Problem 22
Question
Sketch the region bounded by the graphs of the functions and find the area of the region. $$ y=\frac{e^{1 / x}}{x^{2}}, y=0, x=1, x=3 $$
Step-by-Step Solution
Verified Answer
The area of the region bounded by the given curves is \(e^{1/3} - e\).
1Step 1: Plot the Functions
It's important to get a visual understanding of the problem. By plotting the given function \(y=\frac{e^{1 / x}}{x^{2}}\) and the lines \(y=0\), \(x=1\), and \(x=3\), we can observe the region whose area we seek. This region is enclosed by the four bounded entities.
2Step 2: Setup the Integral
Since we are looking for the area bounded by the curves, we set up an integral from 1 to 3 of the function \(\frac{e^{1 / x}}{x^{2}}\) with respect to \(x\). The integral will be \(\int_1^3 \frac{e^{1 / x}}{x^{2}} dx\).
3Step 3: Solve the Integral
We make use of integral calculus to solve the definite integral. Substitution is our best bet in solving this integral. Let's set \(u = 1/x\), then \(du = -1/x^2 dx\) or \( - du = 1/x^2 dx\). Our integral will be \(- \int_{1/3}^{1} e^{u} du\). Now we perform the integration and we get \(-[e^u]_{1/3}^{1}\).
4Step 4: Evaluate the Definite Integral
Evaluating the integral we get \(-[e - e^{1/3}]\).
5Step 5: Simplify the Result
After simplifying, we get the area between the curves as \(e^{1/3} - e\).
Other exercises in this chapter
Problem 21
Use the Log Rule to find the indefinite integral. $$ \int \frac{x^{2}}{x^{3}+1} d x $$
View solution Problem 21
Find the indefinite integral and check the result by differentiation. $$ \int \frac{x-2}{\sqrt{x^{2}-4 x+3}} d x $$
View solution Problem 22
Use the Log Rule to find the indefinite integral. $$ \frac{x}{x^{2}+4} d x $$
View solution Problem 22
Find the indefinite integral and check the result by differentiation. $$ \int \frac{4 x+6}{\left(x^{2}+3 x+7\right)^{3}} d x $$
View solution