Problem 22
Question
We can find an equation of a circle if we know the coordinates of the endpoints of a diameter of the circle. First, find the midpoint of the diameter, which is the center of the circle. Then find the radius which is the distance from the center to either endpoint of the diameter. Finally, use the center-radius form to find the equation. Find the center-radius form for each circle having the given endpoints of a diameter. $$(-4,5) \text { and }(6,-9)$$
Step-by-Step Solution
Verified Answer
The equation of the circle is \((x-1)^2 + (y+2)^2 = 74\).
1Step 1: Finding the Center of the Circle
The center of the circle is the midpoint of the diameter. To find the midpoint between the two given endpoints, \((-4,5)\) and \((6,-9)\), use the midpoint formula: \(M = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\). Substituting the given values, \(M = \left(\frac{-4+6}{2}, \frac{5-9}{2}\right) = (1, -2)\). So, \((1, -2)\) is the center of the circle.
2Step 2: Calculating the Radius
To find the radius, calculate the distance from the center \((1, -2)\) to one of the endpoints of the diameter, say \((-4, 5)\), using the distance formula: \(r = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\). Therefore, \(r = \sqrt{((-4 - 1)^2 + (5 + 2)^2)} \). Solving, \(r = \sqrt{(25 + 49)} = \sqrt{74}\). So, the radius is \(\sqrt{74}\).
3Step 3: Writing the Equation in Center-Radius Form
The equation for a circle in center-radius form is \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius. From previous steps, \((h, k) = (1, -2)\) and \(r = \sqrt{74}\). Therefore, the equation of the circle is \((x-1)^2 + (y+2)^2 = 74\).
Key Concepts
Midpoint FormulaCenter-Radius FormDistance Formula
Midpoint Formula
The midpoint formula is a convenient tool to find the center point between two endpoints. In this exercise, it helps us find the center of the circle, which is crucial for determining the circle's equation. The formula is given by:\[ M = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right) \] Where
- \(x_1\) and \(y_1\) are the coordinates of the first endpoint.
- \(x_2\) and \(y_2\) are the coordinates of the second endpoint.
Center-Radius Form
The center-radius form of a circle is an expression that specifies the equation of the circle using its center and radius. This form is expressed as:\[ (x-h)^2 + (y-k)^2 = r^2 \] Where
- \((h, k)\) is the center of the circle.
- \(r\) is the radius.
Distance Formula
To find the radius of the circle, which is the distance from the center to a point on the circle, we use the distance formula. The formula is invaluable in this scenario for determining how far apart two points in a plane are:\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Here,
- \(x_1\) and \(y_1\) are coordinates of one point.
- \(x_2\) and \(y_2\) are coordinates of the second point.
Other exercises in this chapter
Problem 22
Graph each ellipse by hand. Give the domain and range. Give the foci in Exercises \(11-14\) and identify the center in Exercises \(17-22 .\) Do not use a calcul
View solution Problem 22
The equation of a conic section is given in a familiar form. Identify the type of graph (if any) that each equation has, without actually graphing. See the summ
View solution Problem 23
Use a graphing calculator to generate the curve over the interval for the parameter \(t\), in the window specified. Then find a rectangular equation for the cur
View solution Problem 23
Find an equation for each ellipse. \(x\) -intercepts \((\pm 4,0) ;\) foci \((\pm 2,0)\)
View solution