Problem 22
Question
If you used only a keyboard to enter data, how many years would it take to fill up the hard drive in your computer that can store 82 gigabytes \(\left(82 \times 10^{9}\right.\) bytes \()\) of data? Assume "normal" eight-hour working days, and that one byte is required to store one keyboard character, and that you can type 180 characters per minute.
Step-by-Step Solution
Verified Answer
It would take approximately 2,599 years.
1Step 1: Calculate Characters per Minute
Since each character requires one byte of storage, first determine the number of characters you can type per minute. You are given that this is 180 characters per minute.
2Step 2: Calculate Characters per Hour
Multiply the number of characters per minute (180) by the number of minutes per hour (60) to find out how many characters you type per hour: \[ 180 \times 60 = 10,800 \text{ characters per hour} \]
3Step 3: Calculate Characters per Day
Multiply the number of characters per hour (10,800) by the hours per workday (8) to find out how many characters you type in a day: \[ 10,800 \times 8 = 86,400 \text{ characters per day} \]
4Step 4: Calculate Days to Fill Hard Drive
Determine how many days it would take to fill the hard drive by dividing the total storage capacity by the number of characters typed per day: \[ \frac{82 \times 10^9}{86,400} \approx 949,074 \text{ days} \]
5Step 5: Convert Days to Years
Convert the number of days into years by dividing by 365:\[ \frac{949,074}{365} \approx 2,599 \, \text{years} \]
Key Concepts
Characters per MinuteHard Drive CapacityDays to Years Conversion
Characters per Minute
When considering data entry via typing, it's crucial to first understand the rate at which characters are input. Each character typed requires one byte of storage on your computer. If you type at a rate of 180 characters per minute, this translates directly to 180 bytes per minute of storage used.
- This typing speed remains standard for many scenarios, offering a clear metric for calculating larger data storage needs over time.
- Imagine your digital work pace and how these numbers scale up over longer periods, which helps in understanding the storage fill rate.
Hard Drive Capacity
Understanding hard drive capacity involves both the total storage size and how it relates to data input volumes. Your hard drive can store 82 gigabytes, which equates to 82 x 10^9 bytes. Here's how it breaks down:
- Every character typed consumes one byte, so knowing your typing speed allows you to estimate how quickly you'll use this storage.
- Expanding this understanding helps with planning file management and ensuring you have sufficient storage for your needs.
- As technology advances, hard drives become larger and more efficient, impacting how we manage and optimize storage space.
Days to Years Conversion
To appreciate how long it might take to fill your hard drive based on constant typing, you'll need to convert your daily input rate into a larger time frame. This involves several steps:
- First, calculate the number of characters you can type in a day, which you found to be 86,400 characters for an 8-hour workday.
- Using this daily rate, determine how many days it takes to reach the full 82 gigabytes of storage. It was calculated to be approximately 949,074 days.
- Finally, converting days to years requires dividing by 365, giving you an estimated 2,599 years to fill the drive.
Other exercises in this chapter
Problem 21
A light-year is the distance light travels in one year (at speed \(\left.=2.998 \times 10^{8} \mathrm{~m} / \mathrm{s}\right)\). (a) How many meters are there i
View solution Problem 21
$$ \begin{array}{l}{\text { (II) A light-year is the distance light travels in one year }} \\ {\text { (at speed }=2.998 \times 10^{8} \mathrm{m} / \mathrm{s} )
View solution Problem 22
$$\begin{array}{l}{\text { (II) If you used only a keyboard to enter data, how many }} \\ {\text { years would it take to fill up the hard drive in your }} \\\
View solution Problem 24
Estimate the order of magnitude (power of ten) of: \((a) 2800\), (b) \(86.30 \times 10^{2}\) (c) \(0.0076,\) and \((d) 15.0 \times 10^{8}\)
View solution