Problem 22
Question
$$ \text { Solve each of the following triangles. } $$ $$ a=0.48 \mathrm{yd}, b=0.63 \mathrm{yd}, c=0.75 \mathrm{yd} $$
Step-by-Step Solution
Verified Answer
The angles of the triangle are approximately \( A = 39.54^\circ \), \( B = 56.61^\circ \), \( C = 83.85^\circ \).
1Step 1: Identify the Type of Triangle
Given the sides \( a = 0.48 \text{ yd} \), \( b = 0.63 \text{ yd} \), and \( c = 0.75 \text{ yd} \), check if these sides form a right triangle using the Pythagorean theorem \( a^2 + b^2 = c^2 \). Calculate: \( a^2 = 0.2304 \), \( b^2 = 0.3969 \), and \( c^2 = 0.5625 \). Add \( a^2 + b^2 = 0.2304 + 0.3969 = 0.6273 \), which is not equal to \( c^2 = 0.5625 \). Therefore, this is not a right triangle.
2Step 2: Use the Law of Cosines
Since this is not a right triangle, we use the Law of Cosines to find one angle. Let's find angle \( C \) first using: \[ c^2 = a^2 + b^2 - 2ab \cos C \].Plugging in the values: \( 0.5625 = 0.2304 + 0.3969 - 2(0.48)(0.63) \cos C \), then solve for \( \cos C \).
3Step 3: Solve for \( \cos C \)
Simplify the equation from Step 2: \( 0.5625 = 0.6273 - 0.6048 \cos C \), rearranging gives: \( 0.6048 \cos C = 0.6273 - 0.5625 \).\( 0.6048 \cos C = 0.0648 \). Thus, \( \cos C = \frac{0.0648}{0.6048} \approx 0.1072 \). Find \( C \) using \( C = \cos^{-1}(0.1072) \approx 83.85^\circ \).
4Step 4: Use the Law of Sines
Once you know angle \( C \), use the Law of Sines to find another angle, \( A \), using: \[ \frac{a}{\sin A} = \frac{c}{\sin C} \] \[ \sin A = \frac{a \sin C}{c} \]Plugging in \( a = 0.48 \), \( c = 0.75 \), and \( C = 83.85^\circ \), find \( \sin C = \sin(83.85^\circ) \approx 0.9952 \).Therefore, \( \sin A = \frac{0.48 \times 0.9952}{0.75} \approx 0.6361 \), and hence \( A \approx \sin^{-1}(0.6361) \approx 39.54^\circ \).
5Step 5: Calculate the Remaining Angle
With angles \( C \approx 83.85^\circ \) and \( A \approx 39.54^\circ \), use the angle sum property of triangles to find angle \( B \):\[ B = 180^\circ - A - C = 180^\circ - 39.54^\circ - 83.85^\circ \approx 56.61^\circ \].
6Step 6: Verify Solution
Use the Law of Sines to verify \( \frac{b}{\sin B} = \frac{c}{\sin C} \)\( \sin B = \sin(56.61^\circ) \approx 0.834 \) \( \frac{0.63}{0.834} \approx \frac{0.75}{0.9952} \)Both are approximately equal, confirming the solution is consistent.
Key Concepts
Pythagorean theoremLaw of CosinesLaw of SinesAngle Sum Property
Pythagorean theorem
The Pythagorean theorem is a fundamental principle used to solve right-angled triangles. It states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. Mathematically, this is expressed as:
The calculated sums, \( a^2 + b^2 = 0.6273 \) and \( c^2 = 0.5625 \), do not match. Thus, this is not a right triangle, and therefore you must use another method, such as the Law of Cosines, to solve it effectively.
- \( a^2 + b^2 = c^2 \)
The calculated sums, \( a^2 + b^2 = 0.6273 \) and \( c^2 = 0.5625 \), do not match. Thus, this is not a right triangle, and therefore you must use another method, such as the Law of Cosines, to solve it effectively.
Law of Cosines
When you are dealing with a non-right triangle, you'll often use the Law of Cosines to find angles or sides. This law relates the lengths of the sides of a triangle to the cosine of one of its angles. Here's how it's formulated:
So, to solve for \( C \), we computed: \( 0.6048 \cos C = 0.0648 \), yielding \( \cos C \approx 0.1072 \). Find the angle using the inverse cosine function to get \( C \approx 83.85^\circ \).
- \( c^2 = a^2 + b^2 - 2ab \cos C \)
So, to solve for \( C \), we computed: \( 0.6048 \cos C = 0.0648 \), yielding \( \cos C \approx 0.1072 \). Find the angle using the inverse cosine function to get \( C \approx 83.85^\circ \).
Law of Sines
After determining an initial angle using the Law of Cosines, the Law of Sines is useful for finding the remaining angles. This law, unlike the Pythagorean theorem, can be applied to any triangle. It states:
- \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \)
- \( \frac{a}{\sin A} = \frac{c}{\sin C} \)
Angle Sum Property
The angle sum property of triangles is a simple yet essential rule stating that the sum of the interior angles of any triangle is always \( 180^\circ \). This property allows us to easily find the unknown angle when two angles are known.
For the current problem, after finding \( A \approx 39.54^\circ \) and \( C \approx 83.85^\circ \), using the angle sum property is straightforward:
Verifying the solution is also made simpler with this tactic, because confirming that the angles add up to \( 180^\circ \) serves as a check for any possible calculation errors earlier in the process.
For the current problem, after finding \( A \approx 39.54^\circ \) and \( C \approx 83.85^\circ \), using the angle sum property is straightforward:
- \( B = 180^\circ - A - C \)
Verifying the solution is also made simpler with this tactic, because confirming that the angles add up to \( 180^\circ \) serves as a check for any possible calculation errors earlier in the process.
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