Problem 22
Question
For the following exercises, use the Binomial Theorem to expand each binomial. $$ (\sqrt{x}-\sqrt{y})^{5} $$
Step-by-Step Solution
Verified Answer
\[x^{5/2} - 5 x^2 y^{1/2} + 10 x^{3/2} y - 10 x y^{3/2} + 5 x^{1/2} y^2 - y^{5/2}\]
1Step 1: Identify the Formula
The binomial theorem states that \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\). Identify \(a\), \(b\), and \(n\) for the given binomial expression \((\sqrt{x} - \sqrt{y})^5\) as \(a = \sqrt{x}\), \(b = -\sqrt{y}\), and \(n = 5\).
2Step 2: Calculate the Binomial Coefficients
For each term in the expansion, we need the binomial coefficient \(\binom{n}{k}\). We calculate these coefficients for \(n = 5\) and \(k = 0, 1, 2, 3, 4, 5\). These are \(\binom{5}{0} = 1\), \(\binom{5}{1} = 5\), \(\binom{5}{2} = 10\), \(\binom{5}{3} = 10\), \(\binom{5}{4} = 5\), and \(\binom{5}{5} = 1\).
3Step 3: Expand Using the Binomial Theorem
Write out each term using the binomial coefficients and the formula: \(\binom{5}{k} (\sqrt{x})^{5-k} (-\sqrt{y})^k\) for \(k = 0, 1, 2, 3, 4, 5\). This gives the terms: \(1 \cdot (\sqrt{x})^5 \cdot (-\sqrt{y})^0\), \(5 \cdot (\sqrt{x})^4 \cdot (-\sqrt{y})^1\), \(10 \cdot (\sqrt{x})^3 \cdot (-\sqrt{y})^2\), \(10 \cdot (\sqrt{x})^2 \cdot (-\sqrt{y})^3\), \(5 \cdot (\sqrt{x})^1 \cdot (-\sqrt{y})^4\), \(1 \cdot (\sqrt{x})^0 \cdot (-\sqrt{y})^5\).
4Step 4: Compute Each Term
Simplify each term:1. \((\sqrt{x})^5 = x^{5/2}\)2. \(-5(\sqrt{x})^4(\sqrt{y}) = -5x^2y^{1/2}\)3. \(10(\sqrt{x})^3(\sqrt{y})^2 = 10x^{3/2}y\)4. \(-10(\sqrt{x})^2(\sqrt{y})^3 = -10x y^{3/2}\)5. \(5\sqrt{x}(\sqrt{y})^4 = 5x^{1/2}y^2\)6. \(-(\sqrt{y})^5 = -y^{5/2}\).
5Step 5: Combine All Terms
Combine all the computed terms to get the expanded form: \[x^{5/2} - 5 x^2 y^{1/2} + 10 x^{3/2} y - 10 x y^{3/2} + 5 x^{1/2} y^2 - y^{5/2}.\]
Key Concepts
Binomial ExpansionBinomial CoefficientsAlgebraic Expressions
Binomial Expansion
The concept of binomial expansion is central to understanding expressions raised to powers, especially when dealing with expressions like \[(a + b)^n\]where binomial coefficients and powers of terms come into play. To expand a binomial expression like \[(\sqrt{x} - \sqrt{y})^5,\]we use the Binomial Theorem, which provides a systematic way of expanding expressions based on the pattern of coefficients and powers. The principle is grounded in extending the simple operations of algebra to a more complex power of a binomial.To apply this:
- Recognize the terms of the binomial, which here are \(\sqrt{x}\) and \(-\sqrt{y}.\)
- The power to which the binomial is raised, known as \(n,\) is 5 in this case.
Binomial Coefficients
Key to correctly applying the binomial theorem are the so-called binomial coefficients, represented by \[\binom{n}{k},\]which articulate how terms in the expansion are weighted. They are calculated using the formula:\[\binom{n}{k} = \frac{n!}{k!(n-k)!},\]where \(!\) represents factorial, and \(n\) and \(k\) are integers with \(0 \leq k \leq n.\)In the context of our problem expanding \((\sqrt{x} - \sqrt{y})^5,\)we calculate these coefficients for \(n = 5\) and specific \(k\) values ranging from 0 to 5:
- \(\binom{5}{0} = 1\)
- \(\binom{5}{1} = 5\)
- \(\binom{5}{2} = 10\)
- \(\binom{5}{3} = 10\)
- \(\binom{5}{4} = 5\)
- \(\binom{5}{5} = 1\)
Algebraic Expressions
Dealing with algebraic expressions involves manipulating symbols and numbers to express quantities, solve equations, or represent ideas. An expression like \((\sqrt{x} - \sqrt{y})^5\)demands recognizing the components and how they interact under operations like multiplication and exponentiation. As part of binomial expansion, each term within \((a + b)^n\)is an algebraic expression comprising factors of \(a\) and \(b\) raised to particular powers determined by their position in the series.For example, terms like \[x^{5/2}\] and \[-5x^2y^{1/2}\]are results of the calculated aspects of the expression, where the focus is on:
- Correctly applying radicals and powers from \(a\) and \(b.\)
- Combining like terms efficiently to streamline the expression.
- Ensuring negative bases are treated properly when they interact with exponents.
Other exercises in this chapter
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