Problem 22
Question
In \(21-24,\) find, to the nearest tenth, the degree measures of all \(\theta\) in the interval \(0^{\circ} \leq \theta<360^{\circ}\) that make the equation true. $$ 5 \sin \theta-1=1-2 \sin \theta $$
Step-by-Step Solution
Verified Answer
\( \theta \approx 16.6^{\circ} \) and \( \theta \approx 163.4^{\circ} \).
1Step 1: Understand the problem
The problem involves solving for \( \theta \) in the equation \( 5 \sin \theta - 1 = 1 - 2 \sin \theta \) within the interval \( 0^{\circ} \leq \theta < 360^{\circ} \). Our goal is to find the values of \( \theta \) to the nearest tenth of a degree.
2Step 2: Combine like terms
Rewrite the equation by moving all terms involving sine to one side, and constant terms to the other side: \( 5 \sin \theta + 2 \sin \theta = 1 + 1 \). This simplifies to \( 7 \sin \theta = 2 \).
3Step 3: Solve for sine of theta
Divide both sides by 7 to isolate \( \sin \theta \): \( \sin \theta = \frac{2}{7} \).
4Step 4: Calculate reference angle
Find the reference angle by taking the inverse sine: \( \theta_{ref} = \sin^{-1}\left(\frac{2}{7}\right) \approx 16.6^{\circ} \). This angle represents the closest value, assuming \( \theta \) is in the first quadrant.
5Step 5: Determine all possible angle solutions
Since \( \sin \theta \) is positive, \( \theta \) could be in either the first or second quadrant. **First Quadrant:**\( \theta = \theta_{ref} = 16.6^{\circ} \)**Second Quadrant:**\( \theta = 180^{\circ} - \theta_{ref} = 180^{\circ} - 16.6^{\circ} = 163.4^{\circ} \)
Key Concepts
Sine FunctionQuadrants in TrigonometryDegree Measure
Sine Function
The sine function is a fundamental concept in trigonometry. It is often denoted as \( \sin \theta \), where \( \theta \) is an angle, typically measured in degrees or radians. Sine is particularly useful in understanding relationships in right triangles and unit circles.
- For a given angle \( \theta \), \( \sin \theta \) represents the ratio of the length of the side opposite \( \theta \) to the hypotenuse in a right triangle.
- On the unit circle, \( \sin \theta \) corresponds to the y-coordinate of the point where the terminal side of the angle intersects the circle.
- The range of the sine function is from -1 to 1, which means \( \sin \theta \) will always fall within this interval.
Quadrants in Trigonometry
Understanding quadrants is essential when working with angles in trigonometry, as they help determine the sign and orientation of trigonometric functions like sine. The coordinate plane is divided into four quadrants:
- First Quadrant: Both x and y coordinates are positive. As a result, sine is positive here.
- Second Quadrant: x is negative, and y is positive. Sine remains positive because y is positive.
- Third Quadrant: Both x and y coordinates are negative, making sine negative since y is negative.
- Fourth Quadrant: x is positive, and y is negative. Sine is negative in this quadrant.
Degree Measure
Degree measure is one of the primary units for expressing angles in trigonometry. Each full rotation around a circle is 360 degrees. Using degree measure, we can express angles within a straightforward and familiar system for calculations and problem-solving.
- An angle of \( 90^{\circ} \) represents a quarter turn, forming a right angle.
- \( 180^{\circ} \) is a half rotation, an important benchmark often used to transition between quadrants.
- To express angles precisely, we often round to the nearest tenth of a degree, as done in the given problem.
Other exercises in this chapter
Problem 21
In \(21-24,\) find, to the nearest tenth, the degree measures of all \(\theta\) in the interval \(0^{\circ} \leq \theta
View solution Problem 22
Find, to the nearest hundredth of a radian, the value of \(\theta\) such that \(\sec \theta=\frac{5}{\sec \theta}\) and \(\frac{\pi}{2}
View solution Problem 23
Find two values of \(A\) such that \((\sin A)(\csc A)=-\sin A\)
View solution Problem 23
In \(21-24,\) find, to the nearest tenth, the degree measures of all \(\theta\) in the interval \(0^{\circ} \leq \theta
View solution