Problem 22
Question
In \(11-22,\) find the value of each expression when \(x \neq 0\) $$ \frac{3 x^{0}}{(4 x)^{0}} $$
Step-by-Step Solution
Verified Answer
The value of the expression is 3.
1Step 1: Understand Exponents
First, it's important to understand that any number raised to the power of 0 is equal to 1. This means that both \(x^0\) and \((4x)^0\) are equal to 1.
2Step 2: Simplify the Numerator
Look at the numerator \(3x^0\). Since \(x^0 = 1\), this simplifies to \(3 \times 1 = 3\).
3Step 3: Simplify the Denominator
Now consider the denominator \((4x)^0\). Since anything raised to the power of 0 is 1, \((4x)^0 = 1\).
4Step 4: Calculate the Fraction
Now substitute the simplified numerator and denominator into the expression: \(\frac{3}{1}\). This simplifies to just 3.
Key Concepts
Zero Exponent RuleNumerator and Denominator SimplificationExpression Evaluation
Zero Exponent Rule
When dealing with exponents, one of the most crucial rules to grasp is the zero exponent rule. This rule states that any non-zero base raised to the power of zero equals 1. In mathematical terms, this can be expressed as:
\( a^0 = 1 \)
where \( a \) is any non-zero number. This might seem a bit counterintuitive at first, but it is a foundational part of exponent rules.To see this in action, consider our expression: \( x^0 \) and \( (4x)^0 \). Regardless of what value \( x \) holds (as long as it isn't zero), both \( x^0 \) and \( (4x)^0 \) are 1. The zero exponent simplifies expressions by reducing complex terms to a single, manageable form. This understanding becomes particularly helpful when simplifying fractions or expressions with multiple levels of complexity.
\( a^0 = 1 \)
where \( a \) is any non-zero number. This might seem a bit counterintuitive at first, but it is a foundational part of exponent rules.To see this in action, consider our expression: \( x^0 \) and \( (4x)^0 \). Regardless of what value \( x \) holds (as long as it isn't zero), both \( x^0 \) and \( (4x)^0 \) are 1. The zero exponent simplifies expressions by reducing complex terms to a single, manageable form. This understanding becomes particularly helpful when simplifying fractions or expressions with multiple levels of complexity.
Numerator and Denominator Simplification
Simplifying expressions with fractions involves breaking them down into simpler parts. Let's start with the numerator. In the expression \( \frac{3x^0}{(4x)^0} \), notice the term \( 3x^0 \) in the numerator. Using the zero exponent rule, we know that \( x^0 \) simplifies to 1. Thus, the numerator becomes:
- \(3x^0 = 3 \times 1 = 3\)
- \((4x)^0 = 1\)
Expression Evaluation
With both the numerator and denominator simplified, it's time to perform the final expression evaluation. Our task is now to evaluate \( \frac{3}{1} \). This is straightforward, as dividing by 1 doesn't change the value of the numerator. So, the expression evaluates directly to:
- \(3 / 1 = 3\)
Other exercises in this chapter
Problem 22
A piece of property was valued at \(\$ 50,000\) at the end of \(1990 .\) Property values in the city where this land is located increase by 10\(\%\) each year.
View solution Problem 22
In \(3-37,\) express each power as a rational number in simplest form. $$ 125^{-\frac{3}{3}} $$
View solution Problem 22
Solve each equation and check. \(3^{x+2}=9^{x}\)
View solution Problem 22
In \(18-23,\) solve for the variable in each equation. Express the solution to the nearest hundredth. $$ 5+b^{5}=56 $$
View solution