - 3x + 5\) is all real numbers, \(x \in \mathbb{R}\), because polynomials are defined for all real numbers.
8Step 8: Determine the Domain of f'(x)
The derivative \(f'(x) = 3x^2 - 3\) is also a polynomial, so its domain is also all real numbers, \(x \in \mathbb{R}\).
Key Concepts
Polynomial FunctionLimit ProcessDomain of a FunctionDerivative Calculation
Polynomial Function
A polynomial function is a mathematical expression involving a sum of powers in one or more variables multiplied by coefficients. In simpler terms, it's an equation of the form
For example, in the function \(f(x) = x^3 - 3x + 5\), we have a third-degree polynomial. The leading term \(x^3\) indicates it is a cubic function, with the highest exponent being 3. This particular function includes both a cube term and a linear term, making it a combination of simple polynomial forms. Polynomial functions are very versatile and appear in numerous applications such as physics, economics, and engineering.
- The typical form is: \[ f(x) = a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0 \]
- where \(n\) is a non-negative integer and \(a_n, a_{n-1}, \ldots, a_0\) are constants.
- The highest power of \(x\) determines the degree of the polynomial.
For example, in the function \(f(x) = x^3 - 3x + 5\), we have a third-degree polynomial. The leading term \(x^3\) indicates it is a cubic function, with the highest exponent being 3. This particular function includes both a cube term and a linear term, making it a combination of simple polynomial forms. Polynomial functions are very versatile and appear in numerous applications such as physics, economics, and engineering.
Limit Process
The limit process is a fundamental concept in calculus used to find instantaneous rates of change or slopes of curves. It involves evaluating the behavior of a function as it approaches a particular point. In derivative calculations, limits help us define the exact "slope" of a curve at a specific point.
- For derivatives, the limit is used in the definition:\[ f'(x) = \lim_{{h \to 0}} \frac{{f(x+h) - f(x)}}{h} \]
- The \(h\) in the formula represents a very small change in \(x\).
- As \(h\) gets closer to 0, the fraction typically approaches a single value—this value is the derivative.
Domain of a Function
The domain of a function refers to all the possible input values (\(x\))- or arguments- that the function can accept without leading to any inconsistencies or undefined behaviors. In the context of polynomial functions, determining the domain is usually straightforward.
- In polynomial functions, like \(f(x) = x^3 - 3x + 5\), the domain is all real numbers.
- This means any real number can replace \(x\) without causing issues.
- Polynomials do not have restrictions commonly found in other functions like divisions by zero, or square roots of negative numbers.
Derivative Calculation
Derivative calculation is not only a critical concept but also a powerful tool in calculus used to determine how a function changes at any given point. The derivative of a function at a specific input value tells us the rate of change, or the slope of the tangent line to the function at that point. Calculations generally follow these steps:
- Begin with the definition of the derivative:\[ f'(x) = \lim_{{h \to 0}} \frac{{f(x+h) - f(x)}}{h} \]
- Substitute \(f(x+h)\) and \(f(x)\) into the formula.
- Simplify the expression, factor and cancel terms as necessary.
- Finally, evaluate the limit by setting \(h \to 0\).
Other exercises in this chapter
Problem 22
Evaluate the limit, if it exists. $$\lim _{n \rightarrow 0} \frac{\sqrt{1+h}-1}{h}$$
View solution Problem 22
15-36 Find the limit. $$ \lim _{x \rightarrow \infty} \frac{x+2}{\sqrt{9 x^{2}+1}} $$
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Use a table of values to estimate the value of the limit. If you have a graphing device, use it to confirm your result graphically. $$\lim _{x \rightarrow 1} \f
View solution Problem 23
(a) If $$F(x)=5 x /\left(1+x^{2}\right),$$ find \(F^{\prime}(2)$$ and use it to find an equation of the tangent line to the curve $$y=5 x /\left(1+x^{2}\right)$
View solution