Problem 22
Question
The Sacramento City Council recently adopted a law to reduce the allowed sound intensity level of the much despised leaf blowers from their current level of about 95 \(\mathrm{dB}\) to 70 \(\mathrm{dB}\) . With the new law, what is the ratio of the new allowed intensity to the previously allowed intensity?
Step-by-Step Solution
Verified Answer
The ratio of the new intensity to the old intensity is approximately 0.0032.
1Step 1: Understanding Decibel Scale
The decibel (dB) scale is a logarithmic scale used to measure sound intensity. A change of 10 dB represents a tenfold change in intensity.
2Step 2: Finding the Intensity Levels
The initial intensity level is 95 dB, and the reduced intensity level is 70 dB. We need to convert these decibel levels to their corresponding intensity levels.
3Step 3: Calculating Intensity from Decibels
The formula to convert decibels to intensity is: \( I = 10^{(L/10)} \), where \(L\) is the level in decibels. Thus, the initial intensity \( I_1 = 10^{(95/10)} \) and the new intensity \( I_2 = 10^{(70/10)} \).
4Step 4: Simplifying the Ratios
Calculate \( I_1 = 10^{9.5} \) and \( I_2 = 10^{7} \). Thus, the ratio \( \frac{I_2}{I_1} = \frac{10^7}{10^{9.5}} \).
5Step 5: Simplifying the Final Expression
Use the laws of exponents to simplify the fraction: \( \frac{10^7}{10^{9.5}} = 10^{7-9.5} = 10^{-2.5} \).
6Step 6: Converting to a Decimal Number
Calculate \(10^{-2.5}\) using a calculator. This results in approximately \(0.0032\).
Key Concepts
Decibel ScaleLogarithmic ScaleExponents in Physics
Decibel Scale
The decibel scale is a critical concept when working with sound intensity. It's a unit of measurement used to express the ratio of two values of a physical quantity, particularly power or intensity. The decibel scale is logarithmic. This means each increment of 10 dB represents a tenfold change in intensity.
For example:
For example:
- A sound that is 10 dB higher than another sound is ten times more intense.
- A sound 20 dB higher is 100 times more intense.
- In our exercise, reducing the sound intensity from 95 dB to 70 dB involves significant reduction, showcasing the effectiveness of the logarithmic scale in representing large variations in intensity levels.
Logarithmic Scale
A logarithmic scale is crucial in many scientific disciplines, including physics, because it can simplify the representation of vastly different numbers. A linear scale would not effectively represent the wide range of sound intensities that exist.
With a logarithmic scale:
With a logarithmic scale:
- Each step on the scale is a constant factor above or below the previous step. For example, with base-10 logarithms, each step up is a tenfold increase.
- This makes it much easier to comprehend changes in sound intensity, which often involve orders of magnitude changes.
Exponents in Physics
Exponents are a fundamental concept in physics and maths, facilitating the representation and calculation of very large or very small numbers. In the exercise to find the sound intensity ratio, exponents play a key role in simplification.
Consider the following:
Consider the following:
- When calculating intensity from decibels, the formula used is often represented in terms of powers of ten, e.g., \( I = 10^{(L/10)} \).
- Using the laws of exponents, significant simplifications can occur, streamlining complex calculations.
For instance, the ratio \( \frac{10^7}{10^{9.5}} \) simplifies to \( 10^{-2.5} \) using properties like \( a^m/a^n = a^{m-n} \).
Other exercises in this chapter
Problem 19
For a person with normal hearing, the faintest sound that can be heard at a frequency of 400 \(\mathrm{Hz}\) has a pressure amplitude of about \(6.0 \times 10^{
View solution Problem 20
The intensity due to a number of independent sound sources is the sum of the individual intensities. (a) When four quadruplets cry simultaneously, how many deci
View solution Problem 23
(a) By what factor must the sound intensity be increased to raise the sound intensity level by 13.0 dB? (b) Explain why you don't need to know the original soun
View solution Problem 24
The fundamental frequency of a pipe that is open at both ends is 594 Hz (a) How long is this pipe? If one end is now closed, find (b) the wavelength and (c) the
View solution