Problem 22
Question
Solve and graph the solution set. In addition, present the solution set in interval notation. $$ -8 x+1 \leq 29 $$
Step-by-Step Solution
Verified Answer
The solution is \( x \geq -3.5 \), or in interval notation \([-3.5, \infty)\).
1Step 1: Isolate the Variable Term
Start with the inequality \[ -8x + 1 \leq 29 \]Subtract 1 from both sides to isolate the term with the variable:\[ -8x + 1 - 1 \leq 29 - 1 \]This simplifies to:\[ -8x \leq 28 \]
2Step 2: Solve for the Variable
To solve for \( x \), divide both sides of the inequality by \( -8 \). Remember, when you divide an inequality by a negative number, you must reverse the inequality sign:\[ x \geq -\frac{28}{8} \]Simplify the fraction:\[ x \geq -\frac{7}{2} \] or \( x \geq -3.5 \).
3Step 3: Express the Solution Set in Interval Notation
The solution \( x \geq -3.5 \) means that \( x \) is any number greater than or equal to \(-3.5\). In interval notation, this is expressed as:\[ [-3.5, \infty) \]
4Step 4: Graph the Solution Set
To graph the solution \( x \geq -3.5 \), draw a number line. Place a solid circle or closed bracket at \(-3.5\) to indicate that \(-3.5\) is included in the solution set. Draw an arrow going to the right, indicating all numbers greater than \(-3.5\) are part of the solution.
Key Concepts
Interval NotationGraphing InequalitiesVariable Isolation
Interval Notation
Interval notation is a concise way of expressing a range of values. It is especially useful in inequalities because it clearly shows the boundary values and whether they are included or excluded. In this exercise, after solving the inequality, we concluded that \( x \geq -3.5 \).
Here's how interval notation works for this example:
Here's how interval notation works for this example:
- **Square brackets** \([-3.5, \infty)\) indicate that the number \(-3.5\) is included in the solution set.
- **Parentheses** \([-3.5, \infty)\) signify that \(\infty\) is not a real number and thus can't be included, hence the parenthesis.
Graphing Inequalities
Graphing inequalities involves showing our solution on a number line, which provides a visual representation of the set of solutions. For our inequality \(x \geq -3.5\), graphing becomes a straightforward task.
Here's how to graph this inequality:
Here's how to graph this inequality:
- Draw a horizontal line, which represents all possible values for \(x\).
- Locate the number \(-3.5\) on this line.
- Because the inequality is \(\geq\), we will use a **solid circle** at \(-3.5\) to show that \(-3.5\) is included.
- Draw an arrow extending to the right from \(-3.5\) to illustrate that all numbers greater than \(-3.5\) are included.
Variable Isolation
Variable isolation is the process of transforming an equation or inequality to solve for a specific variable. This often involves performing operations that "isolate" the variable on one side of the equation or inequality.
In our case, we started with the inequality \(-8x + 1 \leq 29\). Our goal is to "release" the \(x\) from other operations:
In our case, we started with the inequality \(-8x + 1 \leq 29\). Our goal is to "release" the \(x\) from other operations:
- First, subtract 1 from both sides to remove the constant term, leaving \(-8x \leq 28\).
- Second, divide by \(-8\) to solve for \(x\). Remember, dividing or multiplying by a negative flips the inequality sign, turning it into \(x \geq -3.5\).
Other exercises in this chapter
Problem 21
Evaluate. \(-x+12,\) where \(x=-2\)
View solution Problem 22
Simplify. $$ -34 a-421 b+13 a-17 b $$
View solution Problem 22
Graph all solutions on a number line and give the corresponding interval notation. $$ -34 \leq x \leq 12 $$
View solution Problem 22
Solve. $$ 2 n+13=-35 $$
View solution