Problem 228
Question
Find \(\frac{d y}{d x}\) for each function. $$ y=\left(3 x^{2}+3 x-1\right)^{4} $$
Step-by-Step Solution
Verified Answer
\( \frac{dy}{dx} = 4(3x^2 + 3x - 1)^3 (6x + 3) \).
1Step 1: Identify the Function Structure
The given function is \( y = (3x^2 + 3x - 1)^4 \). It is of the form \((u(x))^n\) where \(u(x) = 3x^2 + 3x - 1\) and \(n = 4\).
2Step 2: Apply the Chain Rule
To find \( \frac{dy}{dx} \), apply the chain rule: \( \frac{dy}{dx} = n \cdot (u(x))^{n-1} \cdot \frac{du}{dx} \). Here, \( n = 4 \) and \( u(x) = 3x^2 + 3x - 1 \).
3Step 3: Compute the Derivative \( \frac{du}{dx} \)
Calculate the derivative of \( u(x) = 3x^2 + 3x - 1 \). Use the power rule on each term:- \( \frac{d}{dx}[3x^2] = 6x \)- \( \frac{d}{dx}[3x] = 3 \)- \( \frac{d}{dx}[-1] = 0 \)Thus, \( \frac{du}{dx} = 6x + 3 \).
4Step 4: Substitute and Simplify
Substitute \( n = 4 \), \( u(x) = 3x^2 + 3x - 1 \), and \( \frac{du}{dx} = 6x + 3 \) into the chain rule formula: \[ \frac{dy}{dx} = 4 \cdot (3x^2 + 3x - 1)^3 \cdot (6x + 3) \] Thus, the derivative \( \frac{dy}{dx} \) equals \( 4(3x^2 + 3x - 1)^3 (6x + 3) \).
Key Concepts
Chain RulePower RuleDerivative of a Polynomial
Chain Rule
The chain rule is a fundamental rule in calculus for finding the derivative of a composite function. A composite function is a function that is made of two or more functions. The chain rule essentially tells us how to differentiate these types of functions by breaking them into their constituent parts.
To apply the chain rule, you should:
- Identify the outer function and the inner function. In the given problem, the outer function is ((u(x))^4 and the inner function is 3x^2 + 3x - 1.
- Find the derivative of the outer function. Keep the inner function as it is for now.
- Multiply the result by the derivative of the inner function.
Power Rule
The power rule is another key concept in differentiation, providing a quick method for finding the derivative of functions of the form
x^n, where
is a constant exponent.
The power rule formula is simple:
- If f(x) = x^n, then the derivative, f'(x), is nx^{n-1}.
- For each term in the function, multiply the coefficient by the exponent.
- Subtract one from the exponent to find the new degree of the term.
Derivative of a Polynomial
Polynomials are algebraic expressions made up of terms consisting of variables raised to whole number powers and coefficients. The process of differentiating a polynomial involves applying the power rule to each term separately.
In our example, the polynomial
3x^2 + 3x - 1 includes three terms:
- 3x^2, whose derivative is 6x,
- 3x, whose derivative is simply 3,
- and -1, which is a constant and its derivative is 0.
Other exercises in this chapter
Problem 227
For the following exercise, a. decompose each function in the form \(y=f(u)\) and \(u=g(x),\) and b. find \(\frac{d y}{d x}\) as a function of \(x\). $$ y=-6 \s
View solution Problem 228
For the following exercises, find \(\frac{d y}{d x}\) for each function. $$y=\left(3 x^{2}+3 x-1\right)^{4}$$
View solution Problem 229
For the following exercises, find \(\frac{d y}{d x}\) for each function. $$y=(5-2 x)^{-2}$$
View solution Problem 229
Find \(\frac{d y}{d x}\) for each function. $$ y=(5-2 x)^{-2} $$
View solution