Problem 23
Question
Find \(\mathbf{a}+(\mathbf{b}+\mathbf{c})\) for the given vectors. \(\mathbf{a}=\langle 5,1\rangle, \mathbf{b}=\langle-2,4\rangle, \mathbf{c}=\langle 3,10\rangle\)
Step-by-Step Solution
Verified Answer
\( \mathbf{a} + (\mathbf{b} + \mathbf{c}) = \langle 6, 15 \rangle \)
1Step 1: Identify the Vectors
First, take note of the given vectors: \( \mathbf{a} = \langle 5, 1 \rangle \), \( \mathbf{b} = \langle -2, 4 \rangle \), and \( \mathbf{c} = \langle 3, 10 \rangle \). We are tasked with finding \( \mathbf{a} + (\mathbf{b} + \mathbf{c}) \).
2Step 2: Calculate \(\mathbf{b} + \mathbf{c}\)
We start by calculating the vector sum \( \mathbf{b} + \mathbf{c} \). Add the corresponding components: \( \mathbf{b}_x + \mathbf{c}_x = -2 + 3 = 1 \) for the x-component, and \( \mathbf{b}_y + \mathbf{c}_y = 4 + 10 = 14 \) for the y-component. Thus, \( \mathbf{b} + \mathbf{c} = \langle 1, 14 \rangle \).
3Step 3: Calculate \(\mathbf{a} + (\mathbf{b} + \mathbf{c})\)
Now we add vector \( \mathbf{a} \) to the result from Step 2: \( \mathbf{a} + (\mathbf{b} + \mathbf{c}) \).Add the x-components: \( 5 + 1 = 6 \), and the y-components: \( 1 + 14 = 15 \).So, \( \mathbf{a} + (\mathbf{b} + \mathbf{c}) = \langle 6, 15 \rangle \).
Key Concepts
VectorsVector ComponentsVector Notation
Vectors
Vectors are fundamental in math and physics, representing quantities that have both a magnitude and a direction. Unlike scalars, which only have magnitude (like temperature or mass), vectors give us a much richer understanding of spatial information. A vector can describe anything from a force acting on an object to the velocity of a moving car.
- A vector is visualized as an arrow pointing in a specific direction.
- The length of the arrow represents the magnitude.
- A vector can be described in many contexts such as displacement, force, velocity, etc.
Vector Components
To make working with vectors easier, we break them down into components. Vector components are just projections of a vector along the axes of a coordinate system. For example, a 2D vector will have two components: one along the x-axis and another along the y-axis.
- The vector components allow us to perform calculations separately for each axis.
- They simplify vector addition, subtraction, and other operations.
- Adding vectors component-wise means adding the x-components together and the y-components together.
Vector Notation
Vector notation helps in clearly specifying vectors and distinguishing them from scalar values. Vectors are often represented in bold typeface (like \( \mathbf{a} \)) or with an arrow above the letter (like \( \vec{a} \)). Commonly, vectors use angle brackets to list their components, such as \( \langle x, y \rangle \) for two-dimensional vectors.
- Using consistent vector notation makes equations and vector operations clearer.
- The brackets contain the vector's components, representing how much the vector extends in each direction.
- Understanding this notation is crucial when reading or writing vector equations.
Other exercises in this chapter
Problem 23
The set of vectors \(\left\\{\mathbf{u}_{1}, \mathbf{u}_{2}, \mathbf{u}_{3}\right\\}\), where $$ \mathbf{u}_{1}=\langle 1,1,3\rangle, \mathbf{u}_{2}=\langle 1,4
View solution Problem 23
Find the distance from the point \((7,-3,-4)\) to \((\) a) the \(y z\) -plane and (b) the \(x\) -axis.
View solution Problem 24
The vectors \(p_{1}(x)=x+1, p_{2}(x)=x-1\) form a basis for the vector space \(P_{1}\) (a) Show that \(p_{1}(x)\) and \(p_{2}(x)\) are linearly independent. (b)
View solution Problem 24
Find symmetric equations for the line through \((4,-11,-7)\) that is parallel to the line \(x=2+5 t, y=-1+\frac{1}{3} t, z=9-2 t\).
View solution