Problem 22
Question
Solve each equation by using the Square Root Property. \(x^{2}+12 x+36=5\)
Step-by-Step Solution
Verified Answer
Solutions are \(x = \sqrt{5} - 6\) and \(x = -\sqrt{5} - 6\).
1Step 1: Recognize Perfect Square Form
The equation given is \(x^2 + 12x + 36 = 5\). Notice that the left side \(x^2 + 12x + 36\) is a perfect square trinomial because it can be rewritten as \((x + 6)^2\).
2Step 2: Rewrite Equation Using Perfect Square
Rewrite the equation \(x^2 + 12x + 36 = 5\) as \((x + 6)^2 = 5\). This is done by recognizing \(x^2 + 12x + 36\) as \((x + 6)^2\).
3Step 3: Apply Square Root Property
To solve \((x + 6)^2 = 5\), apply the Square Root Property by taking the square root of both sides, which gives \(x + 6 = \sqrt{5}\) or \(x + 6 = -\sqrt{5}\).
4Step 4: Solve for x
Solve the two equations separately. For the first equation, \(x + 6 = \sqrt{5}\), subtract 6 from both sides to get \(x = \sqrt{5} - 6\). For the second equation, \(x + 6 = -\sqrt{5}\), subtract 6 from both sides to get \(x = -\sqrt{5} - 6\). Thus, the solutions are \(x = \sqrt{5} - 6\) and \(x = -\sqrt{5} - 6\).
Key Concepts
Understanding Perfect Square TrinomialsSolving Quadratic Equations Using the Square Root PropertyAlgebraic Manipulation for Solving Equations
Understanding Perfect Square Trinomials
A perfect square trinomial is a special type of quadratic expression that can be factored into a square of a binomial. It takes the form of
- \(a^2 + 2ab + b^2\)
- this can be rewritten as \((a + b)^2\).
Solving Quadratic Equations Using the Square Root Property
Quadratic equations are typically in the form \(ax^2 + bx + c = 0\), and solving them is a fundamental skill in algebra. One effective method is using the Square Root Property, particularly beneficial when the expression is a perfect square trinomial. After rewriting \(x^2 + 12x + 36 = 5\) as \((x + 6)^2 = 5\), we simplify the problem. The Square Root Property states that if \(a^2 = b\), then \(a = \sqrt{b}\) or \(a = -\sqrt{b}\). Applying this property helps us directly solve for x by taking the square root of both sides:
- \((x + 6) = \sqrt{5}\)
- or \((x + 6) = -\sqrt{5}\).
Algebraic Manipulation for Solving Equations
Algebraic manipulation involves various strategies to isolate the variable and solve the equation. In our exercise, once we reached the equations
- \(x + 6 = \sqrt{5}\)
- and \(x + 6 = -\sqrt{5}\).
Other exercises in this chapter
Problem 22
Write each quadratic function in vertex form, if not already in that form. Then identify the vertex, axis of symmetry, and direction of opening. $$ y=\frac{1}{3
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Simplify. $$ \sqrt{125} $$
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Solve each equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are located. $$ -x^{2}+x=-20 $$
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Solve each equation by factoring. Then graph. \(x^{2}-3 x-28=0\)
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