Problem 22
Question
The positive integer which is just greater than \((1+0.0001)^{1000}\) is (A) 3 (B) 4 (C) 5 (D) 2
Step-by-Step Solution
Verified Answer
2
1Step 1: Understand the Expression
The expression we need to evaluate is \((1 + 0.0001)^{1000}\). This involves calculating a power of a number slightly greater than 1.
2Step 2: Approximate Using the Binomial Theorem
For small \( x \), \( (1+x)^n \approx 1+nx \) when \( x \) is very small. Here, \( x = 0.0001 \) and \( n = 1000 \). Thus, we approximate: \((1 + 0.0001)^{1000} \approx 1 + 1000 \cdot 0.0001 = 1 + 0.1 = 1.1.\)
3Step 3: Determine the Nearest Integer Greater Than the Approximation
The calculation yields \( 1 + 0.1 = 1.1 \). The smallest integer greater than 1.1 is 2.
4Step 4: Verify Feasibility of Other Options
Check that the approximation is reasonable: for \( (1 + 0.0001)^{1000} \) to be closer to 3, 4, or 5, the approximation would have needed to be significantly higher than 1.1, which is not the case here.
Key Concepts
ExponentiationApproximationPositive Integer
Exponentiation
Exponentiation is a fundamental mathematical operation where a number, called the base, is multiplied by itself a certain number of times. This number of times is given by the power, or the exponent. For instance, in the expression \( (1 + 0.0001)^{1000} \), 1.0001 is the base, and 1000 is the exponent.
- The process of exponentiation can lead to rapid growth of the result, depending on how large the exponent is.
- When the base is a number slightly greater than 1, as in the exercise, the growth can be modest, especially for large exponents.
Approximation
Approximation is a technique used to find a value that is close enough to the right answer, often within a tolerance that is acceptable for practical purposes. In mathematics, when dealing with complex calculations, approximations can simplify the process significantly.
For example, using the Binomial Theorem, we approximate the value of expressions like \((1+x)^n\) when \(x\) is small. The theorem states that:
For example, using the Binomial Theorem, we approximate the value of expressions like \((1+x)^n\) when \(x\) is small. The theorem states that:
- \((1+x)^n \approx 1+nx\) when \(x\) is very close to zero.
- This simplification works well when \(n\) is large and \(x\) is very small, as it is in our exercise where \(x = 0.0001\) and \(n = 1000\).
Positive Integer
A positive integer is any whole number greater than zero. This set of numbers includes 1, 2, 3, and so on. In mathematical contexts, especially when working with approximations and series, identifying a positive integer that's nearest or convenient to an estimated value is a common task.
- In our problem, after approximation, the value was approximately 1.1.
- The task was to determine which positive integer is just greater than 1.1.
Other exercises in this chapter
Problem 19
The number of integral terms in the expansion of \((2 \sqrt{5}+\sqrt[6]{7})^{642}\) is (A) 105 (B) 107 (C) 321 (D) 108
View solution Problem 21
The digit at unit's place in the number \(17^{1995}+11^{1995}\) \(-7^{1995}\) is (A) 0 (B) 1 (C) 2 (D) 3
View solution Problem 25
If \(n\) is positive integer and \(k\) is a positive integer not exceeding \(n\), then \(\sum_{k=1}^{n} k^{3}\left(\frac{C_{k}}{C_{k-1}}\right)^{2}\), where \(C
View solution Problem 26
If the fourth term in the expansion of \(\left(\sqrt{\frac{1}{x^{\log x+1}}}+x^{1 / 12}\right)^{6}\) is equal to 200 and \(x>1\), then \(x\) is equal to (A) \(1
View solution