Problem 221
Question
For the following exercises, use reference angles to evaluate the expression. If \(\sin t=\frac{\sqrt{2}}{2}, \quad\) what is the \(\sin (-t) ?\)
Step-by-Step Solution
Verified Answer
\( \sin(-t) = -\frac{\sqrt{2}}{2} \)
1Step 1: Understand the Given Information
We are given that \( \sin t = \frac{\sqrt{2}}{2} \). This value corresponds to a well-known angle in the unit circle. Recall that \( \sin \frac{\pi}{4} = \frac{\sqrt{2}}{2} \). Thus, \( t \) could correspond to the angle \( \frac{\pi}{4} \) or any other angle with this sine value in other quadrants.
2Step 2: Consider the Property of Sine Function
The sine function is odd, meaning that \( \sin(-x) = -\sin(x) \) for any angle \( x \). Therefore, \( \sin(-t) = -\sin(t) \).
3Step 3: Apply the Property to Find \( \sin(-t) \)
Using the odd function property of sine, substitute the value of \( \sin t \): \( \sin(-t) = -\sin(t) = -\frac{\sqrt{2}}{2} \).
4Step 4: Interpret the Result
The result \( \sin(-t) = -\frac{\sqrt{2}}{2} \) indicates that the sine of \( -t \) is simply the negative of the sine of \( t \), due to the odd symmetry of the sine function.
Key Concepts
Reference AnglesUnit CircleOdd Functions
Reference Angles
A reference angle is the smallest angle that a given angle makes with the x-axis. It is always a positive angle and is used to simplify the process of finding trigonometric values of any angle. The idea behind reference angles helps us to work within the familiar 0 to \( \frac{\pi}{2} \) (or 0 to 90 degrees) range, making calculations easier.
Consider this:
Consider this:
- To find a reference angle, determine how far the given angle is from the nearest x-axis.
- If the angle is in the first quadrant, the reference angle is the angle itself.
- In the second quadrant, subtract the angle from \( \pi \).
- In the third quadrant, subtract \( \pi \) from the angle.
- In the fourth quadrant, subtract the angle from \( 2\pi \).
Unit Circle
The unit circle is a crucial concept in trigonometry and calculus. It is a circle in the coordinate plane with a center at the origin (0,0) and a radius of 1. This makes it a perfect tool for understanding how the trigonometric functions work, especially sine and cosine.
On the unit circle:
Recognizing patterns on the unit circle allows us to solve trigonometric problems efficiently and provides a visual way to understand angles and their reference angles.
On the unit circle:
- The x-coordinate of a point gives the cosine of the angle.
- The y-coordinate gives the sine of the angle.
- A positive rotation moves counterclockwise from the positive x-axis, while a negative rotation goes clockwise.
Recognizing patterns on the unit circle allows us to solve trigonometric problems efficiently and provides a visual way to understand angles and their reference angles.
Odd Functions
Odd functions are special types of functions in mathematics where \( f(-x) = -f(x) \) holds true for all x in the function's domain. This property manifests as symmetry about the origin on the graph.
The sine function, \( \sin(x) \), is a classic example of an odd function. It means that for every pair \( (t, -t) \), the values of \( \sin(t) \) and \( \sin(-t) \) are opposites; for instance, if \( \sin t = \frac{\sqrt{2}}{2} \), then \( \sin(-t) = -\frac{\sqrt{2}}{2} \).
This symmetry simplifies calculations, especially in solving trigonometric identities and equations, because flipping the sign of the angle simply flips the sign of the sine value.
The sine function, \( \sin(x) \), is a classic example of an odd function. It means that for every pair \( (t, -t) \), the values of \( \sin(t) \) and \( \sin(-t) \) are opposites; for instance, if \( \sin t = \frac{\sqrt{2}}{2} \), then \( \sin(-t) = -\frac{\sqrt{2}}{2} \).
This symmetry simplifies calculations, especially in solving trigonometric identities and equations, because flipping the sign of the angle simply flips the sign of the sine value.
Other exercises in this chapter
Problem 218
For the following exercises, use reference angles to evaluate the expression. If \(\tan t=\frac{12}{5},\) and \(0 \leq t
View solution Problem 219
For the following exercises, use reference angles to evaluate the expression. If \(\sin t=\frac{\sqrt{3}}{2}\) and \(\cos t=\frac{1}{2},\) find \(\sec t, \csc t
View solution Problem 222
For the following exercises, use reference angles to evaluate the expression. If \(\cos t=\frac{1}{2}, \quad\) what is the \(\cos (-t) ?\)
View solution Problem 223
For the following exercises, use reference angles to evaluate the expression. If \(\sec t=3.1, \quad\) what is the \(\sec (-t) ?\)
View solution