Problem 23
Question
Determine the following limits. $$\lim _{x \rightarrow \infty}\left(-12 x^{-5}\right)$$
Step-by-Step Solution
Verified Answer
Answer: The limit of the function $$-12x^{-5}$$ as x approaches infinity is 0.
1Step 1: 1. Analyze the Given Function
Observe that the given function is of the form $$-12x^{-5}$$. As x approaches infinity, the term $$x^{-5}$$ will approach zero, since the exponent is negative.
2Step 2: 2. Calculate the Limit
Now, we will calculate the limit of the function as x approaches infinity:
$$\lim_{x \rightarrow \infty}\left(-12 x^{-5}\right)$$
As the term $$x^{-5}$$ approaches zero, the function becomes:
$$\lim_{x \rightarrow \infty}\left(-12 \cdot 0\right)$$
Multiply -12 by 0, which results in 0:
$$\lim_{x \rightarrow \infty}\left(0\right)$$
Therefore, as x approaches infinity, the limit of the function $$-12x^{-5}$$ is equal to 0.
Key Concepts
Infinite LimitsExponential DecayEvaluating Limits
Infinite Limits
In the realm of calculus, understanding infinite limits is crucial. When we discuss infinite limits, we're looking at what happens to a function as the variable approaches infinity. In simpler terms, we are interested in the behavior of the function when the variable gets very, very large.
For example, in the function \(-12x^{-5}\), as \(x\) increases towards infinity, the expression \(x^{-5}\) implies that \(x\) is raised to the negative fifth power. This means that a large \(x\) value makes the expression very small. Essentially, \(x^{-5}\) approaches zero as \(x\) becomes infinitely large. Since we're multiplying this near-zero value by -12, the whole expression tends towards zero.
Here, it's vital to distinguish between concepts like a variable going to infinity versus a function's limit going to infinity. In our example, although \(x\) goes to infinity, the function itself goes to zero. This demonstrates an **infinite limit** where the input grows without bounds, affecting the behavior of the function.
For example, in the function \(-12x^{-5}\), as \(x\) increases towards infinity, the expression \(x^{-5}\) implies that \(x\) is raised to the negative fifth power. This means that a large \(x\) value makes the expression very small. Essentially, \(x^{-5}\) approaches zero as \(x\) becomes infinitely large. Since we're multiplying this near-zero value by -12, the whole expression tends towards zero.
Here, it's vital to distinguish between concepts like a variable going to infinity versus a function's limit going to infinity. In our example, although \(x\) goes to infinity, the function itself goes to zero. This demonstrates an **infinite limit** where the input grows without bounds, affecting the behavior of the function.
Exponential Decay
Exponential decay is a fascinating yet important concept. It's observed when values decrease rapidly at first, then slowly over time. In the context of limits, this often involves terms with negative exponents.
Take \(-12x^{-5}\) from our exercise. The term \(x^{-5}\) is analogous to the effect of exponential decay because as \(x\) grows, \(x^{-5}\) diminishes. This rapid decrease towards zero is what defines exponential decay within limits. Hence, when you see a negative exponent in a function, anticipate this behavior: quick decline settling toward a minimal value.
Important characteristics of exponential decay include:
Take \(-12x^{-5}\) from our exercise. The term \(x^{-5}\) is analogous to the effect of exponential decay because as \(x\) grows, \(x^{-5}\) diminishes. This rapid decrease towards zero is what defines exponential decay within limits. Hence, when you see a negative exponent in a function, anticipate this behavior: quick decline settling toward a minimal value.
Important characteristics of exponential decay include:
- A starting point which quickly falls off.
- Eventually tapering toward zero or some minimal value.
Evaluating Limits
The ability to evaluate limits helps us understand the behavior of functions as variables approach particular values, including infinity. Let's go step-by-step for clarity using the example \(-12x^{-5}\).
- **Recognize the form:** Here, it's crucial to identify the form, which is \(-12x^{-5}\). This guides our expectations since \(x^{-5}\) hints at exponential decay.
- **Analyze component behavior:** With \(x^{-5}\) as \(x\) approaches infinity, it moves nearly to zero. Therefore, focus on how \(x^{-5}\) changes as \(x\) gets large.
- **Multiply and conclude:** Multiply the resulting small value by -12. This shows that the entire function approaches zero, reflecting both infinite limit characteristics and exponential decay.
Other exercises in this chapter
Problem 22
Use Theorem 2.10 to determine the intervals on which the following functions are continuous. $$g(x)=\frac{3 x^{2}-6 x+7}{x^{2}+x+1}$$
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Use the precise definition of a limit to prove the following limits. $$\left.\lim _{x \rightarrow 0} x^{2}=0 \text { (Hint: Use the identity } \sqrt{x^{2}}=|x|
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Assume \(\lim _{x \rightarrow 1} f(x)=8, \lim _{x \rightarrow 1} g(x)=3,\) and \(\lim _{x \rightarrow 1} h(x)=2 .\) Compute the following limits and state the l
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