Problem 22
Question
Use the laws of logarithms to expand and simplify the expression. $$\log x\left(x^{2}+1\right)^{-1 / 2}$$
Step-by-Step Solution
Verified Answer
The expanded and simplified expression for \(\log x\left(x^{2}+1\right)^{-\frac{1}{2}}\) is \(\log x + \frac{1}{2} \log\left(x^{2}+1\right)\).
1Step 1: Apply the Power Rule
We have the expression \(\log x(x^{2}+1)^{-\frac{1}{2}}\). First, let's apply the Power Rule to the second factor, \((x^{2}+1)^{-\frac{1}{2}}\), to rewrite the expression:
\(\log x\left[\left(x^{2}+1\right)^{-\frac{1}{2}}\right] = \log x[-\frac{1}{2}\log\left(x^{2}+1\right)]\)
Now our expression looks like \(\log x[-\frac{1}{2}\log\left(x^{2}+1\right)]\)
2Step 2: Apply the Product Rule
Next, let's apply the Product Rule to the two logarithms. This rule states that the logarithm of a product is equal to the sum of the logarithms of its factors.
\(\log x[-\frac{1}{2}\log\left(x^{2}+1\right)] = \log x - \left(-\frac{1}{node2} \log\left(x^{2}+1\right)\right)\)
Now our expression looks like \(\log x + \frac{1}{2} \log\left(x^{2}+1\right)\)
3Step 3: Simplification
The expression is now simplified and expanded as per the logarithmic properties discussed earlier.
\(\log x\left(x^{2}+1\right)^{-\frac{1}{2}}\) = \(\log x + \frac{1}{2} \log\left(x^{2}+1\right)\)
So, the expanded and simplified expression is \(\log x + \frac{1}{2} \log\left(x^{2}+1\right)\).
Key Concepts
Power Rule in LogarithmsUnderstanding the Product RuleLogarithmic Properties at Work
Power Rule in Logarithms
The Power Rule is a fundamental logarithmic concept that helps us simplify expressions where variables are raised to powers within logarithms.
- This rule states that \[ ext{If } y = b^x, ext{ then } \ ext{log}_b(y^n) = n imes ext{log}_b(y). \]
- Simply put, exponents in the arguments of a logarithm can be pulled out front as a multiplier.
Understanding the Product Rule
The Product Rule is another key feature in handling logarithmic expressions, particularly when dealing with products within a logarithm.
- This rule states that\[ ext{log}_b(m imes n) = ext{log}_b(m) + ext{log}_b(n). \]
- Essentially, the logarithm of a product is the sum of the logarithms of its individual factors.
Logarithmic Properties at Work
To effectively expand and simplify expressions involving logarithms, understanding various logarithmic properties is crucial. These properties help break down complex expressions systematically into manageable forms.
- We have already discussed the Power Rule and the Product Rule, which are integral to our problem.
- Other useful properties include the Quotient Rule, \[ \text{log}_b\left(\frac{m}{n}\right) = \text{log}_b(m) - \text{log}_b(n), \]which helps handle divisions in logarithms, though not directly used here.
- The Change of Base Formula might also come handy when converting logarithms to different bases, stated as\[ \text{log}_b(a) = \frac{\text{log}_c(a)}{\text{log}_c(b)}, \]useful for simplifying calculations in multi-base logarithms.
Other exercises in this chapter
Problem 21
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