Problem 23
Question
Add or subtract as indicated. Write your answers in the form \(a+b i .\) $$ 6-(8+4 i) $$
Step-by-Step Solution
Verified Answer
The answer is \(-2 - 4i\).
1Step 1: Understanding the Expression
The problem provided is to subtract the complex number \((8 + 4i)\) from 6. The expression is written as \(6 - (8 + 4i)\).
2Step 2: Distribute the Negative Sign
To solve the expression, distribute the negative sign to both terms inside the parenthesis:\[6 - (8 + 4i) = 6 - 8 - 4i\]
3Step 3: Combine the Real Parts
Now, combine the real numbers (non-complex part):\[6 - 8 = -2\]
4Step 4: Write the Imaginary Part
The imaginary part is still \(-4i\) because there was no other imaginary number to combine it with. So we have:\[-2 - 4i\]
5Step 5: Conclude in the Form \(a+bi\)
The final result is in the form \(a + bi\), where \(a = -2\) and \(b = -4\): \(-2 - 4i\)
Key Concepts
Real PartImaginary PartSubtracting Complex Numbers
Real Part
When dealing with complex numbers, it's essential to understand the structure of these numbers. Each complex number can be expressed in the form \(a + bi\), where \(a\) represents the real part and \(b\) represents the imaginary part. The real part, \(a\), is simply a regular real number, untouched by any imaginary units like \(i\).
The real part is crucial because it helps us understand how the complex number behaves on the real axis of the complex plane. In the exercise, the complex number \((8 + 4i)\) features a real part of 8. However, we are subtracting it from 6, not another complex number. The result of this operation is found by performing the arithmetic solely on the real parts:
The real part is crucial because it helps us understand how the complex number behaves on the real axis of the complex plane. In the exercise, the complex number \((8 + 4i)\) features a real part of 8. However, we are subtracting it from 6, not another complex number. The result of this operation is found by performing the arithmetic solely on the real parts:
- Real part of 6 is 6
- Real part of \((8 + 4i)\) is 8
Imaginary Part
The imaginary part of a complex number is paired with the imaginary unit \(i\). For a complex number \(a + bi\), \(b\) denotes the imaginary part. This part illustrates how the number extends along the imaginary axis on the complex plane. This is essential for performing arithmetic operations on complex numbers, like addition and subtraction.
In the exercise example, the complex number \((8 + 4i)\) has an imaginary part of 4. When subtracting \((8 + 4i)\) from 6, the process involves separating the real and imaginary components:
In the exercise example, the complex number \((8 + 4i)\) has an imaginary part of 4. When subtracting \((8 + 4i)\) from 6, the process involves separating the real and imaginary components:
- The imaginary part \(4i\) from \((8 + 4i)\) becomes \(-4i\) when distributed with a negative sign.
Subtracting Complex Numbers
Subtracting complex numbers involves handling both their real and imaginary components separately. When facing an expression like \(6 - (8 + 4i)\), it's key to distribute any numbers or signs before tackling the subtraction.
Here's the step-by-step process:
By following these steps, the complete subtraction yields the result in the form \(a + bi\). The final answer, \(-2 - 4i\), shows clearly separated real and imaginary parts.
Here's the step-by-step process:
- Distribute the negative sign: Change the sign of each part of the number inside the parentheses. For instance, \((8 + 4i)\) when distributed becomes \(-8 - 4i\).
- Real numbers: Subtract the real parts: \(6 - 8 = -2\).
- Imaginary parts: Since 6 has no imaginary part, simply add \(-4i\): \(-2 - 4i\).
By following these steps, the complete subtraction yields the result in the form \(a + bi\). The final answer, \(-2 - 4i\), shows clearly separated real and imaginary parts.
Other exercises in this chapter
Problem 23
Add or subtract as indicated. Assume that all variables represent positive real numbers. $$ -5 \sqrt[3]{625}+\sqrt[3]{40} $$
View solution Problem 23
Use the quotient rule to simplify. Assume that all variables represent positive real numbers. $$ \sqrt[3]{\frac{2 x}{27 y^{12}}} $$
View solution Problem 24
Solve. $$ \sqrt{5 x-4}=9 $$
View solution Problem 24
Rationalize each denominator. Assume that all variables represent positive real numbers. \(\frac{1}{\sqrt{32 x}}\)
View solution