Problem 23
Question
Determine whether the inverse of \(f\) is a function. Then find the inverse. \(f(x)=\frac{3}{x^2}+1\)
Step-by-Step Solution
Verified Answer
The inverse of the given function is indeed a function. Its mathematical expression is \(f^{-1}(x) = \sqrt{\frac{3}{x-1}}\) and its domain is \(x>1\).
1Step 1: Applying the Horizontal Line Test
The graph of our given function \(f(x)=\frac{3}{x^2}+1\) is represented by a vertical parabola which doesn't intersect any horizontal line more than once. So, the inverse of this function is itself a function.
2Step 2: Switch Function to a 'y' notation
Replace \(f(x)\) by \(y\). So, our equation becomes \(y=\frac{3}{x^2}+1\)
3Step 3: Switch 'x' and 'y'
Now, switch 'x' and 'y' to get: \(x=\frac{3}{y^2}+1\)
4Step 4: Solve for 'y'
Solve the equation for 'y' to get the inverse. First, subtract '1' to get \(x-1=\frac{3}{y^2}\). Now, reciprocate the equation to get \(\frac{1}{x-1}=\frac{y^2}{3}\). Then take the square root of both sides to get \(y = \sqrt{\frac{3}{x-1}}\) which is the inverse of \(f(x) = \frac{3}{x^2}+1\). The domain has to be \(x>1\) for the inverse function to be real.
Key Concepts
Horizontal Line TestSolving EquationsDomain and Range
Horizontal Line Test
The Horizontal Line Test is a visual way to determine if a function has an inverse that is also a function. Imagine drawing horizontal lines through the graph of the function you're examining. If any of these lines intersect the graph at more than one point, the function does not pass the test.
For a function to have an inverse that is also a function, each horizontal line should intersect the graph at most once. This indicates that for every output or 'y' value, there is only one corresponding 'x' value.
For a function to have an inverse that is also a function, each horizontal line should intersect the graph at most once. This indicates that for every output or 'y' value, there is only one corresponding 'x' value.
- If a function passes the Horizontal Line Test, it is one-to-one. This allows the function to have an inverse.
- If it fails the test, the inverse will not be a function.
Solving Equations
To find the inverse of a function, solving equations accurately is key. After identifying the function, usually represented in terms of 'y', the next step is to swap the roles of 'x' and 'y'. This transformation helps in finding the inverse.
For our given function, we first express it as:
For our given function, we first express it as:
- Replace the function notation with 'y', making the equation easier to handle, like a regular algebraic expression.
- We then swapped 'x' and 'y'. Now, it’s time to solve for 'y'.
- Begin by subtracting values to clear out unnecessary terms.
- Use reciprocation: this helps in simplifying fractions on both sides of the equation.
- Finally, solve for 'y' using operations like square rooting, while ensuring all mathematical rules are respected.
Domain and Range
Understanding a function's domain and range is crucial when dealing with inverse functions. The domain refers to all possible 'x' values a function can take, while the range is all resulting 'y' values from applying these 'x' values.
When finding the inverse of a function, the domain and range swap roles:
When finding the inverse of a function, the domain and range swap roles:
- The domain of the original function becomes the range of the inverse.
- The range of the original function becomes the domain of the inverse.
Other exercises in this chapter
Problem 22
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