Problem 22
Question
What would be the product formed when 1-bromo-3-chlorocyclobutane reacts with two equivalents of metallic sodium in ether?
Step-by-Step Solution
Verified Answer
The product is bicyclo[1.1.0]butane.
1Step 1: Understand The Reaction Type
The reaction involves 1-bromo-3-chlorocyclobutane and metallic sodium in ether. This is a typical setup for a Wurtz reaction, where two halides react with sodium to form an alkane.
2Step 2: Identify the Halides
1-bromo-3-chlorocyclobutane contains two halides: a bromine at the 1-position and a chlorine at the 3-position. Both of these groups can participate in the Wurtz reaction.
3Step 3: Determine The Bond Formation
In a Wurtz reaction, the sodium metal provides electrons to create radicals from the halide positions. These radicals then couple to form new carbon-carbon bonds. Here, the bromide and chloride leave their respective carbons, allowing a bond to form between these carbons.
4Step 4: Consider Intermediate Alkane Formation
The resulting radical coupling in this scenario forms a cyclobutane with an additional internal carbon bond between the 1st and 3rd positions. However, since the reaction proceeds with two molecules, two cyclobutane rings form a single ring.
5Step 5: Identify The Final Product
The result of the reaction is the formation of a bicyclic hydrocarbon. Specifically, the fusion of the cyclobutanes leads to the formation of bicyclo[1.1.0]butane, a highly strained compound.
Key Concepts
1-bromo-3-chlorocyclobutanemetallic sodiumorganic synthesisbicyclic hydrocarbons
1-bromo-3-chlorocyclobutane
1-bromo-3-chlorocyclobutane is an organic compound that serves as an ideal starting material in the Wurtz reaction. This molecule is a cyclobutane ring, which consists of a square arrangement of carbon atoms, adorned with two distinct halogen atoms: a bromine and a chlorine.
- The bromine atom is located at the 1-position.
- The chlorine atom resides at the 3-position.
metallic sodium
Metallic sodium is a soft, silver-white metallic element that's known for its strong reducing properties.
- In organic chemistry, sodium is valued for its ability to donate electrons.
- These electrons are essential in breaking halogen-carbon bonds through the generation of radicals.
organic synthesis
Organic synthesis is a pivotal process in chemistry focused on constructing new organic molecules. In the Wurtz reaction, this synthesis allows for the formation of complex structures from simpler starting materials like 1-bromo-3-chlorocyclobutane.
- This reaction exemplifies how simple transformations can lead to significant structural changes.
- The formation of new carbon-carbon bonds is a cornerstone of synthesizing new organic molecules.
bicyclic hydrocarbons
Bicyclic hydrocarbons are organic compounds containing two interconnected rings of carbon atoms. They often have interesting chemical properties due to the inherent strain and stability of the bonds within the rings.
- The product of the Wurtz reaction involving 1-bromo-3-chlorocyclobutane is bicyclo[1.1.0]butane.
- This compound's structure includes two cyclobutane rings sharing two adjacent carbon atoms, forming a unique bicyclic structure.
Other exercises in this chapter
Problem 19
The order of reactivity of the given haloalkanes towards nucleophile is : (a) \(\mathrm{RI}>\mathrm{RBr}>\mathrm{KCl}\) (b) \(\mathrm{RCl}>\mathrm{RBr}>\mathrm{
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