Problem 22
Question
The brown ring complex compound is formulated as \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right] \mathrm{SO}_{4} .\) The oxidation state of iron in the compound is (a) 1 (b) 2 (c) 3 (d) 0
Step-by-Step Solution
Verified Answer
The oxidation state of iron in the compound is 2.
1Step 1: Understanding the Ligands
The compound given is \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{NO}\right] \mathrm{SO}_{4} \). This is a coordination complex with \(\mathrm{H}_{2}\mathrm{O}\) and \(\mathrm{NO}\) as ligands. \(\mathrm{H}_{2}\mathrm{O}\) is a neutral ligand, and \(\mathrm{NO}\) can vary in its oxidation state (nitrosyl ligand can be either \(\mathrm{NO}^{+}\), \(\mathrm{NO}\)\(\bullet\) or \(\mathrm{NO}^{-}\)). In many complexes, \(\mathrm{NO}\) is treated as \(\mathrm{NO}^{+}\) with a charge of +1.
2Step 2: Analyzing Sulfate
The \(\mathrm{SO}_{4}^{2-}\) is the counterion, which carries a -2 charge. Since the compound is electrically neutral, the charges of the complex and the \(\mathrm{SO}_{4}\) have to balance each other.
3Step 3: Calculating the Charge on the Complex
Given that \(\mathrm{SO}_{4}^{2-}\) carries a -2 charge, the coordination complex \([\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{NO}]\) must carry a +2 charge to balance the sulfate ion. The coordinated ligands \(\mathrm{H}_{2}\mathrm{O}\) are neutral and do not add to the positive charge.
4Step 4: Determining the Oxidation State of Iron
Assuming \(\mathrm{NO}^{+}\) contributes +1 charge, and the water ligands being neutral, the charge balance equation becomes: \(\text{charge of Fe} + 1 = +2\). Solving this gives the oxidation state of iron: \(\mathrm{Fe}^{2+}\).
5Step 5: Final Conclusion
Since the calculations show that Fe has an oxidation state of +2, option (b) is correct.
Key Concepts
Brown Ring ComplexOxidation StateCoordination ComplexLigands in Chemistry
Brown Ring Complex
The brown ring complex is a fascinating example of a coordination compound. It is often used in qualitative analysis to detect the presence of nitrate ions in solution. The complex is represented by the formula \( \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{NO}\right] \mathrm{SO}_{4} \), which showcases how iron forms a coordination sphere with various ligands. This coordination allows for the formation of a stable compound, notable for its distinctive brown color when nitrate ions are present.
- In these types of compounds, the metal center, which is iron (Fe) in the brown ring complex, is surrounded by a certain number of molecules or ions, known as ligands.
- The formation process is often demonstrated through the reaction of iron sulfate with a solution that has nitrate ions under acidic conditions.
Oxidation State
The oxidation state, sometimes referred to as oxidation number, is a critical concept in understanding chemical compounds. It indicates the number of electrons that an atom gains, loses, or appears to use when bonding with other atoms. In coordination chemistry, determining the oxidation state of a metal center, such as iron in the brown ring complex, is essential for understanding the chemistry involved.
For the brown ring complex \( \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{NO}\right] \mathrm{SO}_{4} \), determining the oxidation state involves analyzing the charges of the ligands and counterions:
For the brown ring complex \( \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}\mathrm{NO}\right] \mathrm{SO}_{4} \), determining the oxidation state involves analyzing the charges of the ligands and counterions:
- \(\mathrm{H}_{2}\mathrm{O}\) is a neutral ligand, contributing no charge.
- \(\mathrm{NO}\) is typically treated as \(\mathrm{NO}^{+}\) with a +1 charge.
- The \(\mathrm{SO}_{4}^{2-}\) is a doubly charged ion, acting as a counterbalance in the compound.
Coordination Complex
A coordination complex, also known as a complex compound, refers to a structure in which a central atom, typically a metal, is bonded to surrounding molecules or ions called ligands. These complexes play a pivotal role in various fields, including chemistry, biology, and materials science.
In the case of the brown ring complex, iron is the central metal, surrounded by water and nitrosyl ligands. Here’s why coordination complexes are significant:
In the case of the brown ring complex, iron is the central metal, surrounded by water and nitrosyl ligands. Here’s why coordination complexes are significant:
- They allow metals to form more stable compounds by sharing electrons with ligands.
- Complexes often exhibit unique chemical properties, such as color changes, that can be exploited in chemical assays.
- Coordination complexes are crucial in the development of catalytic systems and biological processes, where they act as enzymes or enzyme mimics.
Ligands in Chemistry
Ligands are ions or molecules that donate a pair of electrons to a metal atom to form a coordination bond. In the realm of coordination chemistry, ligands are diverse and play a crucial role in the formation and stability of coordination complexes.
In the brown ring complex, two types of ligands are present: water (\(\mathrm{H}_{2}\mathrm{O}\)) and nitrosyl (\(\mathrm{NO}\)).
In the brown ring complex, two types of ligands are present: water (\(\mathrm{H}_{2}\mathrm{O}\)) and nitrosyl (\(\mathrm{NO}\)).
- \(\mathrm{H}_{2}\mathrm{O}\) is a neutral ligand, and it forms part of the coordination sphere by donating lone pairs to the iron center without contributing to the overall charge.
- \(\mathrm{NO}\), as a nitrosyl ligand, can adopt different oxidation states, but in this complex, it is often found as \(\mathrm{NO}^{+}\), contributing a +1 charge to the system.
Other exercises in this chapter
Problem 20
In the following reaction \(\mathrm{Cr}(\mathrm{OH})_{3}+\mathrm{OH}^{-}+\mathrm{IO}_{3} \longrightarrow \mathrm{CrO}_{4}^{2-}+\mathrm{H}_{2} \mathrm{O}+\mathrm
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A metal ion \(\mathrm{M}^{3+}\) loses three electrons to produce another cation. The oxidation number of the metal in the cation is (a) \(+3\) (b) \(+4\) (c) \(
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A, B and C have the oxidation numbers of \(+6,-2\) and \(-1\) respectively, the possible molecular formula when these atoms combine will be (a) \(\mathrm{A}_{2}
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