Problem 22
Question
If \(f(x)\) is an odd periodic function with period 2 , then \(f(4)\) equals (A) \(-4\) (B) 4 (C) 2 (D) 0
Step-by-Step Solution
Verified Answer
The answer is (D) 0.
1Step 1: Understand Odd Functions
An odd function has the property that for any value of \(x\), \(f(-x) = -f(x)\). This means if you take the function's value at any point and flip the sign and input, you should get the negative of the original function's value.
2Step 2: Understand Periodic Functions
A periodic function with period 2 means that \(f(x) = f(x+2)\) for every \(x\). This implies every 2 units along the x-axis, the function repeats itself.
3Step 3: Determine the Function Value
Since \(f(x)\) is a periodic function with period 2, \(f(4) = f(4-2) = f(2)\). Using the property of odd functions, \(f(2) = -f(-2)\). But, due to periodicity, \(f(-2) = f(0)\), so \(f(2) = -f(0)\).
4Step 4: Use Odd Function Property
Since \(f(0)\) for an odd function must be 0 (because \(f(-0) = -f(0)\) giving \(f(0) = -f(0)\), hence \(f(0) = 0\)), \(f(2) = -0 = 0\). Thus, \(f(4) = f(2) = 0\).
Key Concepts
Properties of Odd FunctionsProperties of Periodic FunctionsFunction Evaluation
Properties of Odd Functions
Odd functions have a distinct symmetry about the origin in the coordinate plane. This means if you were to fold the graph along the line \(y=x\), the left side would be a mirror image of the right side, but flipped upside down. You can express this mathematical property with the equation \(f(-x) = -f(x)\).
- This takes any point \((x, f(x))\) and ensures the point \((-x, -f(x))\) also exists.
- It means the function is symmetrical with respect to the origin, often referred to as "origin symmetry."
Properties of Periodic Functions
Periodic functions are all about repetition at regular intervals along their domain. This characteristic is particularly useful in the contexts where repeating patterns are important, like in signal processing, sound waves, and seasonal trends. A periodic function can be identified by the equation \(f(x) = f(x+T)\), where \(T\) is the period.
- This means after every \(T\) distance along the x-axis, the function values repeat.
- The smallest possible positive \(T\) that satisfies this is called the fundamental period.
Function Evaluation
Evaluating functions, especially ones with both symmetry and periodicity, can be simplified through their unique properties. With odd periodic functions, these evaluations often become straightforward using their characteristic equations. When solving for a value like \(f(4)\), leverage both properties:
- Use periodicity to revert back to the starting section by reducing using its period: since 4 is two periods into the repetition cycle, you calculate \(f(4)\) as \(f(4-2)=f(2)\).
- Apply the odd function property: if \(f(2) = -f(-2)\) and through periodicity \(f(-2) = f(0)\), then \(f(2)\) must be \(-f(0)\).
Other exercises in this chapter
Problem 20
The domain of the function \(y=\sqrt{\log \frac{1}{|\sin x|}}\) (A) \(R \backslash\\{n \pi: n \in Z\\}\) (B) \(R^{\prime}(-\pi, \pi)\) (C) \(R \backslash\\{2 n
View solution Problem 21
If \(x\) is real, then the expression \(\frac{x^{2}+34 x-71}{x^{2}+2 x-7}\) (A) cannot lie between 5 and 9 (B) always lies between 5 and 9 (C) is not real (D) N
View solution Problem 23
The function \(f(x)=\cot ^{-1}[\sqrt{(x+3) x}]+\cos ^{-1}\left(\sqrt{x^{2}+3 x+1}\right)\) is defined on the set \(S\), where \(S\) is equal to (A) \(\\{-3,0\\}
View solution Problem 24
If \(f(x)=a^{\cos x}\) and \(g(x)=(\sin x)^{a}, a \in \mathrm{N}\), then (A) \(f(x)>g(x), \forall x\) (B) \(f(x)
View solution