Problem 22
Question
Sketch the given vector with initial point (4, 3), and find the terminal point. $$\mathbf{u}=\langle- 8,-1\rangle$$
Step-by-Step Solution
Verified Answer
The terminal point of the vector is (-4, 2).
1Step 1: Understand the Components of the Vector
The vector \( \mathbf{u} = \langle -8, -1 \rangle \) has components that tell us how to move from its initial point to find the terminal point. The first component \( -8 \) is a horizontal movement (left), and the second component \( -1 \) is a vertical movement (downwards).
2Step 2: Analyze the Initial Point
The initial point of the vector is given as \( (4, 3) \). This is where the vector starts on the coordinate plane.
3Step 3: Calculate the Terminal Point
Starting from the initial point \( (4, 3) \), apply the components of the vector: move 8 units to the left (subtract 8 from the x-coordinate) and 1 unit downwards (subtract 1 from the y-coordinate). This calculation is done as follows:- New x-coordinate: \( 4 + (-8) = -4 \)- New y-coordinate: \( 3 + (-1) = 2 \)Thus, the terminal point is \( (-4, 2) \).
4Step 4: Sketch the Vector
On a coordinate plane, plot the initial point \( (4, 3) \). From this point, draw an arrow 8 units to the left and 1 unit downward to reach \( (-4, 2) \). This forms the directed line segment representing the vector \( \mathbf{u} \).
Key Concepts
Initial PointTerminal PointCoordinate Plane Movement
Initial Point
In the realm of vector operations, the initial point serves as the anchor or starting position of a vector on a coordinate plane. When dealing with vectors, it's crucial to identify where the movement begins. An initial point is usually presented in terms of coordinates. These are the set of numbers that line up with specific points on the x-axis and y-axis.
For the given exercise, the initial point is clearly identified as \((4, 3)\). This means that before any movement along the vector's path is accounted for, you begin at this exact spot on the plane.
For the given exercise, the initial point is clearly identified as \((4, 3)\). This means that before any movement along the vector's path is accounted for, you begin at this exact spot on the plane.
- The x-coordinate of 4 tells us how far to the right (positive) from the origin the point is.
- The y-coordinate of 3 tells us how high up (positive) from the x-axis the point is.
Terminal Point
The terminal point is where the journey of the vector concludes. After starting at the initial point, the vector moves according to its components and ultimately rests at the terminal point. This is the endpoint, encapsulating how far and in which direction the initial point has been displaced.
To determine the terminal point for the vector \( \mathbf{u} = \langle -8, -1 \rangle \) starting from \((4, 3)\), we apply the vector's components:
To determine the terminal point for the vector \( \mathbf{u} = \langle -8, -1 \rangle \) starting from \((4, 3)\), we apply the vector's components:
- Horizontal Movement: The x-component \(-8\) suggests a leftward movement of 8 units. To calculate: \(4 + (-8) = -4\).
- Vertical Movement: The y-component \(-1\) signifies a downward shift of 1 unit. To calculate: \(3 + (-1) = 2\).
Coordinate Plane Movement
Vectors on a coordinate plane are essentially blueprints of movement described by their components. The coordinate plane is divided into quadrants and serves as a map for measuring shifts in direction and distance.
When analyzing movement through vectors:
When analyzing movement through vectors:
- The x-component tells you about horizontal shifts. Positive values move right; negative values move left.
- The y-component describes vertical moves. Positive values ascend; negative values descend.
Other exercises in this chapter
Problem 22
Express the given vector in terms of the unit vectors i, \(\mathbf{j}\). and \(\mathbf{k}\). $$\left\langle- a, \frac{1}{3} a, 4\right\rangle$$
View solution Problem 22
Find the indicated quantity, assuming \(\mathbf{u}=2 \mathbf{i}+\mathbf{j}, \mathbf{v}=\mathbf{i}-3 \mathbf{j},\) and \(\mathbf{w}=3 \mathbf{i}+4 \mathbf{j}\).
View solution Problem 23
Find the area of the parallelogram determined by the given vectors. $$\mathbf{u}=2 \mathbf{i}-\mathbf{j}+4 \mathbf{k}, \quad \mathbf{v}=\frac{1}{2} \mathbf{i}+2
View solution Problem 23
Find an equation of the plane that passes through the points \(P, Q,\) and \(R\) $$P\left(3, \frac{1}{3},-5\right), \quad Q\left(4, \frac{2}{3},-3\right), \quad
View solution