Problem 23
Question
Exer. 13-26: Find a polar equation that has the same graph as the equation in \(x\) and \(y\). $$ y^{2}-x^{2}=4 $$
Step-by-Step Solution
Verified Answer
The polar equation is \( r^2 \cos(2\theta) = -4 \).
1Step 1: Understand the Relationship Between Cartesian and Polar Coordinates
In polar coordinates, a point is given by \((r, \theta)\) where \(r\) is the radius or distance from the origin, and \(\theta\) is the angle from the positive x-axis. The relationships between Cartesian coordinates \((x, y)\) and polar coordinates \((r, \theta)\) are \(x = r \cos \theta\) and \(y = r \sin \theta\).
2Step 2: Substitute Cartesian Formulas into the Original Equation
Begin with the original equation in Cartesian form: \[ y^2 - x^2 = 4 \]Substitute the polar coordinate formulas: \[ (r \sin \theta)^2 - (r \cos \theta)^2 = 4 \]
3Step 3: Simplify the Polar Equation
Simplify the expression: \[ r^2 \sin^2 \theta - r^2 \cos^2 \theta = 4 \]Factor out \(r^2\): \[ r^2 (\sin^2 \theta - \cos^2 \theta) = 4 \]
4Step 4: Use Trigonometric Identity
Recall the trigonometric identity: \[ \sin^2 \theta - \cos^2 \theta = -\cos(2\theta) \]Substitute this into the equation: \[ r^2 (-\cos(2\theta)) = 4 \]
5Step 5: Rearrange for a Clean Polar Equation
Rearrange the equation to get: \[ r^2 \cos(2\theta) = -4 \]This is the required polar equation.
Key Concepts
Cartesian CoordinatesTrigonometric IdentitiesEquation ConversionPolar Equations
Cartesian Coordinates
Cartesian coordinates are a common way to describe points on a plane using two values, typically denoted as \(x\) and \(y\). Imagine a flat surface like a sheet of paper. The horizontal line running across it is the x-axis, while the vertical line is the y-axis. Each point on this plane has a unique pair of coordinates \((x, y)\).
Here’s how it works:
Here’s how it works:
- \(x\) is the distance the point is from the y-axis, moving left or right.
- \(y\) is the distance from the x-axis, moving up or down.
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are universally true. They help in simplifying complex mathematical expressions. When working with polar and Cartesian equations, these identities can be very handy.
A few common trigonometric identities include:
A few common trigonometric identities include:
- \( \sin^2 \theta + \cos^2 \theta = 1\), which is the Pythagorean identity.
- \( \tan \theta = \frac{\sin \theta}{\cos \theta}\).
- \( \sin(2\theta) = 2\sin \theta \cos \theta\).
Equation Conversion
Equation conversion involves changing an equation from one form to another. In mathematics, it's often necessary to shift between Cartesian and polar forms to analyze or solve a problem effectively.
This transformation hinges on using known relationships between the two coordinate systems:
This transformation hinges on using known relationships between the two coordinate systems:
- From Cartesian to polar: \(x = r \cos \theta\) and \(y = r \sin \theta\).
- From polar to Cartesian: \(r^2 = x^2 + y^2\) and \( heta = \tan^{-1}(\frac{y}{x})\).
Polar Equations
Polar equations describe the relationship between the radius \(r\) and the angle \(\theta\) of a point from a central origin. Unlike Cartesian equations, where two coordinates determine a point's position, polar equations rely on distance and angle.
Here’s how polar coordinates work:
Here’s how polar coordinates work:
- The radius \(r\) represents the distance from the origin to the point.
- The angle \(\theta\) represents the direction from the positive x-axis.
Other exercises in this chapter
Problem 22
Exer. 19-30: Find an equation for the ellipse that has its center at the origin and satisfies the given conditions. Foci \(F(\pm 3,0)\), minor axis of length 2
View solution Problem 23
\(x=e^{t}, \quad y=e^{-2 t}, \quad t\) in \(\mathbb{R}\)
View solution Problem 23
Find an equation for the hyperbola that has its center at the origin and satisfies the given conditions. Foci \(F(\pm 5,0)\), vertices \(V(\pm 3,0)\)
View solution Problem 23
Exer. 19-30: Find an equation of the parabola that satisfies the given conditions. $$ \text { Vertex } V(3,-5), \quad \text { directrix } x=2 $$
View solution