Problem 23
Question
Calculate the time required for a sample of radioactive tritium to lose \(80.0 \%\) of its activity. (Tritium has a half-life of 12.3 years.)
Step-by-Step Solution
Verified Answer
19.9 years
1Step 1: Understanding the Problem
We need to calculate the time it takes for tritium to lose 80% of its radioactivity. This implies finding the time it takes for the radioactivity to drop to 20% (since 100% - 80% = 20%) of its original activity. We know that the half-life of tritium is 12.3 years.
2Step 2: Using the Exponential Decay Formula
The formula for radioactive decay is given by:\[ N(t) = N_0 e^{-kt} \]Where:- \( N(t) \) is the remaining quantity of the substance at time \( t \).- \( N_0 \) is the initial quantity of the substance.- \( k \) is the decay constant.- \( t \) is the time elapsed.
3Step 3: Calculating the Decay Constant
The decay constant \( k \) can be derived from the half-life \( T_{1/2} \) using the formula:\[ k = \frac{\ln(2)}{T_{1/2}} \]Substituting the given half-life of 12.3 years:\[ k = \frac{\ln(2)}{12.3} \approx 0.0564 \text{ per year} \]
4Step 4: Setting Up the Equation
We want the activity to decrease to 20% of its original value. Therefore, we set \( N(t) = 0.2N_0 \) and solve for \( t \):\[ 0.2N_0 = N_0 e^{-kt} \]This simplifies to:\[ 0.2 = e^{-kt} \]
5Step 5: Solving for Time, t
Taking the natural logarithm of both sides, we get:\[ \ln(0.2) = -kt \]Substituting \( k = 0.0564 \), solve for \( t \):\[ t = \frac{\ln(0.2)}{-0.0564} \approx 19.9 \text{ years} \]
6Step 6: Conclusion
It takes approximately 19.9 years for tritium to lose 80% of its radioactivity.
Key Concepts
Exponential DecayHalf-Life CalculationDecay Constant
Exponential Decay
Radioactive decay, like that of tritium, is a classic example of exponential decay. In this process, the quantity of a substance decreases at a rate proportional to its current amount. This can be expressed mathematically with the formula:
Understanding exponential decay helps to predict how a substance diminishes over time, which is crucial for calculating how long it takes to reach a certain level of activity.
- \( N(t) = N_0 e^{-kt} \)
- \( N(t) \) represents the quantity of radioactive substance remaining at time \( t \).
- \( N_0 \) is the initial quantity of the substance, or how much you started with.
- \( k \) is the decay constant, which is unique for each substance.
Understanding exponential decay helps to predict how a substance diminishes over time, which is crucial for calculating how long it takes to reach a certain level of activity.
Half-Life Calculation
The concept of a half-life is fundamental in understanding radioactive decay. It is the time required for a quantity to reduce to half its initial amount. Tritium, for example, has a half-life of 12.3 years, meaning after 12.3 years, only half of the initial tritium remains.
- During the first half-life, the substance reduces to 50% of the original amount.
- By the second half-life, it's reduced to 25%, and so on.
- 50 units remain. After another, only 25 units will.
Decay Constant
The decay constant \( k \) plays a key role in radioactive decay. It's a value that defines the rate at which a particular substance decays. For every radioactive isotope, like tritium, \( k \) can be calculated using its half-life with the formula:
- \( k = \frac{\ln(2)}{T_{1/2}} \)
- For tritium, with a half-life of 12.3 years, the decay constant is approximately 0.0564 per year.
Other exercises in this chapter
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