Problem 23
Question
Decide whether each function is one-to-one. $$y=\frac{-4}{x-8}$$
Step-by-Step Solution
Verified Answer
The function is one-to-one.
1Step 1: Understand One-to-One Functions
A function is one-to-one if each element of the range is mapped to by exactly one element of the domain. This means that no two different x-values can produce the same y-value in one-to-one functions.
2Step 2: Investigate the Function
Consider the function given: \( y = \frac{-4}{x-8} \). This is a rational function. To determine if it is one-to-one, we need to check if different x-values lead to different y-values.
3Step 3: Horizontal Line Test
For a function to be one-to-one, no horizontal line should intersect the graph of the function at more than one point. For the given rational function, \( y = \frac{-4}{x-8} \), evaluate by imagining any horizontal line \( y = k \). Each \( y = k \) intersects the graph at only one x-value, since the function can't output the same y-value for different x-values.
4Step 4: Algebraic Test for Injectivity
Test algebraically by assuming \( y_1 = y_2 \), which results from different x-values \( x_1 \) and \( x_2 \). Set \( \frac{-4}{x_1 - 8} = \frac{-4}{x_2 - 8} \). This implies \( x_1 - 8 = x_2 - 8 \), hence \( x_1 = x_2 \). Therefore, the function is injective.
Key Concepts
Horizontal Line TestRational FunctionsInjectivity
Horizontal Line Test
The Horizontal Line Test is a simple and intuitive way to determine if a function is one-to-one, also known as injective. Imagine drawing horizontal lines across the graph of the function. A function is considered one-to-one if and only if no horizontal line intersects the graph more than once.
For the function given in the exercise, \( y = \frac{-4}{x-8} \), applying the Horizontal Line Test requires envisioning any possible horizontal line at \( y = k \), where \( k \) is any constant. In this rational function, any horizontal line will intersect the curve only once as each \( y \) value results from a unique \( x \) value.
In simpler terms:
For the function given in the exercise, \( y = \frac{-4}{x-8} \), applying the Horizontal Line Test requires envisioning any possible horizontal line at \( y = k \), where \( k \) is any constant. In this rational function, any horizontal line will intersect the curve only once as each \( y \) value results from a unique \( x \) value.
In simpler terms:
- If you can draw a horizontal line that hits the function’s graph in more than one spot, the function isn't one-to-one.
- If every horizontal line you can draw only hits one point, the function is one-to-one.
Rational Functions
Rational functions are fractions where both the numerator and the denominator are polynomials. In the expression \( y = \frac{-4}{x-8} \), \(-4\) is the numerator, and \( x-8 \) is the denominator.
These kinds of functions are important as they exhibit interesting behaviors, like vertical asymptotes, and can model several real-world phenomena. Let's explore their characteristics:
These kinds of functions are important as they exhibit interesting behaviors, like vertical asymptotes, and can model several real-world phenomena. Let's explore their characteristics:
- Rational functions are undefined where the denominator equals zero. For \( y = \frac{-4}{x-8} \), the function is undefined at \( x = 8 \) because dividing by zero is not allowed.
- They might have vertical asymptotes, as is the case here at \( x = 8 \).
- The graph of a rational function can display unique patterns making them easy to distinguish from linear or polynomial functions.
- Rational functions are typically smooth, except at points where they are undefined, resulting in vertical asymptotes.
Injectivity
Injectivity, or being one-to-one, is a property of a function indicating that distinct inputs (x-values) lead to distinct outputs (y-values). This is a crucial trait for defining the inverse of a function.
In mathematical language, a function \( f : A \rightarrow B \) is injective if \( f(x_1) = f(x_2) \) implies \( x_1 = x_2 \). In the exercise, to show \( y = \frac{-4}{x-8} \) is injective, we set \( \frac{-4}{x_1-8} = \frac{-4}{x_2-8} \). By algebraic manipulation, this tells us \( x_1 = x_2 \), confirming injectivity.
Here's an easy way to remember it:
In mathematical language, a function \( f : A \rightarrow B \) is injective if \( f(x_1) = f(x_2) \) implies \( x_1 = x_2 \). In the exercise, to show \( y = \frac{-4}{x-8} \) is injective, we set \( \frac{-4}{x_1-8} = \frac{-4}{x_2-8} \). By algebraic manipulation, this tells us \( x_1 = x_2 \), confirming injectivity.
Here's an easy way to remember it:
- No two different inputs should result in the same output.
- If you test several inputs and see that no output repeats, the function is injective.
Other exercises in this chapter
Problem 22
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Graph each function by hand and support your sketch with a calculator graph. Give the domain, range. and equation of the asymptote. Determine if \(f\) is increa
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