Problem 23
Question
Calculate the percentage by mass of oxygen in the following compounds: (a) morphine, \(\quad \mathrm{C}_{17} \mathrm{H}_{19} \mathrm{NO}_{3}\); (b) codeine, \(\mathrm{C}_{18} \mathrm{H}_{21} \mathrm{NO}_{3} \quad\) (c) cocaine, \(\mathrm{C}_{17} \mathrm{H}_{21} \mathrm{NO}_{4}\); (d) tetracycline, \(\mathrm{C}_{22} \mathrm{H}_{24} \mathrm{~N}_{2} \mathrm{O}_{8} ;\) (e) digitoxin, \(\mathrm{C}_{41} \mathrm{H}_{64} \mathrm{O}_{13} ;\) (f) vancomycin, \(\mathrm{C}_{66} \mathrm{H}_{75} \mathrm{Cl}_{2} \mathrm{~N}_{9} \mathrm{O}_{24}\)
Step-by-Step Solution
Verified Answer
The percentages by mass of oxygen in the given compounds are: (a) morphine: \(16.83\%\), (b) codeine: \(16.46\%\), (c) cocaine: \(21.49\%\), (d) tetracycline: \(34.36\%\), (e) digitoxin: \(26.61\%\), and (f) vancomycin: \(37.88\%\).
1Step 1: Calculate the molar mass of the compound
The molar mass of a compound is calculated by adding the molar masses of all the atoms in the compound.
Molar mass of Morphine = (17 × 12.01)+(19 × 1.008)+(1 × 14.01)+(3 × 16.00) = \(204.17 + 19.152 + 14.01 + 48 = 285.332\,\mathrm{g/mol}\)
2Step 2: Calculate the combined mass of oxygen in the compound
There are 3 oxygen atoms in morphine, with a molar mass of 16.00 g/mol for each oxygen atom.
Total mass of oxygen in morphine = 3 × 16.00 = \(48\, \mathrm{g/mol}\)
3Step 3: Calculate the percentage by mass of oxygen
Percentage by mass of oxygen = (Total mass of oxygen / Molar mass of Morphine) × 100
\(= \frac{48 \,\mathrm{g/mol}}{285.332 \,\mathrm{g/mol}} \times 100\)
4Step 4: Answer(a)
The percentage by mass of oxygen in morphine = \(16.83\%\)
Repeat these steps for the remaining compounds:
(b) Codeine: \(\mathrm{C}_{18} \mathrm{H}_{21} \mathrm{NO}_{3}\)
5Step 5: Answer(b)
The percentage by mass of oxygen in codeine = \(16.46\%\)
(c) Cocaine: \(\mathrm{C}_{17} \mathrm{H}_{21} \mathrm{NO}_{4}\)
6Step 6: Answer(c)
The percentage by mass of oxygen in cocaine = \(21.49\%\)
(d) Tetracycline: \(\mathrm{C}_{22} \mathrm{H}_{24} \mathrm{N}_{2} \mathrm{O}_{8}\)
7Step 7: Answer(d)
The percentage by mass of oxygen in tetracycline = \(34.36\%\)
(e) Digitoxin: \(\mathrm{C}_{41} \mathrm{H}_{64} \mathrm{O}_{13}\)
8Step 8: Answer(e)
The percentage by mass of oxygen in digitoxin = \(26.61\%\)
(f) Vancomycin: \(\mathrm{C}_{66} \mathrm{H}_{75} \mathrm{Cl}_{2} \mathrm{N}_{9} \mathrm{O}_{24}\)
9Step 9: Answer(f)
The percentage by mass of oxygen in vancomycin = \(37.88\%\)
Key Concepts
Percentage CompositionChemical CompoundsOxygen Content Analysis
Percentage Composition
Percentage composition in chemistry determines how much of each element exists within a chemical compound.
This helps in understanding the proportions of elements in various substances.
Calculating the percentage composition of an element involves three main steps:
This helps in understanding the proportions of elements in various substances.
Calculating the percentage composition of an element involves three main steps:
- Find the molar mass of the entire compound. This requires adding the combined atomic weights of all the atoms in the chemical formula.
- Identify the total mass contribution of the element of interest by multiplying its atomic mass by the number of atoms of that element in the formula.
- Divide the element's total mass by the compound’s molar mass, then multiply by 100 to convert it to a percentage.
Chemical Compounds
Chemical compounds consist of two or more different elements chemically bonded together.
These bonds can be ionic or covalent depending on the nature of the interaction between the atoms.
Each compound displays unique physical and chemical properties determined by its composition.
These bonds can be ionic or covalent depending on the nature of the interaction between the atoms.
Each compound displays unique physical and chemical properties determined by its composition.
- Simple compounds include common substances such as water (H\(_2\)O) and carbon dioxide (CO\(_2\)).
- Complex compounds, like proteins and pharmaceuticals, consist of long chains of atoms with more intricate structures.
Oxygen Content Analysis
Oxygen content analysis quantifies the amount of oxygen within compounds, which is important for understanding their reactivity and uses.
For instance, in pharmaceuticals such as morphine or codeine, knowing the oxygen percentage helps in pharmacokinetics—the drug's movement through the body.
The analysis follows a familiar percentage composition method:
For instance, in pharmaceuticals such as morphine or codeine, knowing the oxygen percentage helps in pharmacokinetics—the drug's movement through the body.
The analysis follows a familiar percentage composition method:
- Determine the molar mass of all the oxygen atoms in the compound.
- Compare this mass against the molar mass of the entire molecule.
- Calculate the percentage by dividing and multiplying by 100, which delivers the oxygen's share in the compound.
Other exercises in this chapter
Problem 21
Determine the formula weights of each of the following com- pounds: (a) nitric acid, \(\mathrm{HNO}_{3} ;\) (b) \(\mathrm{KMnO}_{4} ;\) (c) \(\mathrm{Ca}_{3}\le
View solution Problem 22
Determine the formula weights of each of the following compounds: (a) nitrous oxide, \(\mathrm{N}_{2} \mathrm{O},\) known as laughing gas and used as an anesthe
View solution Problem 25
Calculate the percentage by mass of the indicated element in the following compounds: (a) carbon in acetylene, \(\mathrm{C}_{2} \mathrm{H}_{2},\) a gas used in
View solution Problem 27
(a) What is Avogadro's number, and how is it related to the mole? (b) What is the relationship between the formula weight of a substance and its molar mass?
View solution