Problem 22
Question
Solve each equation. \(|x-7|=4\)
Step-by-Step Solution
Verified Answer
The solutions are x = 3 and x = 11.
1Step 1: Understand the Absolute Value
The absolute value equation \(|x-7|=4\) can be interpreted as the distance from \(x-7\) to 0 on the number line being 4.
2Step 2: Set Up Two Potential Equations
Since the absolute value will balance out both positive and negative values, the equation \(|x-7|=4\) can be rewritten as two separate equations: \(x-7 = 4\) and \(x-7 = -4\).
3Step 3: Solve the First Equation
Solve the first equation, \(x-7 = 4\), by adding 7 to both sides: \[x = 4 + 7 \]\[x = 11\].
4Step 4: Solve the Second Equation
Solve the second equation, \(x-7 = -4\), by adding 7 to both sides: \[x = -4 + 7 \]\[x = 3\].
5Step 5: Write the Solution Set
The solution set for \(|x-7|=4\) includes both values of \(x\) found in the previous steps: \(x = 3\) and \(x = 11\). Thus, the solutions are \([3, 11]\).
Key Concepts
Linear EquationsStep-by-Step SolutionsAlgebraic Solutions
Linear Equations
Let's dive into the exciting world of linear equations. Linear equations are one of the building blocks of algebra. A linear equation is any equation that forms a straight line when it is graphed. Its standard form is represented as \(ax + b = c\). Here, \(a\), \(b\), and \(c\) are constants, and \(x\) is the variable. Linear equations appear in different real-world contexts, such as calculating distance, finding rate, or determining a specific point in time. Understanding these helps us solve numerous practical problems. Here’s why understanding linear equations is essential:
- They represent simple relationships between variables.
- We can use them to predict values based on a given input.
- They form the basis for understanding more complex algebraic structures.
Step-by-Step Solutions
When tackling math problems, especially those involving absolute value, following a step-by-step process simplifies the task. Take our example, \(|x-7| = 4\): This involves understanding the concept of absolute value as the distance from zero. First, reframe the equation by considering both positive and negative possibilities. This leads to two equations: \(x-7 = 4\) and \(x-7 = -4\).Solving these structures methodically:
- For \(x-7 = 4\), add 7 to both sides to find \(x = 11\).
- For \(x-7 = -4\), add 7 to both sides to find \(x = 3\).
Algebraic Solutions
Algebraic solutions involve manipulating equations to find unknown values. The focus is on logically reducing and simplifying the problems using algebraic rules until we reach a solution. This process uses properties like addition, subtraction, and multiplication to isolate the variable.With absolute value equations like \(|x-7| = 4\), it's key to remember that this represents a distance on a number line. Thus, you use algebra to convert this into two simpler linear equations. We then solve these to determine all possible values of \(x\). Key points to finding algebraic solutions:
- Isolate the absolute value expression.
- Consider all potential solutions by splitting into two equations.
- Solve these equations by isolating \(x\).
Other exercises in this chapter
Problem 22
Factor each polynomial. $$ 63 x^{3} y^{2}+81 x^{2} y^{4} $$
View solution Problem 22
Factor difference of two squares. \(81 a^{4}-16 b^{2}\)
View solution Problem 22
Let \(A=\\{0,1,2,3,4,5,6\\}, B=\\{4,6,8,10\\}\) \(C=\\{-3,-1,0,1,2\\},\) and \(D=\\{-3,1,2,5,8\\}\) Find each set. $$ A \cup C $$
View solution Problem 22
Solve each equation. Check the result. $$ 5(5-a)=4 a+37-6 a $$
View solution