Problem 23
Question
Determine whether each is an expression or an equation. Simplify any expressions, and solve any equations. $$ 5(x+3)-8(2 x-6)=12 $$
Step-by-Step Solution
Verified Answer
This is an equation. Solving for x, the value is x = 51 / 11.
1Step 1: Identify if it's an expression or an equation
The given problem is: 5(x+3)-8(2x-6)=12 An equation has an equality sign \(=\). Since we have the equality sign, this is an equation.
2Step 2: Distribute the constants inside the parentheses
Distribute the constants 5 and -8 into the terms inside the parentheses: 5(x+3) = 5x + 15 -8(2x-6) = -16x + 48 The equation then becomes: 5x + 15 - 16x + 48 = 12.
3Step 3: Combine like terms
Combine the terms involving x and the constant terms: 5x - 16x + 15 + 48 = 12 Combine them to get: -11x + 63 = 12.
4Step 4: Isolate the variable term on one side
Subtract 63 from both sides to isolate the term with the variable (x): -11x + 63 - 63 = 12 - 63 This simplifies to: -11x = -51.
5Step 5: Solve for the variable
Divide both sides by -11 to solve for x: \(-11x / -11 = -51 / -11\) This simplifies to: x = 51 / 11.
Key Concepts
Simplifying Algebraic ExpressionsDistributive PropertyIsolating Variables
Simplifying Algebraic Expressions
Simplifying algebraic expressions is an essential skill in algebra. It involves combining like terms, which are terms that have the same variables raised to the same power. This helps in reducing the expression to its simplest form.
In our exercise, we start by simplifying the terms inside the parentheses. For the given equation, we have 5(x+3) and -8(2x-6). Use the distributive property to expand these terms:
5(x+3) = 5x + 15
-8(2x-6) = -16x + 48
This gives a more straightforward form of the equation: 5x + 15 - 16x + 48 = 12. Next, combine the like terms (terms with x and constant terms):
5x and -16x are like terms, so combine them: 5x - 16x = -11x.
Also, 15 and 48 are constants, so sum them up: 15 + 48 = 63.
Now we have a simplified equation: -11x + 63 = 12.
In our exercise, we start by simplifying the terms inside the parentheses. For the given equation, we have 5(x+3) and -8(2x-6). Use the distributive property to expand these terms:
5(x+3) = 5x + 15
-8(2x-6) = -16x + 48
This gives a more straightforward form of the equation: 5x + 15 - 16x + 48 = 12. Next, combine the like terms (terms with x and constant terms):
5x and -16x are like terms, so combine them: 5x - 16x = -11x.
Also, 15 and 48 are constants, so sum them up: 15 + 48 = 63.
Now we have a simplified equation: -11x + 63 = 12.
Distributive Property
The distributive property is a useful tool in algebra that allows you to multiply a single term by each term within parentheses. It helps simplify expressions and is crucial for solving equations. The distributive property can be written as:
\[a(b + c) = ab + ac\]
In our given equation, we used the distributive property twice:
5(x + 3) = 5 \times x + 5 \times 3 = 5x + 15
and
-8(2x - 6) = -8 \times 2x + (-8) \times (-6) = -16x + 48.
This transformation helps in laying down the equation in a simpler form to solve for the variable x. Always remember to multiply each term inside the parentheses individually by the term outside.
\[a(b + c) = ab + ac\]
In our given equation, we used the distributive property twice:
5(x + 3) = 5 \times x + 5 \times 3 = 5x + 15
and
-8(2x - 6) = -8 \times 2x + (-8) \times (-6) = -16x + 48.
This transformation helps in laying down the equation in a simpler form to solve for the variable x. Always remember to multiply each term inside the parentheses individually by the term outside.
Isolating Variables
Solving equations often involves isolating the variable on one side of the equation. This means you want to get all terms with the variable on one side and the constants on the other side.
For our specific example: We start from -11x + 63 = 12.
To isolate the variable term (-11x), subtract 63 from both sides:
-11x + 63 - 63 = 12 - 63
This simplifies to: -11x = -51.
Finally, solve for x by dividing both sides by -11: \ \frac{-51}{-11} = x \
This simplifies to:
\[x = 51 / 11\].
Now you've isolated and solved for the variable x. Practice makes this process more intuitive!
- Start by combining like terms as seen in the previous sections.
- Next, move the constant terms to the opposite side of the equation from the variable terms.
For our specific example: We start from -11x + 63 = 12.
To isolate the variable term (-11x), subtract 63 from both sides:
-11x + 63 - 63 = 12 - 63
This simplifies to: -11x = -51.
Finally, solve for x by dividing both sides by -11: \ \frac{-51}{-11} = x \
This simplifies to:
\[x = 51 / 11\].
Now you've isolated and solved for the variable x. Practice makes this process more intuitive!
Other exercises in this chapter
Problem 23
Solve each inequality. Graph the solution set, and write it using interval notation. \(5 x+2 \leq-48\)
View solution Problem 23
Solve each equation. $$ \left|\frac{1}{2} x+3\right|=2 $$
View solution Problem 23
Mulder and Scully are driving to Georgia to investigate "Big Blue," a giant reptile reported in one of the local lakes. Mulder leaves the office at 8: 30 A.M. a
View solution Problem 24
The formula \(F=\frac{9}{5} C+32\) can be solved for \(C\) to obtain \(C=\frac{5}{9}(F-32)\). Which one of the following is not equivalent to this? A. \(C=\frac
View solution