Problem 23
Question
Evaluate the piece wise defined function at the indicated values. $$ f(x)=\left\\{\begin{array}{l}{x^{2}+2 x} \\ {x} \\ {-1}\end{array}\right. $$ $$ \begin{array}{l}{\text { if } x \leq -1} \\ {\text { if }-1< x \leq 1} \\\ {\text { if } x >1}\end{array} $$ $$ f(-4), f\left(-\frac{3}{2}\right), f(-1), f(0), f(25) $$
Step-by-Step Solution
Verified Answer
\( f(-4)=8, f\left(-\frac{3}{2}\right)=-\frac{3}{4}, f(-1)=-1, f(0)=0, f(25)=-1 \)
1Step 1: Understanding the Piecewise Function
The function is defined in three different ways depending on the value of \( x \):1. \( f(x) = x^2 + 2x \) if \( x \leq -1 \).2. \( f(x) = x \) if \( -1 < x \leq 1 \).3. \( f(x) = -1 \) if \( x > 1 \).
2Step 2: Evaluating at \( x = -4 \)
Since \( -4 \leq -1 \), we use \( f(x) = x^2 + 2x \).Thus, \( f(-4) = (-4)^2 + 2(-4) = 16 - 8 = 8 \).
3Step 3: Evaluating at \( x = -\frac{3}{2} \)
Since \( -\frac{3}{2} \leq -1 \), we use \( f(x) = x^2 + 2x \).Thus, \( f\left(-\frac{3}{2}\right) = \left(-\frac{3}{2}\right)^2 + 2\left(-\frac{3}{2}\right) = \frac{9}{4} - 3 = -\frac{3}{4} \).
4Step 4: Evaluating at \( x = -1 \)
Since \( x = -1 \leq -1 \), we use \( f(x) = x^2 + 2x \).Thus, \( f(-1) = (-1)^2 + 2(-1) = 1 - 2 = -1 \).
5Step 5: Evaluating at \( x = 0 \)
Since \( -1 < 0 \leq 1 \), we use \( f(x) = x \).Thus, \( f(0) = 0 \).
6Step 6: Evaluating at \( x = 25 \)
Since \( x > 1 \), we use \( f(x) = -1 \).Thus, \( f(25) = -1 \).
Key Concepts
Function EvaluationStep-by-Step SolutionPiecewise Definition
Function Evaluation
Function evaluation is the process of finding the output of a function for a given input value, using the rules or formulas defined by the function. In our exercise, we're dealing with a piecewise function, which means that its formula or rule changes depending on the value of the input \( x \).
To evaluate this function, you must first determine which condition \( x \) satisfies and then use the corresponding part of the piecewise function definition. This involves substituting the \( x \) value into the appropriate expression to find \( f(x) \). Here’s what you should keep in mind for evaluating a piecewise function:
To evaluate this function, you must first determine which condition \( x \) satisfies and then use the corresponding part of the piecewise function definition. This involves substituting the \( x \) value into the appropriate expression to find \( f(x) \). Here’s what you should keep in mind for evaluating a piecewise function:
- Check against each condition sequentially.
- Determine which condition \( x \) satisfies.
- Use the formula specific to that condition to calculate \( f(x) \).
Step-by-Step Solution
A step-by-step solution helps in systematically breaking down the evaluation process of a piecewise function as shown in the original solution. The process ensures accuracy and aids in understanding.
1. **Evaluating at \( x = -4 \):**
Identify that \( -4 \leq -1 \). Hence, use \( f(x) = x^2 + 2x \). After substituting \( x = -4 \), calculate the result: \[ f(-4) = (-4)^2 + 2(-4) = 16 - 8 = 8 \]
2. **Evaluating at \( x = -\frac{3}{2} \):**
The condition \( -\frac{3}{2} \leq -1 \) indicates the same formula as above. Substituting, the calculation yields: \[ f\left(-\frac{3}{2}\right) = \left(-\frac{3}{2}\right)^2 + 2\left(-\frac{3}{2}\right) = \frac{9}{4} - 3 = -\frac{3}{4} \]
3. **Evaluating at \( x = -1 \):**
Since \( x = -1 \leq -1 \), again use \( f(x) = x^2 + 2x \), giving: \[ f(-1) = (-1)^2 + 2(-1) = 1 - 2 = -1 \]
4. **Evaluating at \( x = 0 \):**
Here, \( -1 < 0 \leq 1 \) points to \( f(x) = x \). Thus:\[ f(0) = 0 \]
5. **Evaluating at \( x = 25 \):**
Since \( x > 1 \), apply \( f(x) = -1 \), resulting directly in:\[ f(25) = -1 \]
Following a structured approach like this ensures no steps are overlooked, making sure the final outcomes are correct.
1. **Evaluating at \( x = -4 \):**
Identify that \( -4 \leq -1 \). Hence, use \( f(x) = x^2 + 2x \). After substituting \( x = -4 \), calculate the result: \[ f(-4) = (-4)^2 + 2(-4) = 16 - 8 = 8 \]
2. **Evaluating at \( x = -\frac{3}{2} \):**
The condition \( -\frac{3}{2} \leq -1 \) indicates the same formula as above. Substituting, the calculation yields: \[ f\left(-\frac{3}{2}\right) = \left(-\frac{3}{2}\right)^2 + 2\left(-\frac{3}{2}\right) = \frac{9}{4} - 3 = -\frac{3}{4} \]
3. **Evaluating at \( x = -1 \):**
Since \( x = -1 \leq -1 \), again use \( f(x) = x^2 + 2x \), giving: \[ f(-1) = (-1)^2 + 2(-1) = 1 - 2 = -1 \]
4. **Evaluating at \( x = 0 \):**
Here, \( -1 < 0 \leq 1 \) points to \( f(x) = x \). Thus:\[ f(0) = 0 \]
5. **Evaluating at \( x = 25 \):**
Since \( x > 1 \), apply \( f(x) = -1 \), resulting directly in:\[ f(25) = -1 \]
Following a structured approach like this ensures no steps are overlooked, making sure the final outcomes are correct.
Piecewise Definition
A piecewise function is a function composed of multiple "pieces," each defined by its own formula and applicable on specific intervals of the input value \( x \). This type of function allows for different rules to apply in different situations, offering flexibility where a single rule wouldn’t suffice.
In this exercise, the function \( f(x) \) is broken down into three pieces:
The conditions and domains are written explicitly along with each formula, specifying clearly which rule of the function applies for which range of values.
This structured definition can represent phenomena that exhibit distinct behaviors across different circumstances, such as different tax brackets in finance, or piecewise linear graphs. By understanding piecewise functions, you gain the ability to explore and analyze complex functions that express real-world situations more accurately.
In this exercise, the function \( f(x) \) is broken down into three pieces:
- \( f(x) = x^2 + 2x \) when \( x \leq -1 \)
- \( f(x) = x \) when \( -1 < x \leq 1 \)
- \( f(x) = -1 \) when \( x > 1 \)
The conditions and domains are written explicitly along with each formula, specifying clearly which rule of the function applies for which range of values.
This structured definition can represent phenomena that exhibit distinct behaviors across different circumstances, such as different tax brackets in finance, or piecewise linear graphs. By understanding piecewise functions, you gain the ability to explore and analyze complex functions that express real-world situations more accurately.
Other exercises in this chapter
Problem 23
Use the Inverse Function Property to show that \(f\) and \(g\) are inverses of each other. \(f(x)=2 x-5 ; \quad g(x)=\frac{x+5}{2}\)
View solution Problem 23
\(17-28\) A function is given. Determine the average rate of change of the function between the given values of the variable. $$ f(x)=3 x^{2} ; \quad x=2, x=2+h
View solution Problem 24
19-28 \(=\) A quadratic function is given. (a) Express the quadratic function in standard form. (b) Sketch its graph. (c) Find its maximum or minimum value. $$
View solution Problem 24
23–26 ? Explain how the graph of g is obtained from the graph of f. (a) \(f(x)=x^{3}, \quad g(x)=(x-4)^{3}\) (b) \(f(x)=x^{3}, \quad g(x)=x^{3}-4\)
View solution