Problem 22
Question
Sketch the region in the second quadrant that is inside the cardioid \(\quad r=2+2 \sin \theta\) and outside the cardioid \(r=2+2 \cos \theta\), and find its area.
Step-by-Step Solution
Verified Answer
The area in the second quadrant between these cardioids is \( \frac{1}{2} \int_{\frac{\pi}{2}}^{\frac{3\pi}{4}} \left[ (2+2 \sin \theta)^2 - (2+2 \cos \theta)^2 \right] d\theta \).
1Step 1: Understanding the Problem
We need to sketch the region that is in the second quadrant, which is to the left of the y-axis and above the x-axis, and is inside the cardioid given by\( r = 2 + 2 \sin \theta \) and outside the cardioid \( r = 2 + 2 \cos \theta \). Then, we will find the area of this region.
2Step 2: Plot the Cardioids
The equation \( r = 2 + 2 \sin \theta \) describes a cardioid with the cusp on the positive y-axis. Similarly, \( r = 2 + 2 \cos \theta \) describes another cardioid with the cusp on the positive x-axis. These curves intersect at the origin.
3Step 3: Find Intersection Points
To find where these cardioids intersect, set \( r = 2 + 2 \sin \theta = 2 + 2 \cos \theta \). Solving \( \sin \theta = \cos \theta \) gives \( \theta = \frac{\pi}{4} \) and \( \theta = \frac{5\pi}{4} \). However, in the second quadrant, we consider \( \theta \) from \( \frac{\pi}{2} \) to \( \pi \).
4Step 4: Determine the Limits of Integration
In the second quadrant, for \( \theta \) values from \( \frac{\pi}{2} \) to \( \frac{3\pi}{4} \), \( r = 2 + 2 \sin \theta \) is inside and \( r = 2 + 2 \cos \theta \) is outside. The limits of \( \theta \) become \( \frac{\pi}{2} \) to \( \frac{3\pi}{4} \).
5Step 5: Set Up Integration for Area
The area of the region can be calculated using polar coordinates with the integral \[\frac{1}{2} \int_{\theta_1}^{\theta_2} \left[ (r_{\text{outer}}^2) - (r_{\text{inner}}^2) \right] \, d\theta \]where \( r_{\text{outer}} = 2 + 2 \sin \theta \) and \( r_{\text{inner}} = 2 + 2 \cos \theta \).
6Step 6: Compute the Integral
Calculate the area: \[\frac{1}{2} \int_{\frac{\pi}{2}}^{\frac{3\pi}{4}} \left[ (2 + 2 \sin \theta)^2 - (2 + 2 \cos \theta)^2 \right] \, d\theta.\]This integral can be evaluated by expanding the squares and integrating each term separately.
7Step 7: Evaluate and Simplify
After evaluating the integral, simplify the result to find the total area of the region within the specified boundaries.
Key Concepts
CardioidCalculusIntegrationArea Calculation
Cardioid
A cardioid is a heart-shaped curve, a type of limacon, commonly seen in polar coordinates. They are defined by equations like \( r = a + a \sin \theta \) or \( r = a + a \cos \theta \). This particular shape has a cusp, which is a pointed end. In the context of the exercise, we have two cardioids:
- \( r = 2 + 2 \sin \theta \), with the cusp on the positive y-axis.
- \( r = 2 + 2 \cos \theta \), with the cusp on the positive x-axis.
Calculus
Calculus is fundamental in understanding curves and areas, especially in polar coordinates. It involves two main components: differentiation, which looks at rates of change; and integration, which finds quantities like area or volume.
Integrals are particularly useful when working with irregular shapes like those formed by cardioids, which do not conform to simple geometric formulas for area. Calculus allows us to work with these curves by offering techniques to measure and manipulate their properties, making it an invaluable tool for solving complex spatial problems involving curves.
Integration
Integration is essential to find the area under curves, especially in polar coordinates. In our problem, we use the formula: \[ \frac{1}{2} \int_{\theta_1}^{\theta_2} \left[ (r_{\text{outer}}^2) - (r_{\text{inner}}^2) \right] \, d\theta \]This formula helps in calculating the area between two curves. Here are the steps involved:
- Square the functions: Calculate \((r_{\text{outer}}^2)\) and \((r_{\text{inner}}^2)\) for each cardioid.
- Subtract and integrate: Find the difference between the squared values and integrate over the given limits.
- Halve the result: Since the formula includes \(\frac{1}{2}\), ensure the area reflects the accurate calculation for the polar region.
Area Calculation
Area calculation in polar coordinates can initially appear daunting. However, the process becomes manageable with systematic steps:
- Identify the region: Determine where the two cardioids overlap in the second quadrant. We find this by analyzing the intersections and ensuring the right portion aligns with the polar limits.
- Set the limits properly: Select the correct integration range from \( \frac{\pi}{2} \) to \( \frac{3\pi}{4} \) based on the problem's quadrant constraints.
- Apply the area formula: Use the appropriate area formula to compute the region's size, taking care to subtract the inner cardioid from the outer one.
Other exercises in this chapter
Problem 21
Find the equations of the tangent and the normal lines to the given parabola at the given point. Sketch the parabola, the tangent line, and the normal line. $$
View solution Problem 22
Sketch the graph of the given equation. \(\frac{(x+3)^{2}}{4}+\frac{(y-2)^{2}}{8}=0\)
View solution Problem 22
Find the Cartesian equations of the graphs of the given polar equations. $$ r^{2}-6 r \cos \theta-4 r \sin \theta+9=0 $$
View solution Problem 22
find \(d y / d x\) and \(d^{2} y / d x^{2}\) without eliminating the parameter. $$ x=6 s^{2}, y=-2 s^{3} ; s \neq 0 $$
View solution