Problem 228
Question
Find the divergence of \(\mathbf{F}\). $$ \mathbf{F}(x, y)=x \mathbf{i}-y \mathbf{j} $$
Step-by-Step Solution
Verified Answer
The divergence of \(\mathbf{F}(x, y) = 0\).
1Step 1: Understanding Divergence
Divergence is a scalar measure of how much a vector field spreads out or converges at a given point. For a 2D vector field \(\mathbf{F}(x, y) = P(x, y) \mathbf{i} + Q(x, y) \mathbf{j}\), the divergence is given by the formula \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} \). Here, \(P(x, y) = x\) and \(Q(x, y) = -y\).
2Step 2: Calculate Partial Derivative of P with respect to x
For \(P(x, y) = x\), the partial derivative with respect to \(x\) is: \(\frac{\partial P}{\partial x} = \frac{\partial}{\partial x}(x) = 1\). This means the rate of change of \(P\) with respect to \(x\) is 1.
3Step 3: Calculate Partial Derivative of Q with respect to y
For \(Q(x, y) = -y\), the partial derivative with respect to \(y\) is: \(\frac{\partial Q}{\partial y} = \frac{\partial}{\partial y}(-y) = -1\). This means the rate of change of \(Q\) with respect to \(y\) is -1.
4Step 4: Calculate Divergence
Substitute the partial derivatives back into the divergence formula: \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} = 1 + (-1) = 0\).
5Step 5: Interpret the Result
The divergence \(0\) indicates that the vector field \(\mathbf{F}(x,y) = x \mathbf{i} - y \mathbf{j}\) is neither diverging nor converging at any point; it is source-free.
Key Concepts
Vector FieldPartial DerivativesScalar Measure
Vector Field
A vector field is a function that assigns a vector to every point in a space. In two dimensions, this means having a vector for each point in the plane. Each vector indicates direction and magnitude. In mathematical terms, a 2D vector field \( \mathbf{F}(x, y) \)might be represented as \( P(x, y) \mathbf{i} + Q(x, y) \mathbf{j} \), where:
- \( P(x, y) \) and \( Q(x, y) \) are scalar functions that define the components of each vector
- \( \mathbf{i} \) and \( \mathbf{j} \) are unit vectors pointing in the x and y-directions respectively
Partial Derivatives
Partial derivatives represent the rate of change of a function with respect to one variable while keeping other variables constant. In the context of vector fields, they allow us to determine how each component of the vector changes independently.In the given example, the vector field is\( \mathbf{F}(x, y) = x \mathbf{i} - y \mathbf{j} \).To find the divergence, we took the partial derivatives:
- The partial derivative of \( P(x, y) = x \) with respect to \( x \) is \( \frac{\partial P}{\partial x} = 1 \), indicating that \( P \) changes at a uniform rate of 1 as \( x \) changes.
- The partial derivative of \( Q(x, y) = -y \) with respect to \( y \) is \( \frac{\partial Q}{\partial y} = -1 \), indicating that \( Q \) changes at a uniform rate of -1 as \( y \) changes.
Scalar Measure
Divergence in a vector field is an example of a scalar measure. It quantifies how a vector field converges or diverges at a point. Depending on its value, divergence indicates the presence or absence of sources or sinks in the field.The formula for divergence in a 2D field is \[ abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} \]where you sum up the partial derivatives of each vector component.In our example:
- The contribution to divergence from \( P(x, y) = x \) is \( \frac{\partial P}{\partial x} = 1 \).
- The contribution from \( Q(x, y) = -y \) is \( \frac{\partial Q}{\partial y} = -1 \).
- Thus, \( abla \cdot \mathbf{F} = 1 + (-1) = 0 \), leading to a divergence of 0.
Other exercises in this chapter
Problem 226
Find the divergence of \(\mathbf{F}\). $$ \mathbf{F}(x, y, z)=(x-y) \mathbf{i}+(y-z) \mathbf{j}+(z-x) \mathbf{k} $$
View solution Problem 227
Find the divergence of \(\mathbf{F}\). $$ \mathbf{F}(x, y)=\frac{x}{\sqrt{x^{2}+y^{2}}} \mathbf{i}+\frac{y}{\sqrt{x^{2}+y^{2}}} \mathbf{j} $$
View solution Problem 229
Find the divergence of \(\mathbf{F}\). \(\mathbf{F}(x, y, z)=a x \mathbf{i}+b y \mathbf{j}+c \mathbf{k}\) for constants \(a, b, c\)
View solution Problem 230
Find the divergence of \(\mathbf{F}\). $$ \mathbf{F}(x, y, z)=x y z \mathbf{i}+x^{2} y^{2} z^{2} \mathbf{j}+y^{2} z^{3} \mathbf{k} $$
View solution