Problem 22
Question
Identify the type of function represented by each equation. Then graph the equation. \(y=|2 x|\)
Step-by-Step Solution
Verified Answer
The function \(y = |2x|\) is an absolute value function, and its graph is a V-shaped parabola opening upwards, vertically stretched by a factor of 2.
1Step 1: Identify Function Type
The equation given is \(y = |2x|\), which represents an absolute value function. Absolute value functions are typically characterized by their V-shaped graphs and transformations depending on the expression inside the absolute value.
2Step 2: Rewrite for Simplicity
To better understand the function, rewrite \(y = |2x|\) as \(y = |2| \cdot |x| = 2|x|\). This shows that the function will have a vertical stretch by a factor of 2.
3Step 3: Determine Key Points
Find key points of the function by evaluating the expression at various \(x\) values. For example: when \(x = 0\), \(y = 0\); when \(x = 1\), \(y = 2\); and when \(x = -1\), \(y = 2\). More generally, the graph will pass through the points \((0, 0)\), \((1, 2)\), and \((-1, 2)\).
4Step 4: Sketch the Graph
Plot the key points on a coordinate plane. Start at (0,0), plot (1,2) and (-1,2). Draw lines connecting these points, ensuring the graph forms a V-shape, characteristic of absolute value functions, and is symmetric about the y-axis.
Key Concepts
Graphing Absolute Value FunctionsVertical StretchKey Points of Function
Graphing Absolute Value Functions
Graphing absolute value functions can be a fun and straightforward process once you understand the unique features of these functions. Absolute value functions generally form a V-shaped graph. This is because the absolute value of a number is always non-negative, meaning it reflects all negative inputs above the x-axis, giving the graph its distinct shape.
The most basic form of an absolute value function is \(y = |x|\), which has a vertex, the point where the graph changes direction, at the origin (0,0).
To graph an absolute value function like \(y = |2x|\), you'll follow these steps:
The most basic form of an absolute value function is \(y = |x|\), which has a vertex, the point where the graph changes direction, at the origin (0,0).
To graph an absolute value function like \(y = |2x|\), you'll follow these steps:
- Determine the vertex of the graph, usually the point where \(x = 0\), resulting in \(y = 0\).
- Identify other key points by substituting different values of \(x\) into the equation and solving for \(y\).
- Plot these points on a graph and draw the V-shape, making sure it's symmetrical about the y-axis.
Vertical Stretch
A vertical stretch changes the steepness of the V-shape in an absolute value graph. If you compare the basic absolute value function \(y = |x|\) to \(y = 2|x|\), you will notice that \(y = 2|x|\) stretches the graph vertically.
In the equation \(y = 2|x|\), the coefficient 2 indicates a vertical stretch by a factor of 2. This means that for any given \(x\), the value of \(y\) will be twice as large as it would be in the basic \(y = |x|\) function. This makes the V-shape of the graph steeper.
In the equation \(y = 2|x|\), the coefficient 2 indicates a vertical stretch by a factor of 2. This means that for any given \(x\), the value of \(y\) will be twice as large as it would be in the basic \(y = |x|\) function. This makes the V-shape of the graph steeper.
- When the coefficient is greater than 1, the graph stretches vertically.
- If the coefficient were between 0 and 1, it would result in a vertical compression, making the graph wider and less steep.
Key Points of Function
Identifying key points is crucial when graphing an absolute value function. These points provide a framework for sketching the graph accurately. For \(y = |2x|\), key points can be identified by substituting various values of \(x\) into the equation and solving for \(y\).
For instance:
For instance:
- When \(x = 0\), \(y = |2 imes 0| = 0\).
- When \(x = 1\), \(y = |2 imes 1| = 2\).
- Similarly, at \(x = -1\), \(y = |2 imes -1| = 2\).
Other exercises in this chapter
Problem 21
Simplify each expression. \(\frac{9-t^{2}}{t^{2}+t-12}\)
View solution Problem 22
NUMBER THEORY The ratio of 16 more than a number to 12 less than that number is 1 to 3 . What is the number?
View solution Problem 22
State whether each equation represents a direct, joint, or inverse variation. Then name the constant of variation. \(v w=-18\)
View solution Problem 22
Simplify each expression. $$ \frac{6}{a b}+\frac{8}{a} $$
View solution