Problem 23
Question
A Riddle A movie star, unwilling to give his age, posed the following riddle to a gossip columnist. "Seven years ago, I was eleven times as old as my daughter. Now I am four times as old as she is." How old is the star?
Step-by-Step Solution
Verified Answer
The movie star is 40 years old.
1Step 1: Define the Variables
Let the current age of the movie star be \( S \) and the current age of his daughter be \( D \). We need to find the value of \( S \).
2Step 2: Set Up the Equations
According to the riddle, seven years ago, the movie star was eleven times as old as his daughter. This gives us the equation: \( S - 7 = 11(D - 7) \). Currently, the star is four times as old as his daughter, which gives us another equation: \( S = 4D \).
3Step 3: Simplify the First Equation
Expand and simplify the first equation: \( S - 7 = 11(D - 7) \) becomes \( S - 7 = 11D - 77 \). Thus, \( S = 11D - 70 \).
4Step 4: Substitute and Solve
Substitute the expression for \( S \) from the current age condition \( S = 4D \) into the simplified equation from Step 3: \( 4D = 11D - 70 \).
5Step 5: Rearrange and Solve for Daughter's Age
Rearrange the equation \( 4D = 11D - 70 \) to \( 70 = 11D - 4D \), which simplifies to \( 70 = 7D \). Thus, \( D = 10 \).
6Step 6: Find the Star's Age
Since we know \( S = 4D \) and \( D = 10 \), substitute \( D = 10 \) into the equation \( S = 4D \) to get \( S = 4 \times 10 = 40 \).
Key Concepts
Variables in EquationsEquation SimplificationSubstitution MethodAge-related Problems
Variables in Equations
In algebra word problems, variables are used to represent unknown values. This allows us to form equations that we can solve. Here, let’s consider the scenario of our riddle involving a movie star and his daughter. We introduce variables to model the star's and his daughter’s ages.
For the riddle problem, we need a way to express these ages in a way that reflects the conditions given in the statement. So, we set:
For the riddle problem, we need a way to express these ages in a way that reflects the conditions given in the statement. So, we set:
- \( S \) as the current age of the movie star.
- \( D \) as the current age of his daughter.
Equation Simplification
Simplifying equations is a core concept in solving algebraic word problems. It involves making equations easier to solve by reducing their complexity.
In our riddle, we start with the relationship given from seven years ago: \( S - 7 = 11(D - 7) \).
This equation translates seven years in the past, revealing a connection between ages. We expand it:
In our riddle, we start with the relationship given from seven years ago: \( S - 7 = 11(D - 7) \).
This equation translates seven years in the past, revealing a connection between ages. We expand it:
- Distribute the 11 in \( 11 \times (D - 7) \) to get \( 11D - 77 \).
- Reorganize to isolate \( S \): \( S = 11D - 70 \).
Substitution Method
The substitution method is a powerful algebraic tool used to find the values of variables by replacing one variable with an expression derived from another equation. This method is particularly effective when dealing with multiple equations.
For the movie star’s puzzle, once the equations were set up, we had:
For the movie star’s puzzle, once the equations were set up, we had:
- The simplified equation \( S = 11D - 70 \).
- A current age condition \( S = 4D \).
Age-related Problems
Age-related problems often leverage basic algebra to solve. They typically involve relationships over time expressed through equations.
In this type of problem, you’re usually given a scenario where ages change over time and are related by conditions, like someone being a multiple of another person’s age in the past or present. For the movie star scenario:
In this type of problem, you’re usually given a scenario where ages change over time and are related by conditions, like someone being a multiple of another person’s age in the past or present. For the movie star scenario:
- Seven years ago: The star was eleven times the age of his daughter.
- Current: The star is four times his daughter’s age.
Other exercises in this chapter
Problem 22
\(9- 46\) The given equation is either linear or equivalent to a linear equation. Solve the equation. $$ \frac{2}{3} y+\frac{1}{2}(y-3)=\frac{y+1}{4} $$
View solution Problem 23
Solve the inequality. Express the answer using interval notation. $$ |x-5| \leq 3 $$
View solution Problem 23
\(9-32\) me solve the linear inequality. Express the solution using interval notation and graph the solution set. $$ 4-3 x \leq-(1+8 x) $$
View solution Problem 23
Evaluate the expression and write the result in the form \(a+b i .\) $$ (3-4 i)(5-12 i) $$
View solution