Problem 22
Question
Solve each equation analytically for all complex solutions, giving exact forms in your solution set. Then, graph the left side of the equation as \(y_{1}\) in the suggested viewing window and, using the capabilities of your calculator, support the real solutions. $$\begin{aligned} &9 x^{4}+35 x^{2}-4=0\\\ &[-3,3] \text { by }[-10,100] \end{aligned}$$
Step-by-Step Solution
Verified Answer
Solutions are \(x = \pm\sqrt{\frac{-35 + \sqrt{1441}}{18}}\) and \(x = \pm\sqrt{\frac{-35 - \sqrt{1441}}{18}}\).
1Step 1: Recognize the Equation Type
The given equation \(9x^4 + 35x^2 - 4 = 0\) is a polynomial in \(x\). Notice that \(9x^4\) can be rewritten as \((3x^2)^2\), suggesting this is a quadratic in form of \(u = x^2\). This suggests using substitution.
2Step 2: Substitute to Simplify
Substitute \(u = x^2\) so the equation becomes \(9u^2 + 35u - 4 = 0\). This transforms our quartic equation in \(x\) into a quadratic in \(u\).
3Step 3: Solve the Quadratic Equation
Use the quadratic formula \(u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) with \(a = 9\), \(b = 35\), and \(c = -4\). Calculate the discriminant \(b^2 - 4ac = 35^2 - 4 \times 9 \times (-4) = 1441\). Thus, \(u = \frac{-35 \pm \sqrt{1441}}{18}\).
4Step 4: Find Values of \(u\)
Calculate each value of \(u\): \(u_1 = \frac{-35 + \sqrt{1441}}{18}\) and \(u_2 = \frac{-35 - \sqrt{1441}}{18}\). These values of \(u\) should be simplified to get their exact forms.
5Step 5: Solve for \(x\) with each \(u\) Value
Recall \(u = x^2\) and solve for \(x\). This means for each \(u\) value, we have \(x^2 = u\), leading to \(x = \pm\sqrt{u}\). Substitute \(u_1\) and \(u_2\) to get \(x = \pm\sqrt{\frac{-35 + \sqrt{1441}}{18}}\) and \(x = \pm\sqrt{\frac{-35 - \sqrt{1441}}{18}}\).
6Step 6: Verify and Graph Real Solutions
Graph \(y_1 = 9x^4 + 35x^2 - 4\) using the window \([-3,3]\) for \(x\) and \([-10,100]\) for \(y\). Only consider real parts from the solutions found. Use a calculator to confirm the intersection with the x-axis (real solutions).
Key Concepts
Polynomial EquationsQuadratic FormsGraphing Calculators
Polynomial Equations
A polynomial equation is any equation that involves an expression made up of variables raised to various powers, added or subtracted together, and sometimes multiplied by constant coefficients. For example, the polynomial equation provided in the exercise is a quartic, or fourth-degree polynomial, written as:
- \(9x^4 + 35x^2 - 4 = 0\)
- \(9u^2 + 35u - 4 = 0\)
Quadratic Forms
A quadratic form is a specific type of polynomial where the highest power of the variable is two. This form is typically much easier to solve than higher-degree polynomials. In our exercise, once we applied the substitution \(u = x^2\), we changed our quartic equation into a quadratic equation:
- \(9u^2 + 35u - 4 = 0\)
- \(u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Graphing Calculators
A graphing calculator is a powerful tool that can assist in solving equations by visualizing them. It allows for plotting functions to check for real solutions and provides insight into the behavior of polynomial equations. In this particular exercise, you would graph the left side of the equation:
- \(y_{1} = 9x^4 + 35x^2 - 4\)
- \([-3, 3]\) for the x-axis,
- \([-10, 100]\) for the y-axis
Other exercises in this chapter
Problem 22
Find a polynomial function \(P(x)\) having leading coefficient \(1,\) least possible degree, real coefficients, and the given zeros. $$1+\sqrt{2}, 1-\sqrt{2}, \
View solution Problem 22
Write each number in simplest form, without a negative radicand. $$\sqrt{-169}$$
View solution Problem 22
Solve each equation. For equations with real solutions, support your answers graphically. $$(4 x+1)^{2}=20$$
View solution Problem 22
Find each quotient when \(P(x)\) is divided by the binomial following it. $$P(x)=x^{4}+4 x^{3}+2 x^{2}+9 x+4 ; \quad x+4$$
View solution