Problem 229
Question
If the \(\left[\mathrm{H}^{+}\right]\)is increased by 10 times, its \(\mathrm{pH}\) will change by ______ units.
Step-by-Step Solution
Verified Answer
The pH will decrease by 1 unit.
1Step 1: Understand the pH formula
The pH of a solution is calculated using the formula \( \text{pH} = -\log_{10} [\mathrm{H}^+] \). This equation relates the hydrogen ion concentration \([\mathrm{H}^+]\) to the pH.
2Step 2: Calculate new function with increased concentration
If the concentration of \([\mathrm{H}^+]\) is increased by 10 times, the new concentration will be denoted as \( [\mathrm{H}^+]_{new} = 10 \times [\mathrm{H}^+] \). We can express the related pH as \( \text{pH}_{new} = -\log_{10} (10 \times [\mathrm{H}^+]) \).
3Step 3: Simplify the logarithmic equation
Using the log property \( \log_{10} (a \times b) = \log_{10} a + \log_{10} b \), we have \( \text{pH}_{new} = - \log_{10} (10) - \log_{10} ([\mathrm{H}^+]) \). It follows that \( \text{pH}_{new} = -1 - \log_{10} [\mathrm{H}^+] \).
4Step 4: Calculate change in pH
The original pH is \( \text{pH} = - \log_{10} [\mathrm{H}^+] \). The new pH is \( \text{pH}_{new} = -1 - \log_{10} [\mathrm{H}^+] = \text{pH} - 1 \). Therefore, the change in pH is 1 unit.
Key Concepts
pH FormulaHydrogen Ion ConcentrationLogarithmic Properties
pH Formula
The pH formula is a key concept in chemistry that helps us understand the acidity or basicity of a solution. It's like a translator between the concentration of hydrogen ions in a solution and a number we can easily interpret. The formula used is:
- pH = -\( \log_{10} \left[ \text{H}^+ \right] \)
Hydrogen Ion Concentration
Hydrogen ion concentration, often written as
- \( \left[ \text{H}^+ \right] \)
- \( [\text{H}^+]_{new} = 10 \times [\text{H}^+] \)
Logarithmic Properties
In order to fully grasp how pH and hydrogen ion concentration are related, it's important to understand logarithmic properties. Logarithms are mathematical tools that can simplify the multiplication and division of numbers into addition and subtraction, thanks to properties like
- \( \log_{10}(a \times b) = \log_{10} a + \log_{10} b \)
- \( \text{pH}_{new} = -\log_{10}(10 \times [\text{H}^+]) = -\log_{10} 10 - \log_{10} [\text{H}^+] \)
- \( \text{pH}_{new} = -1 - \log_{10} [\text{H}^+] \)
Other exercises in this chapter
Problem 224
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