Problem 22
Question
In 2010 , the world's population reached 6.91 billion and was increasing at a rate of \(1.1 \%\) per year. Assume that this growth rate remains constant. (In fact, the growth rate has decreased since \(1987 .)\) (a) Write a formula for the world population (in billions) as a function of the number of years since 2010 (b) Estimate the population of the world in the year 2020 (c) Sketch world population as a function of years since 2010\. Use the graph to estimate the doubling time of the population of the world.
Step-by-Step Solution
Verified Answer
Formula: \( P(t) = 6.91 \cdot (1.011)^t \); 2020 population estimate: 7.71 billion; doubling time: ~64 years.
1Step 1: Understand the Exponential Growth Formula
To model the world population growth, we can use the exponential growth formula: \( P(t) = P_0 \cdot (1 + r)^t \). Here, \( P_0 \) is the initial population (6.91 billion in 2010), \( r \) is the growth rate per year (1.1% or 0.011 as a decimal), and \( t \) is the number of years since 2010.
2Step 2: Write the Formula for World Population
Using the information given, we can write the formula for the world population as a function of years since 2010 as follows: \( P(t) = 6.91 \cdot (1 + 0.011)^t \). This equation will allow us to calculate the estimated population for any year \( t \) years after 2010.
3Step 3: Calculate the Population in 2020
To estimate the population in 2020, we set \( t = 10 \) because 2020 is 10 years after 2010. Substitute \( t = 10 \) into the formula: \( P(10) = 6.91 \cdot (1.011)^{10} \). Calculating this gives: \( P(10) \approx 6.91 \cdot 1.116 \approx 7.71 \) billion.
4Step 4: Sketch the Population Growth
The function \( P(t) = 6.91 \cdot (1.011)^t \) is an exponential curve that increases over time. To sketch this graph, plot several key points: \((0, 6.91)\), \((10, 7.71)\), and a few others. The graph should start at 6.91 billion, and by 2020, reach around 7.71 billion, showing a smooth exponential rise.
5Step 5: Estimate the Doubling Time
Using the Rule of 70, the doubling time can be estimated by dividing 70 by the percentage growth rate. So, the doubling time is \( \frac{70}{1.1} \approx 63.64 \) years. From the graph, confirm that it takes around 64 years for the population to double from 6.91 billion to approximately 13.82 billion.
Key Concepts
Population GrowthExponential FunctionsDoubling Time
Population Growth
Population growth is a fascinating and fundamental concept in understanding how the world changes over time. It refers to the increase in the number of people in a population, which can be both natural and influenced by various factors. In our exercise, we consider a scenario where the global population grows at a constant rate.
In 2010, the world population was 6.91 billion, and it's assumed to grow at an annual rate of 1.1%. Even a slight change in the growth rate can significantly impact future population numbers.
In 2010, the world population was 6.91 billion, and it's assumed to grow at an annual rate of 1.1%. Even a slight change in the growth rate can significantly impact future population numbers.
- A constant growth rate means the percentage increase from year to year remains the same. This makes calculations predictable and manageable.
- Population growth can be affected by birth rates, death rates, and migration. In our simplified model, we only consider the growth rate as a constant factor.
Exponential Functions
Exponential functions are mathematical expressions used to model situations where growth accelerates over time. They are characterized by a constant rate of growth, which in this case, is an increase by 1.1% per year. An exponential growth formula is written as:
\[ P(t) = P_0 \cdot (1 + r)^t \]
Where:
\[ P(t) = 6.91 \cdot (1 + 0.011)^t \]
This formula helps us predict populations in future years. Exponential growth leads to dramatic increases over time, as each year the growth builds on the previous year's population.
\[ P(t) = P_0 \cdot (1 + r)^t \]
Where:
- \(P(t)\) is the population after \(t\) years.
- \(P_0\) is the initial population.
- \(r\) is the growth rate (expressed as a decimal).
- \(t\) is the time in years.
\[ P(t) = 6.91 \cdot (1 + 0.011)^t \]
This formula helps us predict populations in future years. Exponential growth leads to dramatic increases over time, as each year the growth builds on the previous year's population.
Doubling Time
Doubling time is an intuitive way to understand how quickly a population, or anything that follows exponential growth, grows to twice its size. It's calculated using a handy rule: the Rule of 70.
The Rule of 70 states:
\[ \text{Doubling Time} = \frac{70}{\text{growth rate as a percentage}} \]
For our population growth exercise, the growth rate is 1.1%. Thus, the doubling time is:
The Rule of 70 states:
\[ \text{Doubling Time} = \frac{70}{\text{growth rate as a percentage}} \]
For our population growth exercise, the growth rate is 1.1%. Thus, the doubling time is:
- \(\frac{70}{1.1} \approx 63.64\) years.
Other exercises in this chapter
Problem 21
find \(k\) so that the function is continuous on any interval. $$g(t)=\left\\{\begin{array}{ll} t+k & t \leq 5 \\ k t & 5
View solution Problem 21
(a) Write an equation for a graph obtained by vertically stretching the graph of \(y=x^{2}\) by a factor of \(2,\) followed by a vertical upward shift of 1 unit
View solution Problem 22
find \(k\) so that the function is continuous on any interval. $$h(x)=\left\\{\begin{array}{ll} k \cos x & 0 \leq x \leq \pi \\ 12-x & \pi \leq x \end{array}\ri
View solution Problem 22
Solve for \(t .\) Assume \(a\) and \(b\) are positive constants and \(k\) is nonzero. $$P_{0} a^{t}=Q_{0} b^{t}$$
View solution