Problem 22
Question
Sketch the graph of each function. $$ h(x)=(x+2)^{2}+2 $$
Step-by-Step Solution
Verified Answer
Shift the parabola \(x^2\) 2 units left and 2 units up; vertex is \((-2, 2)\).
1Step 1: Identify the Base Function
The base function for this problem is the quadratic function \( f(x) = x^2 \). This is a simple parabola that opens upwards and has its vertex at the origin (0,0).
2Step 2: Include the Horizontal Shift
The expression \((x + 2)^2\) indicates a horizontal shift. The \(+2\) inside the parentheses means the graph of \(x^2\) will shift 2 units to the left. Thus, the vertex of the parabola moves from (0,0) to (-2,0).
3Step 3: Apply the Vertical Shift
The \(+2\) outside the squared term translates the graph vertically upward by 2 units. Therefore, the vertex, which was at \((-2,0)\) after the horizontal shift, moves to \((-2, 2)\).
4Step 4: Sketch the Graph
With the vertex at \((-2, 2)\), draw a parabola that opens upwards. The horizontal line symmetry of the parabola will be the line \(x = -2\). The graph should be a smooth curve and should maintain the shape of the standard quadratic function.
Key Concepts
Horizontal ShiftVertical ShiftParabola
Horizontal Shift
When dealing with quadratic functions, horizontal shift refers to moving the graph of the function left or right on the coordinate plane. This shift is determined by the term inside the parentheses of the function. For example, in the expression \((x + 2)^2\), the "+2" indicates a horizontal shift. Counterintuitively, a "+" inside the parentheses actually shifts the graph to the left. Therefore, in the function provided, we move the base parabola \(f(x) = x^2\) two units to the left, which updates the vertex from \((0,0)\) to \((-2,0)\).
- The rule is: \( (x + c)^2 \) shifts \( c \) units to the left if \( c \) is positive.
- Conversely, \( (x - c)^2 \) shifts \( c \) units to the right if \( c \) is negative.
Vertical Shift
A vertical shift in a quadratic function moves the graph up or down along the y-axis. This occurs because of a constant added or subtracted from the quadratic expression. In our example, the \(+2\) located outside the squared term \((x + 2)^2\) indicates a vertical shift upwards by 2 units. This moves the entire graph, including the vertex.After we've performed the horizontal shift, the vertex was at \((-2,0)\). Adding the vertical shift means the vertex relocates to \((-2,2)\). Understanding this behavior enables you to predict and draft the graph's new position conveniently:
- A positive constant (e.g., \(+2\)) shifts the graph up.
- A negative constant would move it down.
Parabola
A parabola is the shape that characterizes the graph of a quadratic function. Typically, it's a symmetrical, U-shaped curve that can either open upwards or downwards. The base form of a parabola can be defined by the simple function \(f(x) = x^2\), which opens upwards from the origin point \((0,0)\).For graphing a function such as \(h(x) = (x + 2)^2 + 2\), the tracing of a parabola will be centered around the vertex, which acts like the 'tip' of this graph. In this specific case:
- The vertex is \((-2, 2)\), found after applying horizontal and vertical shifts.
- The parabola opens upward, because the coefficient of \(x^2\) is positive (1 in this case).
- The line of symmetry is the vertical line \(x = -2\), which passes through the vertex.
Other exercises in this chapter
Problem 21
Write an equation of each line. See Examples 3 and \(4 .\) Horizontal; through (-3,1)
View solution Problem 22
Suppose that an object is thrown upward with an initial velocity of 64 feet per second off the edge of a 960 -foot-cliff. Neglecting air resistance, the height
View solution Problem 22
Write an equation of each line. See Examples 3 and \(4 .\) Vertical; through (4,7)
View solution Problem 23
If \(f(x)=\frac{x+8}{2 x-1}\) and \(g(x)=\frac{x-2}{x-5},\) find each function value. $$ f(2) $$
View solution