Problem 23
Question
Exer. 21-24: Determine the domain and range of \(f^{-1}\) for the given function without actually finding \(f^{-1}\). Hint: First find the domain and range of \(f\). $$ f(x)=\frac{4 x+5}{3 x-8} $$
Step-by-Step Solution
Verified Answer
Domain of \(f^{-1}\): all real numbers except \(\frac{4}{3}\); Range of \(f^{-1}\): all real numbers except \(\frac{8}{3}\).
1Step 1: Understanding the problem
We need to determine the domain and range of the inverse function \(f^{-1}\) by first finding the domain and range of the given function \(f(x) = \frac{4x + 5}{3x - 8}\).
2Step 2: Determine the Domain of \(f\)
To find the domain of \(f(x)\), observe where the function is undefined. This happens when the denominator is zero. Solve \(3x - 8 = 0\), which gives \(x = \frac{8}{3}\). Therefore, the domain of \(f\) is all real numbers except \(x = \frac{8}{3}\).
3Step 3: Determine the Range of \(f\)
To find the range of \(f\), look for the values \(y\) that \(f(x)\) cannot take. Since \(f(x)\) is a rational function, it cannot equal its horizontal asymptote. The horizontal asymptote for \(\frac{4x + 5}{3x - 8}\) is found by evaluating the ratio of the leading coefficients, \(\frac{4}{3}\). Thus, the range of \(f\) is all real numbers except \(y = \frac{4}{3}\).
4Step 4: Determine the Domain of \(f^{-1}\)
The domain of an inverse function \(f^{-1}\) is the range of \(f\). From the range of \(f\), the domain of \(f^{-1}\) is all real numbers except \(\frac{4}{3}\).
5Step 5: Determine the Range of \(f^{-1}\)
The range of an inverse function \(f^{-1}\) is the domain of \(f\). From the domain of \(f\), the range of \(f^{-1}\) is all real numbers except \(\frac{8}{3}\).
Key Concepts
Domain of a FunctionRange of a FunctionRational Functions
Domain of a Function
The domain of a function is the set of all possible input values (typically represented as "x") for which the function is defined. To determine the domain of a rational function, such as \(f(x) = \frac{4x + 5}{3x - 8}\), we need to check where the function becomes undefined. This usually happens when the denominator equals zero, leading to division by zero, which is not allowed. To find where the function \(f(x)\) is undefined, set the denominator equal to zero:\[3x - 8 = 0\]Solving this equation, we find:\[x = \frac{8}{3}\]Hence, the domain consists of all real numbers except \(x = \frac{8}{3}\). This means you can plug any real number into the function except \(\frac{8}{3}\).
- The function is undefined at \(x = \frac{8}{3}\).
- The domain is all real numbers except this value: \(x eq \frac{8}{3}\).
Range of a Function
The range of a function is the set of all possible output values (typically represented as "y") that a function can take. For rational functions, the range can often be found by identifying the horizontal asymptotes, which represents a value that the function approaches but never actually reaches. In the case of \(f(x) = \frac{4x + 5}{3x - 8}\), we find the horizontal asymptote by examining the ratio of the leading coefficients in the function, because as \(x\) tends towards infinity, those terms dominate the behavior of the function. Here, the horizontal asymptote is\[y = \frac{4}{3}\]As such, the range of \(f(x)\) is all real numbers except \(y = \frac{4}{3}\). This means \(f(x)\) can produce any real number apart from \(\frac{4}{3}\).
- The horizontal asymptote limits the range.
- \(y\) cannot equal \(\frac{4}{3}\).
Rational Functions
Rational functions are functions represented by the ratio of two polynomials. The general form of a rational function is \(f(x) = \frac{P(x)}{Q(x)}\), where both \(P(x)\) and \(Q(x)\) are polynomials, and \(Q(x) eq 0\). A key characteristic of rational functions is that they can have asymptotes:
- Vertical asymptotes occur where the function becomes undefined (where \(Q(x) = 0\)).
- Horizontal asymptotes depend on the degree and leading coefficients of the numerator and denominator polynomials.
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