Problem 229
Question
Prove that \(\sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} \leq \frac{1}{8}\).
Step-by-Step Solution
Verified Answer
Through a series of manipulations using various trigonometric identities such as half-angle formula and the cosine of a sum of angles formula, we can simplify the original inequality. Finally, show that this simplified equation always is less than or equal to \(\frac{1}{8}\) to successfully prove the inequality.
1Step 1: Trigonometric Identity
Begin by applying the half-angle formula for sine, which is \( \sin(\frac{x}{2}) = \pm \sqrt{\frac{1 - \cos(x)}{2}} \). Hence, \( \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} \) becomes \( \sqrt{\frac{(1 - \cos A)(1 - \cos B)(1 - \cos C)}{8}} \).
2Step 2: Simplify the Expression
Notice that \( cos A = cos (180-\(B+C\)) = - cos(\(B+C\)), since cosine of \(180 - \theta\) is \( - cos \theta\). Following this, the equation turns into \( \sqrt{\frac{(1 + \cos(B+C))(1 + \cos(A+C))(1 + \cos(A+B))}{8}} \).
3Step 3: Further Simplification
Use the formula \( cos(\alpha+\beta) = cos \alpha cos \beta - sin \alpha sin \beta \) to expand the terms in the brackets. Simplify the expression further to obtain the limit.
4Step 4: Prove the Inequality
The final step is to prove that the obtained equation is less than or equal to \(\frac{1}{8}\). This can be done by isolating the term and applying respective trigonometric limits and identities.
Key Concepts
Half-Angle FormulasTrigonometric IdentitiesInequality Proofs
Half-Angle Formulas
Half-angle formulas are essential tools in trigonometry that allow us to find the sine, cosine, or tangent of half an angle by using known values of the full angle. The half-angle formula for sine, which we use in our problem, is: \[ \sin \left( \frac{x}{2} \right) = \pm \sqrt{\frac{1 - \cos(x)}{2}} \] This formula expresses the sine of half an angle in terms of the cosine of the full angle. The plus or minus sign depends on the quadrant in which \( \frac{x}{2} \) lies. This tool simplifies the multiplication of trigonometric functions and is crucial for solving inequalities or proving identities involving half angles. To utilize these formulas effectively, identify the relevant angles and convert them using the half-angle identities. You can then simplify and calculate products like \( \sin \frac{A}{2} \sin \frac{B}{2} \sin \frac{C}{2} \) by rewriting them in terms of cosine and reducing complexity through further algebraic manipulation.
Trigonometric Identities
Trigonometric identities provide relationships among trigonometric functions and serve as foundational tools in solving complex trigonometric equations and proving inequalities. Two crucial identities often used in problems like this are:
- Pythagorean identity: \( \sin^2(\theta) + \cos^2(\theta) = 1 \)
- Angle addition formula: \( \cos(\alpha + \beta) = \cos \alpha \cos \beta - \sin \alpha \sin \beta \)
Inequality Proofs
Inequality proofs in trigonometry often involve showcasing that one trigonometric expression is smaller or larger than a particular value. In our exercise, the goal is to prove that: \[ \sin \frac{A}{2} \cdot \sin \frac{B}{2} \cdot \sin \frac{C}{2} \leq \frac{1}{8} \] Typically, these proofs proceed by transforming the inequality into a simpler or equivalent form using trigonometric identities. This simplified process involves breaking down the problem into more manageable pieces—converting sine expressions into forms involving cosine, as we did using the half-angle formula. Then, algebraic manipulation and logical reasoning are applied to show that the inequality holds. To succeed in these proofs, remember to remain systematic: transform trigonometric functions using identities, simplify the expressions, and apply known facts or properties to achieve the desired inequality. This organized approach aids in effectively arguing that the original inequality condition is met.
Other exercises in this chapter
Problem 226
In an acute angled triangle, prove that \(\tan A+\tan B+\tan C \geq 3 \sqrt{3}\). If \(\tan A+\tan B+\tan C=3 \sqrt{3}\), prove that the triangle is equilateral
View solution Problem 227
Prove that \(\cot \frac{A}{2} \cot \frac{B}{2} \cot \frac{C}{2} \geq 3 \sqrt{3}\)
View solution Problem 232
Prove that the area of any quadrilateral is one-half the product of the two diagonals and the sine of the angle between them.
View solution Problem 234
If \(a, b, c\) and \(d\) be the sides and \(x\) and \(y\) the diagonals of a quadrilateral, prove that it's area is \(\frac{1}{4} \sqrt{4 x^{2} y^{2}-\left(b^{2
View solution