Problem 23
Question
A spinner has 4 sections labeled \(A, B, C,\) and \(D .\) Can the spinner be designed so \(P(A)=\frac{1}{12}, P(B)=\frac{1}{6}, P(C)=\frac{1}{3},\) and \(P(D)=\frac{5}{12} ?\) If so, explain how.
Step-by-Step Solution
Verified Answer
The sum of the probabilities \(P(A), P(B), P(C), P(D)\) is \(\frac{1}{12} + \frac{1}{6} + \frac{1}{3} + \frac{5}{12} = 1\). Therefore, it is possible to design the spinner with these probabilities for sections A, B, C, and D respectively.
1Step 1: Understand the total probability rule
In any random experiment (like spinning a spinner), the combined probability of all possible outcomes must be 1. This is a fundamental concept in probability, known as the total probability rule.
2Step 2: Add up the given probabilities
You need to add up the given probabilities \(P(A) = \frac{1}{12}, P(B) = \frac{1}{6}, P(C) = \frac{1}{3}, P(D) = \frac{5}{12}\). So the total probability \(P(Total) = P(A) + P(B) + P(C) + P(D)\).
3Step 3: Check if sum of probabilities is 1
Now, you evaluate whether the total probability equals to 1. If \(P(Total) = 1\), then it means that the spinner can be designed as per the given probabilities. If not, then it's impossible to design such a spinner based on the provided probabilities.
Key Concepts
Total Probability RuleRandom ExperimentProbability SumSpinner Design
Total Probability Rule
The Total Probability Rule is a key principle in probability theory. It states that the sum of the probabilities of all possible outcomes of a random experiment is always equal to 1. This rule is essential to ensure that all potential scenarios are accounted for, and no possibility is left unaddressed.
For instance, if you spin a spinner divided into sections, each section will account for a part of that total probability. Together, all probabilities must add up to 1, reflecting the fact that when you spin the spinner, one of the outcomes must occur.
By understanding the Total Probability Rule, we ensure that probability values are correctly assigned and verified for whatever random experiment we are considering.
For instance, if you spin a spinner divided into sections, each section will account for a part of that total probability. Together, all probabilities must add up to 1, reflecting the fact that when you spin the spinner, one of the outcomes must occur.
By understanding the Total Probability Rule, we ensure that probability values are correctly assigned and verified for whatever random experiment we are considering.
Random Experiment
A random experiment is any process or action where the outcome is uncertain. In the context of the probability problem we're discussing, spinning a spinner is an example of a random experiment.
Such experiments have several possible outcomes, which cannot be predicted with absolute certainty before the experiment is conducted. Each outcome has a probability associated with it, representing the chance of that specific result occurring.
Fundamentally, random experiments form the basis of probability studies, allowing us to predict likelihoods and make informed decisions based on potential results. Analyzing a spinner helps to visualize these concepts, turning abstract principles into something tangible.
Such experiments have several possible outcomes, which cannot be predicted with absolute certainty before the experiment is conducted. Each outcome has a probability associated with it, representing the chance of that specific result occurring.
Fundamentally, random experiments form the basis of probability studies, allowing us to predict likelihoods and make informed decisions based on potential results. Analyzing a spinner helps to visualize these concepts, turning abstract principles into something tangible.
Probability Sum
When dealing with probabilities, the concept of probability sum helps us check the validity of a probability distribution. To ensure a correct setup of a random experiment, like our spinner example, the sum of all individual outcome probabilities must equal 1.
Take the spinner problem: you're provided with probabilities for each section— \(P(A) = \frac{1}{12}\), \(P(B) = \frac{1}{6}\), \(P(C) = \frac{1}{3}\), and \(P(D) = \frac{5}{12}\). Adding these, we get:
Take the spinner problem: you're provided with probabilities for each section— \(P(A) = \frac{1}{12}\), \(P(B) = \frac{1}{6}\), \(P(C) = \frac{1}{3}\), and \(P(D) = \frac{5}{12}\). Adding these, we get:
- \(P(Total) = \frac{1}{12} + \frac{1}{6} + \frac{1}{3} + \frac{5}{12}\)
Spinner Design
When designing a spinner, the probability of landing on each section needs to be considered carefully. To fit the given probabilities for sections A, B, C, and D, the spinner must be constructed such that these probabilities are accurately represented.
Consider how dividing the spinner should both reflect and ensure the calculated probabilities. Each probability like \(\frac{1}{12}\), \(\frac{1}{6}\), \(\frac{1}{3}\), and \(\frac{5}{12}\) determines relative section sizes on the spinner. Suppose the circumference of the spinner is seen as 1 whole unit; then each segment's arc length should be proportionate to its assigned probability.
Creating a spinner based on such clear probability guidelines helps to visualize probability concepts and ensures all outcomes are equally and fairly assessed.
Consider how dividing the spinner should both reflect and ensure the calculated probabilities. Each probability like \(\frac{1}{12}\), \(\frac{1}{6}\), \(\frac{1}{3}\), and \(\frac{5}{12}\) determines relative section sizes on the spinner. Suppose the circumference of the spinner is seen as 1 whole unit; then each segment's arc length should be proportionate to its assigned probability.
Creating a spinner based on such clear probability guidelines helps to visualize probability concepts and ensures all outcomes are equally and fairly assessed.
Other exercises in this chapter
Problem 22
Quality Control A company claims that 99\(\%\) of its cereal boxes have at least as much cereal by weight as the amount stated on the box. a. At a quality contr
View solution Problem 23
Another measure of variation is variance, which equals \(\sigma^{2} .\) Find the variance and the standard deviation of each data set. $$ 60 \mathrm{m} 40 \math
View solution Problem 23
A normal distribution has a mean of 100 and a standard deviation of \(10 .\) Find the probability that a value selected at random is in the given interval. at l
View solution Problem 24
A normal distribution has a mean of 100 and a standard deviation of \(10 .\) Find the probability that a value selected at random is in the given interval. at m
View solution